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1997-009510 - new septic system
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2425 Thoroughbred Lane - 04-117-23-11-0018
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1997-009510 - new septic system
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Last modified
8/22/2023 5:06:17 PM
Creation date
4/17/2019 1:29:20 PM
Metadata
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Template:
x Address Old
House Number
2425
Street Name
Thoroughbred
Street Type
Lane
Address
2425 Thoroughbred La
Document Type
Septic
PIN
0411723110018
Supplemental fields
ProcessedPID
Updated
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LCT`" 'LCL;'- '✓ <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(gpd) <br /> Estimated ')SQ gpd Numba <br /> of Type I lype II Type III Type IV <br /> or measured - x 1.5 = - gpd. Bedrooms <br /> 2 300 225 180 <br /> 3 450 300 218 of <br /> B. SEPTIC TANK LIQUID VOLUMES 4 600 375 256 <br /> 5 750 450 294 <br /> -/OO (7 gallons 6 900 525 332 7 1050 600 370 °� <br /> mt <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) <br /> ,, , Numbs or r� <br /> 1. Depth to restricting layer = a4 to�>a inches Bedrof oom ter , <br /> 2. Depth of percolation tests = I'D, inches `"""' (PH-) <br /> Iess <br /> 3. Percolation rate I q • 3 mpi 23or44 17050°0 1LIZ <br /> W <br /> 4. Land slope 3 % 7 org 2. o <br /> ova 9 See fig.C-6 (x 1S) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = , <br /> r)So gpd x 0.83 sq. ft./gpd sq. ft-t toy„ -(o,,o <br /> 2. Select width of rock layer (10 feet or less) _ /0 ft. <br /> 3. Length of rock layer= area_width = Rock Bed <br /> 6,,14L sq. ft. y ft. _ _ft. . . .*,.ti.ti.,.�.�.�...�.,.ti.ti•,•ti <br /> !•!•!•!•!N•!•!•!•!•!N•!•. . . <br /> S•�• .ti.�.ti•ti•ti.♦.t•Nti•tiK•ti•S <br /> idth 510 ft. <br /> E. ROCK VOLUME ~- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> �,qLi sq.ft.x /,OSS ft. =-QL!�cu. ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 'Lc cu. ft. j-27= -.\2 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> cu. yd. x 1.4 ton/cu.yd. _ tons. <br /> F. ADSORPTION WIDTH <br /> A on width SizingTable <br /> 1. Percolation rate in top 12 inches of soil is 14 .3 mpi r�o,,h�,�,� tea- R.�d <br /> bd <br /> Minutes per MCI% Soil Texture ye,"u <br /> (mpi) - .b�.nea. <br /> •M" <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 4 gpd/ft'- 0.1 toy Sand 120 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio b dividing rock layer 16 to 30 Loan► 0.60 2.00 <br /> � �' g 31 to 45 Silt Loam 0" 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; -�40 C1av Loam .45 2.62 <br /> 1.20 gpd/ft2i��gpd/ft2= . (o Slowerthan 120 Clav 24120 Clay 5_00 <br /> ••Soil havimt 509E or more of fine or vev fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> .L,DX J0 ft = a l . ft <br />
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