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1996-007924 - new septic system
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2685 Rainey Road - 04-117-23-43-0013
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1996-007924 - new septic system
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Last modified
8/22/2023 5:14:36 PM
Creation date
7/16/2018 9:10:05 AM
Metadata
Fields
Template:
x Address Old
House Number
2685
Street Name
Rainey
Street Type
Road
Address
2685 Rainey Rd
Document Type
Septic
PIN
0411723430013
Supplemental fields
ProcessedPID
Updated
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• � � OUND DESIGN W�RKSHEET <br /> � ' (For Flows up to 1200 gpd) <br /> A. FLOW Estimue+d Sewage f7ow in Gallons pa Day(gpdj <br /> Estimated gpd � <br /> or rrleasured x 1.5 = -- gpd. s�a� �`' '�`'t 'y�`»I �`'v _ <br /> 2 300 2?S 180 6at <br /> D 3 450 30U 218 � <br /> i7. SEI�'ITC T . LIQUID VOLIJMES � a � 375 � r�m <br /> a;�oo c7 ,Sallons s �so .so i� �. <br /> 6 90o su 332 � <br /> 7 1050 600 370 °'�' <br /> mt.�. <br /> 8 1200 675 406 <br /> C. SOII.S(refer tq site evaluation) N,�� ►�. ,� <br /> ,� ,� o� �� �.,�. <br /> 1. Depth to r�stricting layer= ta -�o a y inches �,� �.,,, ,;�,, <br /> 2 Depth of pereolation tests = , )a'' inches `'"' `'"'�`' <br /> 3. Percolado rate �a ,a mpi 23 a'4` ,'o�oo i;s o <br /> 4. Land slo 3 % ;Q 8 � � <br /> ova 9 See fq.C-6 (z 1.� <br /> i i <br /> � D. RO�K LAYER DIlvIEIVSIONS <br /> 1. Multiply flpw rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = � <br /> �oo . gpd x 0.83 sq.ft./gpd = y 9� sq. ft.�ro�o su�' <br /> � 2 Select width of rock layer(10 feet or less) = 1 o ft. <br /> 3. Length of rpck layer=area s width= Rock Bed <br /> �_sq. ft.i ��o, ft. _�,5,_ft. ti. <br /> .ti,.ti,•,,•.•ti.,•,•,•,...,.. <br /> 1•!•�N•�•�•t•t•r•�•t•�•�•r•!•1• <br /> � h.�.ti.ti.ti.ti.�.ti.ti.t•tK•ti•M 1 M�ti <br /> tiJ{:�:ti:ti:tijti.f{fti:ti�y:yf�yfy�yfti�ti �dth 510 ft. <br /> � tirtftiil:tii�?tii�i�itirti���tifti±tif�f� <br /> •f�f•t.I.f.r.f•r•f.f•f•j•j./•j•f• <br /> E. ROCK VOLUM� ~- �"g�' � <br /> 1. Multiply r ck area by rock depth to get cubic feet of rock; -� <br /> �sq. ft. x�ft. =S�y cu. ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> s�H cu. ft. i 27=,3L cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �c�a. yd. x 1.4 ton/cu. yd. _�tons. <br /> F. ADSCtiRPTTON TH G��K L07�tr✓I ' lvdth ' " Tabk <br /> 1. Percolation ratle in top 12 inches of soil is m i � �� <br /> Ja.z p' r�a.ti«,�� ��,. �... <br /> M;,�y m�;,,�, SoilTexture �� ,.;,d,,. <br /> t.w �6.�w� <br /> ..�iA <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse sana 12o i.00 <br /> ��� �d/ffi 0.1 to� Sand 1.20 1.00 <br /> 0.1 to� Fine Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adso hon width ratio b dividin rock la er 16 to�o L'°�' o.� �-oo <br /> � � Y 8 Y 31 to 4� suc�m o� 2.�0 <br /> loading rate of 1,20 gpd/ft2 by allowable soil loading rate; �co bo c�a t,oan, o.4s 2.�� <br /> 1.20 gpd/f?�i .tiS gpd/ft�= a,l�� Slowerthan 120 �y oZ4 �-oo <br /> "Shc havi�50�or mare of fu+e or vey fxt+e saad <br /> 4. Mul�iply adsorpdon width ratio by rock layer width to get <br /> requ'ved adsorption width; <br /> �_x�ft=� : ft <br /> ,.J <br />
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