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PUMP SELECTION PROCEDURE <br /> 1. Determine pump capacity: <br /> A. Gravity distribution <br /> 1. Nlulirnurri required discharge is 10 oTpm <br /> ?. tilaximum suggested discharge is 45 gpm. For other <br /> estaL'lishments at least 10"., greater than the water supply rate, <br /> but no faster than the rate at NN'hlch effluent will flO` out of the <br /> distribution device. <br /> .. <br /> B. Pressure distribution <br /> Seg' pi-c ssare d ist ribllfiUll work Slli'et LL '' <br /> From A or B Selected pump capacity: -- gPm <br /> 2. Determine pump head requirements: ,, soil treatment system <br /> A. Elevati n difference between pump and point of discharge? &point of aiscnorga <br /> feet pipe <br /> oral pipe <br /> B. Special head requirement? (see Figure at riglit - Special Heati Requirement') iengtr) <br /> 2A.elevation f <br /> __feet <br /> inlet - ditierence <br /> pipe � .i i <br /> C. Calculate ............Friction loss ;t <br /> I� <br /> diameter <br /> 1. Select pipe ia......---- <br /> 2. Enter Figure E-9 with 6-pn1 (1A or B) and pipe diameter (0). <br /> EPressure <br /> al Head Requirements <br /> head friction loss in feet per 100 feet from Figure E-9 Distribution 0 rt <br /> Friction Loss = 0� 0 ft/100ft of pipe Distribution tt <br /> ;. Determine total pipe length from pump discharge to soil treatment <br /> C\ <br /> discharge point. Estimate by adding 25 percent to pipe length for <br /> fitting loss. Total pipe len-th tunes 1.25 = equivalent pipe length E-q: Friction Loss in Plastic Pipe <br /> Per 100 feet <br /> Lfeet x 1.25 = -z,�feet <br /> nominal <br /> 4. Calculate total friction loss by multiplying friction loss (0) pipe diameter <br /> in ft/100 ft by the equivalent pipe length (C3��di vide by 100. flow rare 1.5" 21- <br /> & <br /> " 3" <br /> pm <br /> 2=010 ft/100ft x Z,G =100 = 20 L.47 0.73 0.11 <br /> D. Total head required is the sum.of elevation difference (�), special 25 3.73 l.11 0.16 <br /> head requirements (B�, and total friction loss (C ) Z9 30 5.23 1.55 0.23 <br /> -ft T �_ft+ `.� S,ft = 28`S '" 35 o.vc Z2o-1) <br /> G.30Total head: 2qo' feet 40 8.91 0.39 <br /> 45 11.07 3.28 0.43 <br /> j. Pump selection 50 13.46 3.99 0.58 <br /> 55 4.7o 0.70 <br /> plli,lp I11L1S1 be selected todeliverat least '�V tT 00 5.00 0.82 <br /> 24.d 65 0.48 0.95 <br /> (j.-k or B) with at least - feet of total head (2D) <br /> 7(17 ,14 1.09 <br /> 1 l;er �' �ni,� that I have co',,fileted this work in accurdance with applicable ordinance>, rules and laws. <br /> N 3Z (license s) /017-q/0 (date <br /> _(Signature) / <br />