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1992-004455 - new septic system
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2650 Silver View Drive - 33-118-23-42-0009
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1992-004455 - new septic system
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Entry Properties
Last modified
8/22/2023 4:51:41 PM
Creation date
1/4/2019 2:23:12 PM
Metadata
Fields
Template:
x Address Old
House Number
2650
Street Name
Silver View
Street Type
Drive
Address
2650 Silver View Drive
Document Type
Septic
PIN
3311823420009
Supplemental fields
ProcessedPID
Updated
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� �OWNSLOPE DIKE WIDTH <br /> . landslope is 2.9 percent or less, basal width includes both the <br /> upslope and downslope dike widths, <br /> 2. Calculate minimum mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation /��S feet <br /> b. Multiply rock layer width by landslope to determine drop <br /> in elevation; Slope Difference „�,�,,,,, <br /> ��� x_�%+ 100 = � feet „m°�; � <br /> c. Add depth of clean sand depth of clean sand for � ��,�,,,„.,�� '--�"'�`"""'"' i,s� �- <br /> a?< <br /> separation af upslope edge (2a) to depth of rock layer to�k" -- '"' 9i�°"'<� <br /> rock depth and the depth of cover to find the total mound �L� R"�"`�'dth � � <br /> height at upslope edge of rock layer• /p � �-�•�W�•�� � <br /> �5'ft+ 1 ft + I ft = �.5 feet � _Z I�, ` <br /> d. Enter table on page bottom with landslop e and upslope S'�,• � . n� c � <br /> dike ratio. Select dike multiplier of �. O �`�- � '7c� <br /> e. Multiply dike multiplier b�' upslope mound height <br /> to get upslope dike width:=� x .�S- _ /�� <br /> f. Add the depth of slope difference(2b) to the upslope <br /> height to get the downslope height C� ` +�.3 = ,�S�- <br /> g. Enter table on page E-18 with landslope and downslope et <br /> dike ratio. Select dike multiplier of �a <br /> h. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width: 4�:o x 3..s = � c feet <br /> - i. Mininmum'mound width is the sum of upslope dike <br /> width plus rock layer width plus downslo e dike '" <br /> =ft + /o ft + 15� ft= width; ���:���:. :; ����:�� � <br /> 3� feet '�:�:::�`;:�`••::�::�.,::.. : :.:�:.::.:�::�:��:::�: .:..:.;.x-�::::. <br /> � j. Subtract the Mi Raki�aw�d�h�'��`� � :u�b��i�i��w�d;h`��c'i�. <br /> nimum width G.i from the Absorption ��'7 <br /> width F.4 to�nd the Additional Downsiope required for � ��� ������������� ��� <br /> Absor Rak Iled Lcngth : .,,.,'..� <br /> � ption �.:;:. :;►�=�� <br /> � � �O ft 3� _ b ti��i�ciN�a"�'�`� `����`'''�' '��' �'� , <br /> ��.�_ k. Add it /a feet U� � �h�'�' :: :�.:....'•..''.;a"�' <br /> �•Upsbpc Dikc IN' t � <br /> �,�G�� the Additional Downslope required for Abso <br /> V to the do rption ,- <br /> .,,� wnslo e dike wid `��+���:�'� � <br /> �s u o M P th and recalulate the Total �W�io���ak���w�d,ti`�'�c� <br /> �u_.� ��5 ound Width which is is the sum of u slo � <br /> wid th P pe dike .�r <br /> plus rock la er _ <br /> p� j„ y width plus downslo <br /> �`�`Y� d a ft + / pe dike width <br /> ���(� a ft + 2� ft =�'v f e e t ��-T o t a l.L c n.t h.. <br /> c- 1. To ta l moun d length is the sum of upslope dike width g -� <br /> �,,, � plus rock layer length plus upslope dike width; �� � �� <br />��n c� ���J 2 o ft +�ft + Zc� ft= /a � feet <br />�u F c�� ��-,'� <br /> � � wns o <br />'y. �:i �:i s:i � �:� �:� a:i ps c�pc <br /> � <br /> ��iop� , �:� s:t 6:t �:i e:� <br /> = a�. r -;� 3� s,.� s�.� 60 �.o �.o ;� <br /> 2 3.�s �,ss S� �� �sa �.9� �� i.i6 " �.o �.o a.o <br /> 3 3� �S! e.�� Za� a.m s.r� s.s� �.a <br /> � � 7.32 �� 5.36 6.1� 6.90 <br /> 3.11 �.76 8.86 2.75 357 �.35 <br /> S 3S1 S.OD � 7.89 9.72 2.68 3.15 5.08 5.79 6.i5 <br /> 6 3� 5.26. 7� 9'� I0.77 2.61 3.33 l.00 I.BI S.t6 6.06 <br /> 5.�9 <br /> 7 ' <br /> � �� s� 7.69 /03t 13.� 25d 323 3.G5 t.q 5.71 <br /> 9 f.11 6� �'� 1151 15.91 �� 3.12 3.70 1.23 �.70 5.11 . <br /> 9.OD 3.Q1 S.t� <br /> 10 �29 i67 10.0 , 13.M 18.92 2.7! 1.91 3.57 �.t15 1.19 I.Ae <br /> 2.31 3.15 {.30 <br /> I1 t.td 7.I1 ll.11 I5.00 2J33 2e6 3.3J 7.90 l.65 <br /> I2 4.69 7.69 ILSO 17.65 30./7 2.26 278 3.75 �.12 I.d4 <br /> 21.0 �3.7i 2.21 3'23 3.61 3.95 {26 <br /> 2.7p _ 3.12 7.�9 3.9n �rq . <br />
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