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1998-010148 - new septic system
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1050 Tamarack Drive - 26-118-23-42-0006
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1998-010148 - new septic system
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Last modified
8/22/2023 4:18:51 PM
Creation date
4/16/2019 10:46:40 AM
Metadata
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Template:
x Address Old
House Number
1050
Street Name
Tamarack
Street Type
Drive
Address
1050 Tamarack Drive
Document Type
Septic
PIN
2611823420006
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G. DOWNSLOPE IRM WIDTH <br /> 1. If landslope is�6 �more,subtract rock layer width from <br /> adsorption width to obtain minimum downslope dike toe <br /> 1ft-,1o_ft = j 1)- feet <br /> 2. Calculate Minimum.mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation . o feet <br /> b. Multiply rock layer width by landslope <br /> to determine drop in elevation; 1 toot a e .a <br /> Slope Difference Saperetlo° (gel <br /> j_x_i`%+100 = , (.,_feet Slope Dlif erenee ! e t <br /> UDsIODe Width \ <br /> c. Add depth of clean sand for separation (2a) L feet RDcK Bed width <br /> at upslope edge,depth of rock layer (1 foot) to depth of 12 feet Downslope wlatn <br /> cover(1 foot) to find the mound height at the upslope edge 1'7 feet <br /> of rock layer; <br /> I. o ft+ lft + ift= 3.0 feet <br /> d. Enter table with landslope and upslope dike ratio. <br /> Select dike multiplier of Z.a-]) <br /> e. Multiply dike multiplier by upslope mound height <br /> to find upslope dike width: 3'o x 3.xs =z_ feet <br /> f. Add depth of dean sand for slope difference (2b) at <br /> downslope edge,to the mound height at the upslope edge <br /> of rock layer(2c) to find the downslope height; <br /> -3.o ft+ . ft= 3,L- feet <br /> g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of 5. a c. <br /> h. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width: s. 6. x 3.t, =1_feet <br /> i. Compare the values of step G.1 and Step G.2h Select the <br /> greater of the two values as the downslope dike width; <br /> 1�---feet t,De�o .�lot. <br /> j. Total mound width is the sum of <br /> .......... .. .........>.... I <br /> upslope dike(G.2e) width plus rock >'fi '. f5eek°ea wleln <br /> �.l.a <br /> layer width (D.2)plus D <br /> v UD$to .wl.ln UD6100e wic <br /> fee <br /> downslope dike width(G.2i) L <br /> 10 ft+moo ft+ g_ft = -ZL feet IMF!: <br /> k. Total mound length is the sum of 3� pD.ve I.D.wlDte <br /> taa <br /> upslope dike width(G.2e) plus rock layer - € a : <br /> length D.3 plus u slo a dike width (G.2e); <br /> gt <br /> ( >P P P i <br /> ft+a_ft+ /o ft= 4 ) feet <br /> Total Llhilth <br /> Downslope Upslope <br /> 311 4:1 sl fill 7:1 3:1 4:1 5:1 &1 7:1 6:1 <br /> 0 3.0 4A., SA LO 7.0 3.0 11.0 5.0 6.0 7.0 8.0 <br /> 1 399 L17 Sall L311 751 191 3AS 4.76 5.66 L51 7A1 <br /> 2 339 4x S56 L112 L14 2.113 3.70 454 536 6.14 6.90 <br /> 1 330 454 in 732 11.116 L75 3S7 43S 5.08 S.79 6AS <br /> 4 3A1 4.n 4.25 7.119 9.72 L68 3.45 4.17 4.114 5.16 6.06 <br /> S 353 S,W LO 857 10.77 2.613�� 4.00 4.62 S.19 S.716 -- 009 ')- 7.14 935 12072.54 _'�j,21J 3.95 4.41 4.93 SAI <br /> 7 3.80 556 7A9 1034 1373 248 .12 3.70 4.23 4.70 5.13 <br /> 8 395 SigL33 1154 ISM 242 3.03 3S7 4.05 4.19 438 <br /> 9 4.11 L25 90 Ism 18.92 236 1% 3.45 3.90 430 4AS <br /> 10 419 667 10.0 15.00 2333 2.31 286 337 3.75 4.12 4A4 <br /> 11 4.411 7.14 11.11 17.65 30A3 2.26 278 3X3 3.61 3.95 426 <br /> 12 4A9 7.69 1250 21.01 4375 1 121 270 3.12 3.49 3.80 4.08 <br />
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