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1997-009348 - new septic system
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125 Truffula Trail - 33-118-23-44-0041
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1997-009348 - new septic system
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Last modified
8/22/2023 4:53:17 PM
Creation date
7/1/2019 10:24:02 AM
Metadata
Fields
Template:
x Address Old
House Number
125
Street Name
Truffula
Street Type
Trail
Address
125 Truffula Trail
Document Type
Septic
PIN
3311823440041
Supplemental fields
ProcessedPID
Updated
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ENO PERFORATION OF A PERFORATED LATERA <br /> PRESSLIRE DISTRIBU'T TON SYSTEM <br /> WOaa r"0► <br /> <.T <br /> 1. Select number of perforated laterals TapwM , <br /> �' LOYN of liaaraeraa t"ae/la les tp/ <br /> 'Loanllr Sano LayerInco lures-a na,Wwar.".Wed <br /> 2 Select perforation spacing = feet. `earn°°"'' <br /> �r, P0rlm0rl0n On11N /larwotwly <br /> on/o Gap Now TN <br /> 1/:Plus - .,� Y Lwal 12'to 94" <br /> 3. Since perforations should not be placed closer than I ft. to t n—fl a«r u Naas Larw <br /> the edge of the rock layer(see diagram),subtract 2 ft from <br /> ;al"tati a«•1 <br /> CIO"sar>a Law <br /> rock layer length. `. <br /> W. <br /> O1,19MI l 3011 Preporly Uarilka <br /> --2 ft. _ —3 feet. 84taa Placing$ono Layer <br /> Ruck layer lalglh TABLE OF PERFORATION DISCHARCFS IN CPM <br /> 4. Determine the number of spaces between perforations. Head Perioration diaruser(inches) <br /> Divide the length above by perforation spacing and round 7/' 1/a <br /> down to nearest whole number. 0s6 <br /> 1.5 0.69 0.90 <br /> Len herf. spacing ft. -3 ft. _ 7 spaces <br /> P P g 2.5 o� 1.y <br /> (3) (2) 3.0 0.98 1:B <br /> S. Number of perforations is equal to one plus tht. number of s o 1.26 1.63 <br /> perforation spaces . <br /> aL'.ia 1.0 foot of head for tssiderllsal syatsals. <br /> bUse 2.0 feet of head for ocher etabLUhnumcs <br /> j.L spaces + 1 = perforations/lateral <br /> Ma—err�avert 1 r Pa�rO�pr bwl r <br /> ";""°` <br /> 6. Multiply perforations per lateral by number of laterals to yara.ur.p• �""� <br /> rte, 1.�inch 1.5 inch ..A inc:I <br /> get total number of perforations. 2s 14 28 <br /> 330 13 26 <br /> 3 $ '3.3 12 16 2s <br /> = 5=perforations. 4.0 11 1i 23 <br /> la/eral s x /tataral 2 <br /> 7. Determine required flow rate by multiplying <br /> number of perforations by flow per perforation <br /> 5'4 _ c!p gp m� rwrow wuno �r a ►rasalwc aar.wrrwr srsnr <br /> � x i �Prf <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example, to select minimum required lateral diameter; enter �,✓ .�,.. <br /> table with perforation spacing and number of perforations <br /> per lateral. Select minimum diameter for <br /> perforated lateral = inches. <br /> y�gfFR Mlr�.ln r�q <br /> Cw�rf 1 <br /> Lti a.....�.[row..�. 1 X110/n✓ <br /> 9. If perforated lateral system is attached to manifold pipe near <br /> the center, lower diagram, perforated lateral length and ':.:r.�='"'" <br /> number of perforations per lateral will be approximately one <br /> half of that in step8. Usingthese values, select minimum """' �"� C�o° <br /> , � <br /> diameter for perforated lateral = 'K2 inches. �.. '� � Z <br />
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