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Geotexrile fabric PRESSURE DISTRIBUTION SYSTEM 1. Select number of perforated laterals _._ >uarto:inch perforations spaced Q 3' 12 2. Select perforation spacing = ft I 9"of rock i Perf Sizing 3/16" - 1/4" 3. Since perforations -,hould nt)t be placed closer than lout tc, Perf Spacing 15-5' the edge of the rock layer (see diagram), subtract 2 tt•t,t from the rock layer lenbti E-4 Maximum allowable number of 1/4-inch perforations per iateral to guarantee d 0%discharge variation Rock Ix—length ft = s'3 ft perforation spacing j 4. Determine the number of spaces between perfurati,;,:�. j Divide the length ( by perforation spacing (2) and ur.� (faet 1 inch 1.25 inch 1,5 inch 2,0 inch down to nearest wht le number. 5 8 14 18 28 Perforation spacing = .53 ft -,3 ft= / spaces 0 8 13 11 26 • 5. Number of perforations is equal to one plus the nun;'t)tr of 3 7 12 16 2 perforation spaces(4). Check rigure E-4 to assure the rli,r�:bcr ul 0 1 11 15 23 perforations per later,. juaranrcc <10`i,, discharge �t, ::, :i. 6 10 14 22 space, + 1 = perforations/later.;l E-6: Perforation Discharge in gpm 6. A. Total number of perforations = perforation, per 111 ceral (5) perforation diameter times number of laterals (1) head inches (fe1/8 3/16 7/32 1/4 perfs/11.t x _--_lat= J peri' 1.0a 0.18 0.42 0.56 0.74 B. Calculate the square rootage per perforation. Should be 6-10 sgrt, perf. Does not apply to at-grades. 2.0b 0.26 '0.59 0.80 1.04 Rock bed area = rock width (ft) x rock length (ft) 5.0 0.41 0.94 1 .26 1.65 eft xft = 5S� sgft Use 1.0 foot for single-fomuv nomas Square foot per perforation = Rock bed area - num,_,r or perf, (d: b Use 2.0 feet for onvtning else sgfr =_ perfs =_Z6 sgft. pert 7. Determine required tow rate by multiplying the tom., iiumber of , perforations (6A) by ,low per perforation (see fi,,urr D"--110(n perfs xttf, gpm/perfs ,Cap 8. If laterals are connected to header pipe as shown un �.pper example, to select minimum required lateral diamctc':; enter olip eiron figure E-4 with perforation spacing (2) and number ;-,errorations hyureE l:ManiloldlocatedatEndolSystem per lateral (5) Select minimum diameter for —_ perforated lateral = _-- in,Hes. fig.aE•2:Manifold locoied in re Center of the System 9. If perforated lateral system is attached to manifc iii pi: near the center, lower diagram, perforated lateral len,-th („ snd rtOYI�q GL< number of perforations per lateral (5) will be approxirr,.itely one half of that in step 8. Using these val us, select min::r..::n diameter for perforated lateral = 1 �lZ, inches. air rtify that I have coni eted this work in accorda,.ct- ut-iinanc1es, rules and laws. _(signature) n r.) 1 ( G y (date)