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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(gpd) <br /> Estimated�.Sc�gpd Number <br /> TypeTyp <br /> or measured x 1.5 = gpd. Bedroom: Ie II Type III Type IV <br /> 2 300 225 180 60% <br /> 3 450 300 218 f j <br /> B. SEPTIC TANK LIQUID VOLUMES 4 600 375 256the <br /> rr=. I <br /> 5 750 450 294 in <br /> ' 5C) I-10o() gallons 6 900 525 332 the <br /> 7 1050 600 370 o <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) Naber s <br /> 1. Depth to restricting layer= 156 -6;e inchesB f -edmoms , o bw <br /> 2. Depth of percolation tests = 1. inches ``umo `""m`) <br /> 3. Percolation rate 4S . mpi 23«as` 17.0500 1'.112 <br /> 5or 6 1.500 2,250 <br /> 4. Land slope - % 7 or g 2.00D 3.000 <br /> over 9 See fig.C-6 (x IS) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = , <br /> 7S0 gpd x 0.83 sq. ft./gpd sq. ft.-1)a,�v i�Ay <br /> 2. Select width of rock layer (10 feet or less) = / 10 ft. <br /> 3. Length of rock layer= area_width = Rock Bed <br /> -t.,,64-sq. ft. -- _ln ft. _ t.,,K ft. .,.�.,.,.,.ti.�...�.ti.,.,.�.,.,.ti <br /> J•J•J•J•J•J•J•J•! I•J•J•J•!•J•J• <br /> 1 ti•tiK•1 1•ti•ti•ti•ti•ti•1.1•ti•ti•ti•t <br /> !•!•J•J•!•J•!•!•!!•!•J•J•J•!•J• <br /> ~!~!:J~l�l,!f~J r r f�rtir•itif fti idth <_10 ft. I <br /> •S • • • • •JY <br /> •t•ti•ti•ti•�•t•ti•ti•ti•ti•1•�•1•ti•1•ti <br /> JJJJJ •J•J•J•J•J•J•J•J•!• <br /> E. ROCK VOLUME Length -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 0454 sq.ft. x i o ft. _ cu.ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> (,,%4 cu.ft. 27=-;�f) cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 2 cu. yd.x 1.4 ton/cu. yd. _ tons. <br /> F. ADSORPTION WIDTH L LA Y LA N wl Absorption wide,SuingTable <br /> 1. Percolation rate in top 12 inches of soil is q.4 mpi Percolation Rate �"� o& <br /> Minutes pa inti+ Soil Texture P,=- iedc6 ft <br /> r,ed.o <br /> (mpi) f••. r• a. <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> .L4 gpd/ft'- 0.1 to 5 Sand 1.20 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio b dividing rock layer 16 to 30 Loam 0. 0 2.00 <br /> � iy g y 31 to 45 Silt Loam 0.550 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Clay Loam 0.45 2.67' <br /> 1.20 gpd/ft-2 .Lj:gpd/ft2= a�l„ Slower t 61 aClay oz4 �_oo <br /> � wer thann 120 Clav 11 <br /> ••Soil having 30%or more of fine or very fine sand I <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> D,L"')x iy ft=,a 4"r) ft <br />