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s ' <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) ,,c T 7 B K / Mkj,,J u1oQ _____ <br /> A. FLOW E.1irnA :d Scwagc Flows in Gallons per day <br /> Estimated bon gpd (90) <br /> . UM <br /> Of Type 1 'i�pe II U3 Typo <br /> or measured x 1.5 = gpd. 0c4morns )„ <br /> 2 300 221 180 <br /> B. SEPTIC TANK LIQUID VOLUMES J00 21a <br /> 600 373 236 <br /> 2 - 1 n ci CJ gallons O go o aC,✓pf' 'S0 1.94 <br /> 6 900 3:3 332 <br /> 7 I05U 600 370 „� <br /> a 12W 673 +Wl .slot <br /> C. SOILS (refer to site evaluation) _ <br /> 1. Depth to restricting layer IS-Z4 inches _ Sq-T-C•.-,.%•ww- <br /> N.rawr•t Mt LapW ui."y•'� <br /> 2 Depth of percolation tests inches ....�. �w ,.,..pA-P-,, <br /> 3. Percolation rate 39.3 mpi13 <br /> 4. Land slope % ,s;d. ;p , <br /> D. ROCK LAYER DI1vfF_i 1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> Lon gpd x 0.83 sq. ft./gpd ='mon sq. ft. t <br /> 2• Select width of rock layer (10 feet or less) = 16 ft. <br /> 3. Length of rock layer = area+width = Rock Bed <br /> Seo sq. ft. 1c;._ft. <1 _ft. <br /> r•J•J r•:•:.J•r•J•r•r•r•�•r•r.r• 0' <br /> ti.ti.ti.•..ti.•..ti.ti.ti.ti.ti.ti.ti.ti.ti.♦.� <br /> With 510 f <br /> .J.r•J•r•r•J•J.J•J r•r•r•J•J�r�r~ <br /> `I�%~.�'~!�f~f~.•�f~I�I 1,/�•~•,•,'~ <br /> 1•J.I•J• <br /> E. ROCK VOLUME Length ----� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; S� 0 <br /> S sq. ft. x ft. i�p_cu. ft. 0 <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> st:1 cu. ft. -+-27= AI cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> cu. yd. x 1.4 ton/cu. yd. =30 tons. <br /> F. ADSORPTION WIDTH Absorption Width Siting Table <br /> Percouuon Ram Gallons Rruo of <br /> 1. Percolation rate int top 12 inches,o�lf soil is.,A,p 3 mpi _ iT 1,;1.".R r Sad Temure peday pe, Ab-nx�,,,I.. ., <br /> 111�n J CCA�/ hG nr1 !1G'm�• ��) ��I / Fp� s Lich(MPI) agnate foot to Rock Laycr <br /> wc� w+dm <br /> 2. Select allowable soil loading rate from table; " ( Fau"wan 0.1 coam sand _. <br /> 0.1 to S S.na l.xo 1.ao <br /> gpd/fe 069051• Fina y'� 0.7609 isi <br /> 16 to 30 I.uun 0.60 2.00 <br /> 31104S Loam <br /> aS .Il10� <br /> 3. Calculate adsorption width ratio by dividing rock layer s c,Zs o.as W,7 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; Slu..at an CAY <br /> 1.20 gpd/ft'+Q e gpd/ft' 7 1S... <br /> • Soil lou coarse for insullauets of a <br /> standard system. <br /> See 7080.0170 Subp 2.G.3, age 28. <br /> 4. Multiply adsorption width ratio by rock layer width to get •• Soil having 5011.or more of�ne sand <br /> required adsorption width; So°i too heavy forry fine installation <br /> nstallation of a <br /> standard system. <br /> 2.7 x�_ft = _ft Sce 7040.0Z 10 Subp s.A.pago 33. <br />