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1998-010148 - new septic system
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1050 Tamarack Drive - 26-118-23-42-0006
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1998-010148 - new septic system
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Last modified
8/22/2023 4:18:51 PM
Creation date
4/16/2019 10:46:40 AM
Metadata
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Template:
x Address Old
House Number
1050
Street Name
Tamarack
Street Type
Drive
Address
1050 Tamarack Drive
Document Type
Septic
PIN
2611823420006
Supplemental fields
ProcessedPID
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(gpd) <br /> Estimated ao o gpd Nwof nber Hype l Type I Type III ,yp<ry <br /> or measured x 1.5 = gpd. Bedrooms <br /> 2 300 225 180 60+ <br /> 3 450 300 218 .1 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 600 370 256 <br /> s Iso Oso 244 v <br /> gallons i6 900 525 1 s�o <br /> s 1200 675 408 <br /> C. SOILS(refer to site evaluation) Number <br /> 1. Depth to restricting layer= 3 0 4 3 y o inchesB � - <br /> 2. Depth of percolation tests = ) a inches `'"0 `.125 <br /> 3. Percolation rate 3.LI mpi 23 or 44 tless 7.0�00 i'� <br /> 1-1 <br /> 4. Land slope e % S or 6 7 or l 2.000 00 3 3..0000 <br /> 00 <br /> over 9 S«6g.C.6 (a 1.5) <br /> D. ROCK LAYER DIlYMNSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer.A x 0.83 = <br /> Soo . gpd x 0.83 sq.ft./gpd = -.4g sq. ft.+►off, <br /> 2. Select width of rock layer(10 feet or less) _ /o ft. <br /> 3. Length of rock layer= area+width= Rock Bed <br /> a,),4 sq. ft.+ 1_ft. =12 ft. r�•�ti 1•�ti•ti•YYv.V�•�M•ti.�•♦•}Sv r�r�•r•r•3•r•r•r r r• <br /> � Y�NN•{�•�Y�N•1•ti•YZ•�H <br /> MRrdth 510 ft. <br /> r•r•r•}•r•r•r•r•r r•r•r•r•r•r•r• <br /> •r•r.r•r•r.r•r.r•r•r•r.r•r•r•r•r• <br /> E. ROCK VOLUME Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> a�sq. ft. x ),"!g, ft. = cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> cu.ft. +27= 1L_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> I l cu. yd. x 1.4 ton/cu. yd. =1 e- tons. <br /> F. ADSORPTION WIDTH LI.Ac q L O 4 vn W1dth Stain it <br /> 1. Percolation rate in top 12 inches of soil is mpi pereekdonx,b � ;;b; <br /> mints a�hVh Soil Texture *..r„� .;,,,,. <br /> Ir .►..rAr <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> .4S' gpd/ft2 0.1to5 FilneSan d" 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 152 <br /> 3. Calculate adsorption width ratio b dividing rock layer 16 to 45 Loam 0.50 2.00 <br /> rp y g }' 31 to 45 Silt Loam 050 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Cla Loam 0.45 2.67 <br /> 61 t0120 Clay 024 5.00 <br /> 1.20 gpd/ftz+ gpd/ft2 = a.t,;�_. Slower than 120 1 Clay - - <br /> •'Soil)u"501E or mom of fine or very fw.and <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ��x /0 ft = aL,r) ft <br />
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