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2008-P12228 (00020) - new septic
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3940 Watertown Road - 32-118-23-32-0001
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2008-P12228 (00020) - new septic
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Last modified
8/22/2023 4:40:30 PM
Creation date
11/4/2019 1:48:52 PM
Metadata
Fields
Template:
x Address Old
House Number
3940
Street Name
Watertown
Street Type
Road
Address
3940 Watertown Road
Document Type
Septic
PIN
3211823320001
Supplemental fields
ProcessedPID
Updated
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PRESSURE DISTRIBUTION SYSTEM <br /> Geotextile fabric <br /> 1• Select number of perforated laterals a <br /> 'r-,4fC' c`�le*J: ((..y�• PF.° rb"p, 'e•• <br /> uarterinch erfo 3 '' <br /> ,,..f,,_,• raHonss aced `"''�'� • `� TRS <br /> 2. <br /> _. Select perforationP_—feet. <br /> 3 ;G'�:P�"T••;,C.�'�i�jiF,4?.:,,Ar.,1::p�l.c;„��',.'.f'Sh:b,:.:D4r.0ff.'c�,l'�-t-l'1•71-jr9°:'�;,:.:.,�dtw•o,:'�?tai i`�;a�(.1'?..S'.c?:�.::%•ya(..%:j�:;;�.{•:7 <br /> c.oi:�?:.;•;r'..o:i':1.;'.•t1,',. <br /> S?r,:17�:trrgl!?%L•y^,a�•"11L J' 'Il,C;�'J.l.ry'.•y,•<��••F;ii�7 <br /> Since perforations should not be placed closer than 1 ft. to Perf Spacing 32"5' 3rr', il,.,7• _r `'; <br /> c.:..a <br /> Perf Sizing 7/32"-1 J4" <br /> the edge of the rock layer (see diagram), subtract 2 ft. from <br /> the rock layer length. <br /> ► JL4-�� r Thead , <br /> ischarges In gpm <br /> oc ayer eng -2�ft. _(p0 _feet. (�9 t )04.sSerforation diameter <br /> IFIL"''VI tf Inches <br /> 4• Determine the number of spaces between perforat oris 4'� 3/16 7/32 1/4Divide the length above by perforation spacing and round0.42 0.56 0.74down to nearest whole number. 0.59 0.80 1.04Length perf. spacing= (� ft_ _ 0.94 1.26 1.65 <br /> ft. __ <br /> (3) (2) 20 spaces o 111.0 foot for single-family homes. <br /> 5• Number Of b Use 2.0 feet for anything else. <br /> perforations is equal to one plus.the number of ' Potential for Plugging <br /> perforation spaces _ <br /> aJ spaces + I = 1 perforations/lateral Maximum number of quarter inch perforations per <br /> lateral to guamantee<10%discharge variation <br /> er <br /> 6- Multiply perforations per lateral by number of laterals to PS f a�gn , <br /> get total number of.perforations. . {feet) 14 P2 2 <br /> 3 _ 2-5 14 18 28 <br /> lateralsX -2, perforations. 3.0- 13 1 <br /> pePr�s aFer 26 <br /> Calculate the square footage per perforation (6-10 sgft/peri.) 3.3 12 16 25 <br /> System area: i0 .x L-� = 0_ 11 15 23 <br /> 5.0 10 <br /> area 14 22 <br /> ea e>�a ons —— / 6 _S of t/p erf <br /> 7_ Determine required flow rate b MN'F°`° LOCATED ^T ENo Up PfiESSURE UISTT{IBUiION SYSTEM <br /> number of perforations by.flow per multiplying,oration <br /> Li <br /> (0 39 <br /> � x gpm Pei —_12 gpm <br /> 8. If laterals are connected to header pipe as shown on upper „P•rt """� �"f'RJw 1 <br /> example, to select minimum required lateral diameter; enter <br /> table with pei:foration spacing and number of perforations <br /> per lateral. Select minimum diameter for LAro�RP PERS TE-PIPE LATERALS mn <br /> PRE]]ugE'RI]TNieUt10N Y.Mau NO <br /> perforated lateral = l�-inches. sc� > t� `I �1���•�T,E <br /> 9. If perforated lateral system is attached to manifold pipe near. ylE' R ; <br /> the center,lower diagram, r PIr " <br /> �' ,perforated lateral length and <br /> number of perforations per lateral will-be approximately.one . m -- <br /> half of that in step 8. Using these values,select minimum <br /> diameter for perforated lateral <br /> .inches. <br />
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