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PRESSURE DISTRIBUTION SYSTEM END PERFORATION OF A PERFORATED LATERAL <br /> Gross Cover <br /> 1. Select number of perforated laterals 3 ` Topsails <br /> 2. Select perforation spacing= 3 feet. `` .., sand Layer '4tdtLil'�a°`6.1 111.or Fa°r'` `"'°"' <br /> :>`,,: ser of tta or prow covered <br /> i:Fwl h rosin paper) <br /> Erforra <br /> tion Drilled Horizontally <br /> Into C p Near Top <br /> 3. Since perforations should not be placed closer than 1 ft. to ,,�PI I Least 12'to Edge <br /> the edge of the rock layer (see diagram).,subtract 2 ft. from ,. . '' R �;.1 of Rock Lays <br /> Paforttlltxts Located at <br /> the rock layer length. <br /> Clean�,� Layer Bottom of Lateral <br /> _2 ft. _ O feet. ONglnat sero ProPe►ly saarlfied <br /> Rock layer length Before Placing Sand Layer <br /> Its <br /> 4. Determine the number of spaces between perforations. "`"da+ a je <br /> Divide the length above by perforation spacing and round ;2.�M ;.�.� <br /> down to nearest whole number. `feet) <br /> 1.0a 0.56 0.74 <br /> Length perf. spacing = ft. + 3 ft. = it, spaces <br /> 2.Ob 0.80 1.04 <br /> (3) (2) a.Use for single family homes <br /> b.Use for all other applications <br /> 5. Number of perforations is equal to one plus the number of <br /> perforation spaces . <br /> Maximumnumber of quarter inch perforations pel <br /> spaces + 1 = I perforations/lateral lateral to gnarnantee<10%discharge variation <br /> Perforation <br /> 6. Multiply perforations per lateral by number of laterals to Spacing iia P2 2 <br /> get total number of perforations. 2.5 14 18 2$ <br /> 3 x I — -5 perforations. 3.0 13 17 26 <br /> ''�'`' - p 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying 4.0 11 15 23 <br /> number of perforations by flow per perforation 5.0 10 14 22 <br /> peds <br /> x _4� gpm. MpYPoW LOCATED AT END OF I'MMU nE OMMOUTION SYSTEM <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example,to select minimum required lateral diameter;enter - " <br /> table with perforation spacing and rmndw of perforations „ ,.�° �'— <br /> per lateral. Select minimum diameter for ��'°”" <br /> perforated lateral=. I A inches. <br /> uva+r40! eaMretl nFE urcnus N111 <br /> W/KaasTeMlrlaN w MOUND <br /> KleeMwA RtlIK.Ile <br /> 9. If perforated lateral system is attached to manifold pipe near �' >, ,✓ <br /> the center,lower diagram,perforated lateral length and ...�... r <br /> number of perforations per lateral will be approximately one <br /> half of that in step 8. Using these values,select minimum <br /> diameter for perforated lateral = 1 !i inches. ,„ °`"`� ,,. <br />