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1992-004455 - new septic system
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1992-004455 - new septic system
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Last modified
8/22/2023 4:51:41 PM
Creation date
1/4/2019 2:23:12 PM
Metadata
Fields
Template:
x Address Old
House Number
2650
Street Name
Silver View
Street Type
Drive
Address
2650 Silver View Drive
Document Type
Septic
PIN
3311823420009
Supplemental fields
ProcessedPID
Updated
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• • MOIIND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) �-- � �� �� `� <br /> - A. FLOW <br /> � � �� ��� E� <br /> Es timated �� C� I:stimaicd Sew�Be Flows in OL��iM�s�dL <br /> or measured gPd (see pages D-7 or I_3� 4,5) y <br /> ----_ gpd x 1.5 = �m�:. cs��> <br /> t��e•�ms Trrx t 'rrr�:n iy�,:m I�V <br /> B• �EI'TTC TANK LIQUtD VOLUMES <br /> — �vZ�d 2 300 225 I RO <br /> gallons (see pages G3�r G5) 3 4so <br /> � 3� 218 ena. <br /> � J 75 25G ^r� <br /> 450 Zqd rdie. <br /> C• SOILS (refer to site evaluation) 6 900 ;� <br /> � 1050 GW 370 T�tv�. <br /> 1. Depth to restrictin 8 120° �'s a�K '° <br /> g layer- /8'- z� �d�� <br /> 2• Depth of percolation tests - �Z inches ,ty,�T,wk�.o.�.�,k;;,,R.��..�. <br /> 3• Percolation rate inches "�^��� MinimumLi�uiJ �., �;,�„�.;, <br /> 4. I:and �d mpi �k+d.00n,. G,p�;ry ;.�di.p,u,,'w <br /> slope o :a r.. �� <br /> /o iax� �izs <br /> IS(U �� <br /> �•� 1�xY� � <br /> m�er 9 <br /> D• ROCK LAyER pIMENSIONS ' <br /> � <br /> 1• Multiply f1ow rate by 0.83 to obtain required area of rock <br /> layer: Daily F1o�,�,x 0.83 = <br /> �Sv gpd x 0.83 s ft. 1 Z3 � <br /> 2• Select width of rock layer (10 f ep or les _ S�' ft''�' �`�r� ' ����� <br /> 3• Length of rock layer=qrea t Wi�th - S, — �—�ft. <br /> � ; � �'$=sq. ft. + /o _ ft. -� ft. <br /> `` Rock Bed <br /> ��! , <br /> f�f�:�r���f�r, / <br /> E. ROCK V �••;:.•:f:•� �'��ti::f;f:::f:: T � -- <br /> OLIIMg t l t:'1i:ti�'��,�1.1�1������:�'� I <br /> 1• Mu1H 1 f:�•i::f�•�~��1�'r��:���t�f tVidth SIOft. <br /> ply rock ar r'• •:. ....:•�1 <br /> ea by rock depth to get cubic Eeet of rock; r_-- Length �--�, <br /> ��d sq. ft. x l.o ft. _ �8� <br /> 2• Divide cu, ft. b — �• ft. (,,A �' <br /> Y 27 cu. f t./c u. ��, f o ge t cu bic yards; <br /> �g� cu. ft. + <br /> 3. Multiply cubic ard 27=cs7��`�cu. yd. <br /> ,�s a y s by 1.4 to get weight of rock in tons; <br /> — �• yd• x 1.4 ton/cu, yd, =,3 � to <br /> ns. <br /> F. ADSORPTTON WIDTH <br /> I• Percolation rate in top 12 inches of soil is �� <br /> 2• Select allowable soil loadin rate from table on aPe g_. �h��tiu�i Wf����5���,�k 7��Ic <br /> Q.�� p g r«��U�w�� <br /> * pna/`� i m Minutc:per Soi!Tezluro Galkwis Ratio of <br /> 3• Calculate adso -� �r- � �nch(MPI) ���OYtkr �n�,.�,;o„w;�,i, <br /> rption width ratio by dividing rock layer Fi��N������ , ��a��""' ,°�°`"�Y`T <br /> loading rate of 1.20 wK►�n <br /> gpd/ft +pa/f�bY al Zowable soil loading rate; o°�ws;. �sn"� �:20 <br /> 1.20 2 s,�w -.... <br /> —�gpd/ft — -, �� � FneSand�• �•� <br /> Check this va/ue on Q 6�°'s Sn�y��� o.LO Z`p <br /> t6 ta 30 [,pam 0.� 1.52 <br /> 4• Multiply adsorption width ratio by ock layer Width to �'°,s S''`�m Z.��, <br /> Clry Lown 0.50 2.40 <br /> required adsor tion �,id�� get �Y o_z �r� <br />-'� �� ,w... . <br /> . � x 1v Ft = 5t� ft <br /> J: . <br /> T <br />
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