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<br /> , G. �DOWNSLO E DII�WIDTH �
<br /> 1. If landslope is 3% or more,subtract rock layer width from
<br /> ;=;�:, adsorption wi th to obtain minimum downslope dike toe
<br /> `' � ' �. ft-_LQ_ft=�_feet
<br /> 2. Calculate Min num mound size based on geometery:
<br /> a. Determiane depth of clean sand fill at upslope edge of rock
<br /> layer: Separation a, o feet
<br /> b. Multipl}r rock layer width by landslope r reor co�.�.
<br /> e teot Ro •a
<br /> to dete 'ne drop in elevation;
<br /> Slope Di ence s.o.�si�op i..c
<br /> X 3 %i 100 = •3 feet s1ev• or�r.�.��.� .�
<br /> uosiooe w�atn
<br /> c. Add dep of clean sand for separation (2a) -�-r�« Rock 8e0 w1atD
<br /> at upslo edge,depth of rock layer(1 foot) to depth of �+��� oaw�:�ooe w,at�
<br /> cover(1 f t)to find the mound height at the upslope edge �-f°"
<br /> of rock la er;
<br /> � �.o ft+ Ift+ lft=�_feet
<br /> d. Enter tabQe with landslope and upslope dike ratio. �
<br /> Select dilqe multiplier of :� .S�
<br /> e. Muldply dike multiplier by upslope mound height
<br /> to find u�slope dike widths y.� x 3.�� _�_feet '
<br /> f. Add depth of clean sand for slope difference (2b)at
<br /> downslop�edge, to the mound height at the upslope edge
<br /> of rock lay�er(2c) to find the downslope height;
<br /> ' �y,o ft+��ft= �.3 feet
<br /> �� g. Enter tabl�with landslope and downslope dike ratia
<br /> ` -. Select dik multiplier of y ,S�
<br /> h. Multiply�ike multiplier by downslope mound height
<br /> to get downslope dike width: y.3 x 4 Sy =,�Z feet
<br /> i. Compare the values of step G.1 and Step G.Zh Select the
<br /> greater of the two values as the downslope dike width;
<br /> ;.;<:: ;::,::
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<br /> Tq+i;yi; .. . .�i::�.w:::'v.:.fi1
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<br /> IO�+S S f��l
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<br /> � �.r..t .. . ...:,.. . . �_��..t
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<br /> rotetl•nptn 9.,�'
<br /> wn ope ps ope
<br /> 3:1 l:l 5:1 &1 7:1 3:1 l:l 5:1 Sl 7:1 83
<br /> x
<br /> 0 3A l.0 SA i0 7.0 3.0 �.0 5.0 60 7.0 8A
<br /> 1 3A9 1.17 5�6 638 753 291 3.D3 �.76 5.66 6.51 7A1
<br /> 2 3.19 556 6.Q 8.N 2.83 3 151 536 6l4 6.90
<br /> 3 330 Sd1 732 6.86 2Ta � {3S 5.� 5.79 6.�5
<br /> ,�. _�--�3,t1-_ 4.96 `625----7,lq----�9.72--- -266'-'-3. 1.17 l8t 5.r6 6A6
<br /> t-•;'3a� 5 353 � 6AD i67 S57 ]077 26I 33i �.OD L62 5.19 571
<br /> .`•� 6 366 b26 7.1� 93b 1207 2.Si 333 3.lS ll1 �.93 SAt
<br /> 7 3�D Ssb 7.69 7031 1373 2t8 3.72 3.70 a23 �.70 5.13
<br /> 6 3.% 5� � liSt 1591 2Q 3.m 3S7 L� f.19 tis
<br /> 9 l.11 6.75 9A➢ I3D1 18.92 236 291 3.15 3.90 l30 4.65
<br /> 70 �2! i.67 10A 15.00 2333 231 286 333 3.75 t12 �A/
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<br /> 12 ': td➢ T.69 1LS0 21.�3 d375 221 27D 3.12 3.49 3.80 lA8
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