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HomeMy WebLinkAboutSeptic design �b ��SiG� ?� . , �� � f . • . . emo To: Melanie Curtis ��.1�.�J From: Willie Gibbs, SSTS Manager ����/�.� Date: 1/29/2013 Re: Bayside Meadows Proposed Plat I have reviewed the preliminary septic system designs for the 5 proposed lots in Bayside Meadows Addition. The designs show two standard septic sites for each lot with a proposed house site. Lots 2-5 would allow some flexibility in final house location. Lot 1 does not allow for any flexibility and should be noted as such. The septic sites split much of the lot and along with the wetland limits the house site to basically where it is proposed. I have stamped approvals for the five proposed sites. If you have further questions please let me know. 1 t . � � r� � �1/l � /V � � �f �" a�c��v�D �� I �� JAN 2 3 2013 Joseph Olson D.B.A. �rTlf 0�ORONO Rusty Olson's--Soil and Percolation Testin�-�� Joseph J. Olson--MPCA License #810 11481 Riverview Rd. NE, Haoover, MN 55341 (763) 498-8779 fag (763) 498-8290 January 15,2013 Ervin Wachman PID#0611723220018 Proposed Lot 2 Orono,Hennepin.County This on-site Sewage Treatment System is partially designed for a Type 1,five-bedroom home in accordance with the Minnesota Pollution Control Agency Chapter 7080 and local ordinances. Once the house size, location and septic primary and future sites are chosen this desigr►can be completed. The periodically saturated soils were located at 16-18 lnches(mottled soil). Due to the periodically saturated soils,a pressurized mound system will need to be installed to treat the septic effluent.The bottom of the treatment area must be located at least 3' above the saturated soils. The soils at a depth of l2"have a percolation rate averaging 6.5 MPI. The absorption areas do not overlap. All tanks need to be insulated if there is less than two feet of cover over the top of the tanks.A fi Iter needs to be installed on the second tank.Clean outs must be installed on the end of the laterals for maintenance. A pumping chamber will need to be installed to lift the effluent to the treatment area.The power supply and switches must be located outside the manhole and pumping chamber in a weatherproof enclosure.A warning device must be installed with a light and sound device;this is in case of a pump failure. Use 7/32 inch perforations on the laterals. Keep all heavy eyuipment off of t6e proposed treatment areas before and after construction.The treatment area must be fenced off before construction begins.This Design is not valid &the System will need to be relocated if failure to protect the areas proposed for the On-Site Sewage Treatment systems occurs. Nothing other than gray water,(laundry,showers,ect.)human water&toilet rissue should be disposed of into the septic tanks. Garbage disposals are not recommended.Additives must not be used;they may cause harmful damage to your septic system. It is recommended that you pump the septic tank every year for 1 tank,every two years for two tanks. sincerely, �"�'�' �F O ONQ �� 5EPTIC PE IT P _REV _._----- �eph J.Olson INSPECT��Rc DATE '' ' 3 PBRMIT NO.�,,,.,.,�,,,,,,...,�., APPRQYGA AS St;ii�t(TTEU APPROYGD WITH CORRF:CTIONS AS nOTBD NOT AFPROYF:U•CURRF.CT&RF:5L'HMIT � 'Thcsc eommentc are for your information. All work shall bc du� _:� in full compliance with all upplicuble scptic und zoning cuda �l Reyuiremcnts inctudin�items not sprcificaliy not�J ia Uiis c�wieW. f� ,:,,�,�.� K f:G!'T H�S P L A K S E T U h S 1 T E A T A L 4 T I�N 4 S .�� �� ' . ' + � � ♦ ^ ' ., a • +�� " .. 1 ' ' v � � � �...�°'t # . 'a . . 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J � � '�i� .�\\ _ ty , ��\ � /'J . �i - - �. v � s - _�v:. :� ^7. r v A_�`� f� �{� C� ...� V t� !"� � -� i. . � ��< O � � ���-1 Q r _ `�, ,� �� �; �(:;'� �' i 1 � i `�?;o � � � � ; `-'�__ �-''��. �'� ��` - . � �; ,_ ,v, . C� ���� �, � � ;,- � - � = --� � , ��- ] � o n � � � �f.. �:.. � -----------:� I � � c � � �' !\ �� � A � ` � � LI7 � ' � �-; � + �" o� � � �7 O � ; � D d � � � C' V� ' = � •"� 6 '(� � i � (✓ . i � � {} i � �, i � �`� � � � �_ � I � � � ,_ �: � i 3 -�r'.- i � � ' i^ OSTP Design Summary Worksheet UNIVERSITY `� Minnesota Pollution OF MINNESOTA ���` `" Control Agency �,��;;;, Property Owner/Client: Ervin WaChmdn ���•�9•ZZ ProjectlD:� site address: Proposed Lot 2 (Site A ) 1. AVERAGE DESIGN FLOW: A. Design F(ow: 750 Gatlons Per Day(GPD) Note: The estimated design flow is considered a peak ffow rate incfuding a safety factor.For long term performance,the average dai(y flow is recommended to be< B. Septic Tank capacity: 2250 Gallons 6o%of this va(ue. �. Number of Septic Tonks or Comportments: �� Efffuent Screen&Alorm? NO Type of Soil Tread�nt and Dispersal Area* Type of Distribution• � Trcnches Q Bed QQ Mound �At-Grade 0 Gravity Distribution QQ Pressure Dis6ibutbn-l.evel Q Piessurc Distribution-Unkvel �Drip Distrib. � Holding Tank� Oth�� 'Selection Required Benchmark Elev= ft System Type Benchmark Location: ASSumed [�y_!Type I (i Type II ❑Type Iil [l Type IV ❑Type V Type of Distribution Media: Rock D. Pump Tank 1 Capacity: ��Gatlons Pump Tank 2 Capacity: ��Gallons L��J 2. SITE EVALUATION: A. Depth io Limiting Layer: 18 inches 1.5 ft Elevation 8 Location of Limiting Layer: 9$$,5 ft B. Measured Percent Land S(ope: 12.0 % 0.0 Location: BdCkSlOp2 C. Soil Texture: Clay Lodm Perc Rate: C7�MPI D. Soil Hydraulic Loading Rate: 0.45 GPD/ftZ E.Contour Loading Rate 12.0 Gal/ft 3. DESIGN SUMMARY Trench Design Summary Dispersal Area �ftZ Sidewall Depth C��n Trench Width C��� Total Lineal Feet �ft Number of Trenches �� Maximum Trench Depth �in Designers Max Trench Depth��in Bed Design Summary Absorption Area ��ft� Media Below Pipe ��in Bed Length C�ft Bed Width �ft Maximum Bed Depth ��in Designers Max Bed Depth �in Mound Design Summary Absorption Area 625 ft2 Bed Length 63 ft Bed Width 10.0 ft Absorption Width 26.0 ft Clean Sand Lift 1.5 ft Berm Width (slope 0-1%)�ft Upslope Berm Width 10.0 ft Downslope Berm Width 25.0 ft Endstope Berm Width 15.0 ft Total System Length g3 ft Total System Width 45 ft At-Grade Design Summary Absorption Bed Width �ft Absorption Bed Length C�ft System Height �ft Absorption Bed Area �ftZ Upslope Berm Width �ft Downstope Berm Width �ft Endslope Berm Width ��ft System Length ��ft System Width �ft MinnesotaPollution OSTP Design Summary Worksheet UNIVERSITY � , Control Agency OF MINNESOTA ' ,���� Pressure Distribution Summary No.of Perforated Laterats �� Perforation Spacing �3 �ft Perforation Diameter 7/32 in �-- Lateral Diameter 2.00 �n Supply Pipe Diameter 0.00 in Minimum Dose Volume � Flow Rate 36 GPM Total Head ��ft Maximum Dose Votume 187.5 Holding Tanks Only Number of Holding Tanks � Total Volume of Holding Tanks � Sallons High Level Alarm? � 4. Additional Info for Type IV/Pretreatment Design Type of Pretreatment Unit Being Installed: Organic Loading to Pretreatment Unit =Design Flow X Estimated BOD in mg/L in the effluent X 8.35:1,000,000 �BPd X ��mg/L X 8.35=1,000,000= �tbs BOD/day Calculate System Organic Loading: fbs. BOD/day:Boitom Area =lbs/day/ft� ��lbs/daY= �ftZ= ��lbs/day/ftZ Comments/Special Design Considerations: I hereby certify that I have completed this work in accordance with all applicable ordinances, rules and laws. Joseph J Olson ..---------- 810 01/12/13 (Designer) ,.'� (Signature) (License#) (Date) � � OSTP Mound Design Worksheet Minnesota Pollution p UNIVERSITY Controi Agency >1 / Stope OF MINNESOTA �""'?',��;`�., �• SYSTEM SIZING: ProjeCt ID: v 11.09.22 A. Design F(ow(Flow&Soi(- 1.A): 750 GPD TABLE IXa B. Soil Loading Rate(Flow&Soi(-3.C): 0.45 GPD/ftZ LOADING RATES FOR DETERMINING BOTTOM ABSORPTION AREA AND ABSORPTION RATIOS USING PERGOLATION TESTS C. Depth to Limiting Condition: 1.5 ft Treatment Leve1 c Treatment Lcvel A,A•2,B, D. Percent Land S(ope: 12.0 % � Perco�ation Rate Absorptioo ���d nbso�onoo ��� Area Loading Area Loading ���� Ra[e Absorption Rate �SOfP�O� E. Design Media Loading Rate: 1.2 GPD/ftZ ' � (��RZ) Ratio ���ft� Ratio F. Mound Absorption Ratio(Tabte IXa): 2.60 I<o� . � _ � G.Design Contour Loading Rate: 12.0 GPD/ft o'`O 5 1.2 > >.s i �-0.�to 5(fine sand 0.6 2 1 1.6 Tabie 1 and ioamv I�ne sarxl 1AOUND CONTOUR LOADING R.1TE5; e t��� 0.78 �.5 � 1.6 s.oawrad ' Texturp-darivad �Cntaur ?o"to 30 0.6 2 0.78 2 Rprc Rais oR mound abso�pdon rat,o Loading .3;ro� . Fat4: 0.$ 2.4 0.78 2 �'���� 0.45 2.6 0.6 2.6 :b0�:i,'.. L0. i.i.2Q.'[.-1.L6 c 12 ,6�totZp _ 5 0.3 5.3 51-12C mpi �R S.Q cti '>t?0 - ' ' ' = �=�'�"�" �`-'-� -h' 'Systems with these values are not Type I systems. Contour Loading Rate(linear loading rate)is a recommended value. 2. DISPERSAL MEDIA SIZING A. Catculate Required Dispersal Bed Areo:Design F(ow (1.A):Design Media Loading Rate (1.E)=ftZ If a larger dispersal media area 750 GPD: 1.20 GPD/ftZ = 625 ftZ is desired,enter size: ��ftz B. Calculate Dispersal Bed Width:Contour Loading Rate (1.G):Design Media Loading Rate (1.E)=Bed Width 12.0 ft : 1.2 gpd/ftz = 10 ft C. Calculate Dispersal Bed Length: Dispersal Bed Areo (2.A)=Bed Width (2.6)=Bed Length 625 ftz : 10 ft = 63 ft D. Select Dispersol Media: E. If using a registered product,enter the Component Length: ��in: 12 = �ft F. If using a registered product,enter the Component Width: �in: 12 = Qft G. Number of Components per Row =Bed Length (2.C)divided by Component Length (4.J) (Round up) � ft : � ft= �components/row H, Number of Rows =Bed Width (2.6)divided by Component Width (4.K) (Round up) Note:CLR of 10.3 ga(/ft results in 9 foot Adjust Contour Loading Rate on Design Summary page until this number is a whole number wide bed. � ft: � ft= �� rows I, Toto(Number of Components =Number of Components per Row X Number of Rows � X � - ��components ' 3. ABSORPTION AREA SIZING Note:Mound setbacks ore measured from the Absorption Area. A. Calculate Absorption Width:Bed Width (2.6)X Mound Absorption Ratio (1.F)=Absorption Width 10.0 ft x 2.6 = 26.0 ft B. For slopes>1%,the Absorption Width is measured downhill from the upslope edge of the Bed. Catculate Downslope Absorption Width:Absorption Width (3.A)-Bed Width (2.6)=ft 26.0 ft - 10.0 ft = 16.0 ft 4. MOUND SIZING A. Calculate C(ean Sand Lift: 3 feet minus Depth to Limitinq Condition (1.C)=Cleon Sand Lift (1 ft minimum) 3.0 ft - 1.5 ft = 1.5 ft Design Sand Lift(optional): �1.5 B. Calculate Upslope Height:C(ean Sand Lift (4.A)+media depth (t ft.)+cover (1 ft.)=Upstope Heiqht 1.5 ft + 1,0 ft + 1.0 ft= 3.5 ft D-?-,:�lo[e'.tuitiplier Tahir � Ld(1dSI0pt+;5 0 I 2 3 4 5 6 1 8 9 iQ II 11� 13 id IS 16 f7 '8 14 20 21 22 13 Z4 1� i I Up�19R? I's:1 ?.00 2.51�i.3i 1.15 2.5$ 2.Si 2.Ss�2.�49 Lai �.35��.31i2.2� 2.;I�T.'? i.�?ji.CS i.05 ?.u; ?.00� 1.9? 1.9> I."r� l.i� i.89 1.8' L?i! j E��7n hd;'n jd:i �.�J i.85 i.i0 3.57 3.d5 J.33�3.23 3J2 ?.D3 2.9a�?.8b 2.78 2.70 2.b2 2.55 2.�8 ?.at 2.35 214 ?.23 2.18 2.13 2.08 1.Di 198 1.9�j I LandSlope`b 0 1 3 a 5 h 7 9 9 10 il 11 ' !7 i3 I5 I4 �1 IB 19 10 21 2t 13 24 25 i � DO';;I151rp? �`1:1 3.1N :.C'>�3.'i 3.i^ i.al 3.53�i.Eb�i.F.t ?55 4.0 419�:.1�3 �.SS�'�5�i,'tJ i.i5 5.89 6.2�! �.63 7.0: 7..1.'• ?.=>i 9.�1:�3.9's 9.�t6 it�.U�� �� E�Ifii R�i�i; i4:1 ;.DO �.17 J.35 J.�l d.76 9.� 5.I6 5.55 5.B6 b,i5 5.b1 ?,ta 7.65 E."t5 8.92 951 10.2a 10.4J it.67 12.J2 13.14 '3.59 W.8't �5,67 ?6.5� 17..�:� � Select Upslope Berm Mu(tip(ier (based on land slope): 2.70 (figure D-34) D. Calculate Ups(ope Berm Width:Multip(ier (4.C)X Ups(ope Mound Height (4.B)=Ups(ope Berm Width 2.70 ft X 3.5 ft = 10.0 ft E. Calculate Drop in Elevation Under Bed:Bed Width (2.B) X Land S(ope (1.D):100=Drop (ft) 10.0 ft x 12.0 % : i oo= 1.20 ft F. Calcutate Downstope Mound Height:Upslope Height (4.6)+Drop in Elevation (4.E)=Downslope Height 3.5 ft + 1.20 ft = 4.7 ft G Select Downs(ope Berm Multip(ier (based on land stope): 5.32 (figure D-34) H. Calculate Downslope Berm Width:Mu(tip(ier (4.G)X Downslope Height (4.F)=Downslope Berm Width 5.32 x 4.7 ft = 25.0 ft I. Calculate Minimum Berm to Cover Absorption Area:Downs(ope Absorption Width (3.6 or 3.C)+4 ft. =ft 16.0 ft + �� ft = 20.0 ft J. Design Downslope Berm =greater of 4H and 41: 25.0 ft K. Select Endslope Berm Multiplier: 3.00 (usualty 3.0 or 4.0) L. Calcutate Ends(ope Berm (4.K)X Downs(ope Mound Height (4.F)=Ends(ope Berm Width 3.00 ft X 4.7 ft = 15.0 ft M.Calculate Mound Width: Upslope Berm Width(4.D)+Bed Width (2.6)+Downs(ope Berm Width (4.J)=ft 10.0 ft + 10.0 ft + 25.0 ft = 45.0 ft N. Catculate Mound Length:Endslope Berm Width (4.L)+Bed Lenqth (2.C)+Endslope Berm Width (4.L)=ft 15.0 ft + 63.0 ft + 15.0 ft = 93.0 ft Comments: • 5. MOUND DIMENSIONS ---------------------------------- � Upslope (4.D) �o_o � v � i �� � � , , � Endslo e (4.L)I, Uispersat Bed: (2.B x 2.0} �Endsto e 14.L►, c: �' I ;15.0 � ' 15.0 � 10X 63 � ; � ' � � r� i � ; � � � � v ' � � c , o �' ' � �a Downstope (4.J) 25.0 � �---------------------------------- ---------_ Totat Mound Lenoth (4.N) 93.0 4" inspecti�n pipe 18"cover on top Ups(ope berm (4.D) Downslo e benn �4.J► 25.0 ; 10.0 12"cover on sides _ (6" topsoil) 1.5 iClean sand tift (4.A� (ft �� 1.5 ' .. t ii Absor tion Width 13.A) �Jote: 26.0 For 0 to 1 o stopes, Absorption Width is measured from the Bedequally in both directions. For slopes >1��, Abso�ption W�dth is measured downhill from the upsiope edde of the BPd. OSTP Mound Materials Worksheet UNIVERSITY � Minnesota Pollution OF MINNESOTA �` ,�,�� Control Agency - Project ID: ��� O9 Zz A• Calculate Bed (rock)Votume:Bed Length (2.C)X Bed Width 2.6)X Depth =Vo(ume ft') 63.0 ft x 10.0 ft X �.0 = 630.0 ft3 Divide ft'by 27 ft'/yd'to catculate cubic ards: 630.0 ft' : 27 = 23.3 yd' Add 20%for constructability: 23.3 yd3 X 1.2 = 28.0 yd' B. Calculate C(ean Sand Vo(ume: Volume Under Rock bed:Averaqe Sand Depth x Media Width x Media Length =cubic feet 2.1 ft x 10.0 fc X 63.0 ft = 1323.0 ft; For a Mound on a slope from 0-1% Volume from Length=((Upslope Mound Height-1)X Absorption Width Beyond Bed X Media Bed Length) ft -1) X X ft = Votume from Width=((Upslope Mound Height-1)X Absorption Width Beyond Bed X Media Bed Width) ft -1) X X ft = Totol Clean Sand Volume:Volume from Length+Volume from Width+Vo(ume Under Media ft' + ft' + ft3 = ft' For a Mound on a slope greater than 1% Upslope Volume:((Upslope Mound Heiqht - 1)x 3 x Bed Length)T 2=cubic feet (( 3.5 ft -�) x 3.o ft x 63.0 )T z= 236.3 ft' Downslope Volume:((Downslope Height-1) x Downslope Absorption Width x Media Length)*2=cubic feet (( 4.7 ft-�) x 16.0 ft x 63.0 )�-z= 1864.8 ft' Endslope Volume:(Downslope Mound Height- 1) x 3 x Media Width =cubic feet ( 4.7 ft-1 ) X 3.0 ft X 10.0 ft = 111.0 ft' Toto[Clean Sand Volume:Upslope Volume +Downslope Volume +Endslope Volume +Volume Under Media 236.3 ft' + 1864.8 ft' + 111.0 ft3 + 1323.0 ft'= 3535.1 ft3 Divide ft3 by 27 ft3/yd3 to calcutate cubic yards: 3535.1 ft' = 27 = 130.9 yd' Add 20%for constructabitity: 130.9 yd3 X 1.2 = 157.1 yd' C. Calculate Sondy Berm Volume: Total Berm Volume(approx):((Avg.Mound Height-0.5 ft topsoil)x Mound Width x Mound Length)+2=cubic feet � 4.1 _ 0.5 )ft x 45.0 ft X 93.0 )=z= 7533.7 ft' Tota!Mound Volume-C(ean Sand volume-Rock Volume=cubic feet 7533J ft3 - 3535.1 ft' - 630.0 ft' = 3368.6 ft' Divide ft'by 27 ft'/yd'to calcutate cubic yards: 3368.6 ft' = 27 = 124.8 yd; Add 20%for constructability: 124.8 yd' x 1-2 = 149.7 yd' D. Calculate Topsoi!Material Vo(ume:Total Mound Width X Total Mound Length X.5 ft 45.0 ft x 93.0 ft X o.5 ft = 2092.7 ft' Divide ft3 by 27 ft'/yd3 to calculate cubic yards: 2092.7 ft' : 27 = 77•5 yd' Add ZO%for constructability_ 77.5 yd' x 1.2 = 93.0 yd' OSTP Pressure Distribution UNIVERSITY ..� Minnesota Pollution Design Worksheet OF 1�/IINNESOTA Control A enc �-�,L�,.- ProjectiD: v 11.09.22 1. Select Number of Perforated Laterals in rystem/zone: �_J _---- _ (1 feet is minimum and 3 feet is maximum spocing) �,,.,,�.,�„�.,�;,..,.�,,,. 2. Select Perforation Spacing: 3.0 ft �> = , _. �' , �,;,,�o�.,; - �....,�,.,�,� �.�,,,;m,,,,, ' ' �� t.."pe�lw;it�o�i•.�.�i:�<.r�f':i��.ut t"��"ol�ock t Z' 3. Select Perforation Diameter Size 7/32 in _ _ 6"u(rnck 4. Length of Laterals =Media Bed Length -2 Feet. �•,..��:,�,<,,,.. ,<,:�,-�., ,. �>�,f�,.,,;�,,.,>.,�,,,:, , ,,,� 63 - 2ft = 61 ft Perforation can not be closer then 1 foot from edge. 5• Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4) by the Perforation Spacing (Line 2}and round down to the nearest whole number. Number of Perforation Spaces = 61 ft - �ft = 20 Spaces 6. Number of Perforations per Lateral is equat to 1.0 plus the Number of Perforotion Spaces (Line 5). Perforotions Per Lateral = 20 Spaces + 1 = 21 Perfs. Per Lateral Check tab(e below to verify the number of perforations per(otera(guorantees less than a 10q discharge variation. The va[ue is double if the a center manifold is used. Maximu�n Number of Perfu-atia�s Fer Laterat to G�wrantee<1ff�Dischacge Yariat�on ' '�(�.�Fc-rtoratio:�s 7132 I;�ch F'e�farati��s Pe�-f�rt+on Spacing(Feetl F'ipe Diarr�eter ilnches) Perfaratian Spating Pipe D:ar►eter(tnches} S tu< 1ti: 2 3 fFee'ti 1 11�: tt: 2 3 7 10 13 18 3Q b0 2 if 16 21 34 68 '-+: 9 12 16 28 54 2�: i0 14 20 32 6-4 � P 12 16 25 52 3 9 14 f 9 30 6tl ?'16 Inth Per�oratic�ns 1�'8 In�h Perfarat:ans Fip?UiaRwt?r(Inchesj Pe.*foration Spacing Pipe D�ameter f.#ncl:esa Pe�v�dt-o��pac'ng{F'retl i 11. 1�: 2 3 IFeetl i i��: ft: t ? 2 12 i8 26 46 87 2 2f 33 4# 74 149 2i: 12 17 24 40 8�J 2� 20 3Q 4t b� 135 � 12 1fi 12 37 75 3 2Q 19 38 64 128 7• Tota(Number of Perforations equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of Perforated Loterals (Line 1). 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. -- 8. Calculate the Square Feet per Perforation. Recommended value is 4-10 ft 2 per perforation. Pa+«��+�o+xti,���o%,� Does not app/y to At-Grodes Hcad (� �<<oratbn Diamotcr � � ,,, ,,, �,, ,, Bed Area = Bed Width(ft)X Bed Length(ft) 1.0' 0.18 0.47 0.56 0.7{ 1.5 0.22 0.57 0.69 0.9 10 ft X 63 ft = 630 ftZ Z.°° °.2` °.5' °.� ,.°' 2.5 0.29 0.65 0.89 I.17 3.0 0.32 0.72 0.98 1_28 Squore Foot per Perforotion =Bed Area divided by the Total Number of Perforatfons (Line 7). +-o o.» o.e� ,.,3 ,.a� 5.0` O.Ii 0,97 1.26 1.65 Dwelling�wich 1/t6 inch m t/I irch 630 ftZ - 63 perforations = 10.� ftZ/perforations �f�� Dt�oratiom Dwellings wi[h�/8 inch pertoraeurs 2 feet O[her�staCiishments and N.5T5 wiU 3/tb 9. Select Minimum Average Head: 1.0 ft ��h�o,�<;���PeKo,a�a� 5 f�� Ocher e[abtishme.�t;and N5T5 viieh 1!8 inc� pe.fo.a��o�s 10. Select Perforation Discharge (GPM)based on Table IIi: 0.56 GPM per Perforation 11• Determine required Flow Rate by multiplying the Tota(Number of Perforations (Line 7)by the Perforation Discharge (Line 10). OSTP Pressure Distribution UNIVERSITY MinnesotaPollution Design Worksheet OFMINNESOTA ,�� -" Control A enc ti-'�\- 63 Perforations X 0.56 GPM per Perforation = 36 GPM OSTP Pressure Distribution UNIVERSITY Minnesota Pollution Design Worksheet OF MINNESOTA �:. Control A enc ��ti��-- 12. Select Type of Manifold Connection (End or Center): � End ❑ Center 13. Select Latera(Diameter: 2.00 in Table II Votume of Liquid in 14. Volume of Liquid Per Foot of Distribution Piping: 0.170 Gatlons/ft Pipe �5. Vo(ume of Distribution Piping = �pe Liquid Diameter Per Foot _ [Number of Perforoted Laterals (Line 1)X Length of Laterals (Line 4)X (inches) (Gallons) (Volume of Liquid Per Foot of Distribution Piping(Line 14)] 1 0.045 � X 61 ft X 0.170 gat/ft = 31.1 Gatlons 1.25 O.o7s 1_5 0.110 16. Minimum Dose=Volume of Distribution Piping(Line 15)X 4 2 0.170 3 0.380 31.1 gals X 4 = 124.4 Gallons 4 0.661 mam o plpe` ,_Geanouts '-- ^ � -- � � \� � , � pipe from pump �' Manifold pipe� � , � r lean outs l ' ♦ � Altemate location �� �� of pipe from pump a�tefftate�OCdtip(1 Of i e from Ufi1 Pi e from pum Comments/Speciat Design Considerations: OSTP Design Summary Worksheet UNIVERSITY ' Minnesota Pollution OF MINNESOTA � Control Agency ���,�- Property Owner/Client: Ervin WdChmdn Project ID:� v 11.09.22 s;ce address: Proposed Lot 2 (Site B) 1. AVERAGE DESIGN FLOW: A. Design Flow: 75� Gallon5 Per Day(GPD) Note: The estimated design jlow is consldered o peok j(ow rate including a wjety foctor.For long term perjormance,the overage daily flow is recommended to be< B. Septic Tank capacity: 2250 Gallons 60%oj this value. �, Number of Septic Tanks or Compartments: � Eff(uent Screen&A(arm? NO Type of Soil TreaVnent and Dispersal Area' Type of Distribution* Q Trcrxhes C Bed QQ Mound �AFGrade Q Graviq•Distribution '� prcssurc Distribution-Level Q Pressurc Distribution-Unkvel C,Drip Distrib. Q Nolding Tank� Oth� *Selection Required Benchmark Elev= ft System Type Benchmark Location: ASSUmed �Type I ❑Type II �Type I II ❑Type N [_:Type V Type of Distribution Media: Rock D, Pump Tonk 1 Capacity: �Gallons Pump Tank 2 Capacity: �Gatlons 2. SITE EVALUATION: A. Depth to Limiting Layer: 16 inches 1.3 ft Elevation &Location of Limiting Layer: 9$3.6 ft B. Meosured Percent Land 5(ope: 12.0 % 0.0 Location: � Backslope C. Soil Texture: Cldy LOam � Perc Rate: �MP� D. Soil Hydraulic Loading Rate: 0.45 GPD/ft2 E. Contour Loading Rate 12.0 Gal/ft 3. DESIGN SUMAAARY Trench Design Summary Dispersal Area �ftz Sidewalt Depth �in Trench Width �in Total lineal Feet �ft Number of Trenches � Maximum Trench Depth �in Designers Max Trench Depth in Bed Design Summary Absorption Area �ftz Media Betow Pipe �in Bed Length �ft Bed Width �ft Maximum Bed Depth �in Designers Max Bed Depth �in Mound Design Summary Absorption Area 625 ftZ Bed Length 63 ft Bed Width 10.0 ft Absorption Width 26,p ft Clean Sand Lift 1.7 ft Berm Width (slope 0-1%)�ft Upslope Berm Width 10.0 ft Downslope Berm Width 25,Q ft Endslope Berm Width 15.0 ft Total System Length 93 ft Total System Width 45 ft At-Grade Design Summary Absorption Bed Width �ft Absorption Bed Length �ft System Height �ft Absorption Bed Area �ftZ Upslope Berm Width �ft Downstope Berm Width �ft Endslope Berm Width �ft Sysiem Length �ft System Width �ft Minnesota Pollution OSTP Design Summary Worksheet UNIVERSITY Control Agency OF MINNESOTA ,1��'``� v``` ��, � "'`J Pressure Distribution Summary No.of Perforated Laterats � 3 � Pertoration Spacin8 � 3 �ft Perforation Diameter 7/32 in Lateral Diameter 2.00 �n Supply Pipe Diameter 0.00 in Minimum Dose Votume � 0 � Flow Rate 36 GPM Total Head ��ft Maximum Dose Volume 187.5 Holding Tanks On(y Number of Holding Tanks �� Total Volume of Holding Tanks �� gallons High Levet Alarm? �� 4. Additional Info for Type IV/Pretreatment Design Type of Pretreatment Unit Being Instalted: Organic Loading to Pretrentment Unit =Design F(ow X Estimated BOD in mg/L in the effluent X 8.35:1,000,000 ��Pd X �mg/L X 8.35= 1,000,000= ��tbs BOD/day Calcutate System Organic Loading: (bs. BOD/day:Bottom Area =lbs/day/ftz ��lbs/day a C�ft2= ��lbs/day/ft2 Comments/Special Design Considerations: I hereby certify that I have completed this work in accordance with all applicable ordinances, rutes and laws. Joseph J Olson /v.--�'' """��--�---..__,. 810 01/12/13 (Designer) � (Signature) (License#) (Date) OSTP Mound Design Worksheet _ Minnesota Pollution 0 UNIVERSITY �t' .- Control Agency >1 / Slope OF MINNESOTA �.�,�'_ 1. SY$TEM SIZING: ProjectlD: ���_p9,22 A. Design F(ow(Fiow 8 Soi!- i.A): 750 cPo TABLE IXa B. Soi(Loodtng Rate(Flow 8 Soil-3.C): 0.45 GPD/ftZ �',LOADING RATES FOR DETERMINING BOTTOM ABSORPTION AREA AND ABSORPT�ON RATIOS USING PERCOLATION TESTS C. Depth to Limiting Condition: 1.3 ft Treatment Level C Treatment Level A,A•2,e, D.Percent Land Slope: 12,0 % Percolauon Rate ���� Nound �S°rption �und � Area loading Area Loading � (MPI) Rate Absorption Rate Abwrption E. Design Media Loading Rate: 1.2 GPD/ftZ i ��k=� Rd°° ���ft,� aacio F. Mound Absorption Ratio(Table IXa): 2.60 I<«� - 1 - � IO.t ro 5 1.2 1 1.6 � G. Design Contour Loading Rate: 12.0 GPD/ft ' ;0 t to 5(hne sancl 0.6 2 1 1.6 Table I '�and�oa �ine sa MOUNU CONTUUR IVADINi.RATE4: '�iO�5 0.78 1.5 'I 1.6 Contour ��6to30 0.6 2 0.78 2 l.t9asurod OR Toxtura-dorived loading Ps�c Rato mound absa.ption ratio Rat�. 3i ro a5 0.5 2.4 0.78 2 a6 to 60 0.45 2.6 0.6 2.6 -60rn;� Lp. t.3.2.0. 2.d.2.6 _t. � loi to t20 - 5 0.3 5.3 5�-�2urnpi OR 5.0 cl� >�20 - - - - =�Z����?�' -`��' -�' 'Systems wi[h these values are not Type I systems. Contour Loading Rate(linear loading rate)is a recommended value. 2. DISPERSAL MEDIA SIZING A. Calculate Required Dispersa(Bed Area:Design Flow (1.A):Design Media Loading Rate (1.E)=ftZ If a targer dispersal media area 750 GPD: 1.20 GPD/ftZ = 625 ftZ is desired,enter size: �ftz B. Calcutate Disperso(Bed Width:Contour Loading Rnte (1.G):Design Media Loading Rate (1.E)=Bed Width 12.0 ft = 1.2 �pd/ftZ = 10 ft C. Calculate Disperwl Bed Length: Dispersol Bed Area (2.A):Bed Width (2.6)=Bed Length 625 ft2 : 10 ft = 63 ft D. Select Dispersal Media: E. If using a registered product,enter the Component Length: �i�: 12 = �ft F. If using a registered product,enter the Component Width: �in a 12 = �ft G. Number of Components per Row =Bed Length (2.C)divided by Component Length (4.J) (Round up) � ft : � ft= �components/row H. Number of Rows =Bed Width (2.6)divided by Component Width (4.K)(Round up) Note:CLR of 10.3 ga(/ft results in 9 foot Adjust Contour Loading Rate on Design Summary page until this number is a whole number �de bed. �� ft: � ft= � rows �, Totot Number of Components =Number of Components per Row X Number of Rows � X � �components 3. ABSORPTION AREA SIZING Note:Mound setbocks are measured from the Absorption Area. A. Calculate Absorption Width:Bed Width (2.6)X Mound Absorption Ratio (1.F)=Absorption Width 10.0 ft x 2.6 = 26.0 ft B. For slopes>1%, the Absorption Width is measured downhilt from the upslope edge of the Bed. Calculate Downslope Abwrption Width:Absorption Width (3.A)-Bed Width (2.6)=ft 26.0 ft - 10.0 ft = 16.0 ft 4. MOUND SIZING A. Calculate C(ean Sand Lift: 3 feet minus Depth to Limiting Condition (1.C)=C(ean Sand Lift (t ft minimum) 3.0 ft - 1.3 ft = 1.7 ft Design Sand Lift(optional): �1.7 B. Cdlculate Ups(ope Height:C(ean Sand�ift (4.A)+media depth (1 ft.)+cover (1 ft.)=Upslope Height 1.7 ft + 1.0 ft + 1.0 ft= 3.7 ft U 3::)Inp'r Multi0lier`t able ; Land Slope'� 0 I 2 3 d 5 6 1 8 9 10 I I 12 13 14 15 16 il 18 19 20 21 �2 23 24 25 � UpS(Ope l.:l ?.(�':� 2.Si,i.i3�?.75 2.SE 2.5! 25!i:.�+3 1.�i i.?5�2,?I 2.25 2.21 [.'.'"2.13 2.G4 ?.n� 2.0; Ll�' 1.9? I.ii 1.4i I.it 1.Ev I 1.6? 1.9i i Feim RdiQ 'd:l d.�li 3,&5 's.7i� 3,57 3,a5 3.3i 3.2i 3.1i 3.Oi 2.91�2.65 2.)b 2.10 2.62 2.55 2.�18 ?.�ll 2.?5 2.29 2.2's 2.1$ 2.f3 2.Q8 2.C� t.y8 L9i LB�d$IOpE''v 0 1 2 3 4 $ 6 7 8 9 ;4� II It� 13 Id! I`, 16 17 i$ l9 '10 tl 22 23 24 "15 i I ��C�.','I1SIrDP i 3:l :lk� 3.CS�i.'>'i.'s� i.al 3.5? i.55�3.80 J.iS J.1� 1.24 :.,8 :.59 i45':i.21 i.i`� �E8 6.., S.Ei 1.0: 1..{7 1.i's 3.Jt E.4i 9.� i.n.5[i ', 6?fNRd:'r ;�:i a0('4.!1 d.3s a.5d..lb 5.60 5.2hj5.55 5.fi8 6.25 6.b? l.ta 7.69 E.25 8.92 9.51 t0.t�! 10.45 11.6? 12.�2 !3.19 i3.4i N.Bi 15.6' '6.'.1 Il.�j Seled Ups(ope Berm Mu(tiplier �' (based on land slope): 2.71 (figure D-34) D. Catculate!lpsfope Berm Width:Multip(ier (4.C)X Upslope Mound Height (4.6)=Ups(ope Berm Width 2.71 ft X 3.7 ft = 10.0 ft E. Catculate Orop in E(evation Under Bed:Bed Width (2.6) X Land Slope (1.D): 100=Drop (ft) 10.0 ft X 12.0 % _ �00= 1.20 ft F. Calculate Downslope Mound Height:Upslope Height (4.B)+Drop in E(evation (4.E)=Downs(ope Height 3.7 ft + 1.20 ft = 4.9 ft Select Downstope Berm Mu(tiplier �' (based on land slope): 5.11 (fi�ure D-34) H. Calculate Downsfope Berm Width:Mu(tip(ier (4.G)X Downslope Height (4.F)=Downslope Berm Width 5.11 x 4.9 ft = 25.0 ft I. Calculate Minimum Berm to Cover Absorption Area:Downslope Absorption Width (3.6 or 3.C)+4 ft. =ft 16.0 ft + �4 ft = 20.0 ft J. Design Downslope Berm =greater of 4H and 41: 25.0 ft K. Select Ends(ope Berm Multiplier: 3.00 (usually 3.0 or 4.0) L. Calculate Endslope Berm (4.K)X Downslope Mound Height (4.F)=Ends(ope Berm Width 3.00 ft x 4.9 ft = 15.0 ft M.Calculate Mound Width: Upslope Berm Width(4.D)+Bed Width (2.6)+Downs(ope Berm Width (4.J)=ft 10.0 ft + 10.0 tt + 25.0 ft = 45.0 fc N. Calculate Mound Length:Endslope Berm Width (4.L)+Bed Length (2.C)+Endsiope Berm Width (4.l)=ft 15.0 ft + 63.0 ft + 15.0 ft = 93.0 ft Comments: ' S. MOUND DIMENSIONS p -------------- —-------- �, Upslope (4.D) �o.o v � `, � �� , —1 , � Endslo e (4.L), Uispersal Bed: f2.6 x 2.C? ..� ' v' , � Endsto e (4.Lj , s � ;15.0 i ` 15.D � �__-_ 10x f 63 ; � � I � � � — � � � , � ` V � C � i J O t I � ;� Do�vnslope (4.J) 25.0 � '�------------------------------ --------- Totat Mound Len th (4.N) ' 93.0 4" inspection pipe 18"cover on top Upslope berm �4.D) Downsto e berit� 14.J► 25.0 10.0 12"cover on sides �% - -.. `�`'�� (b" topsoil► i.7 ICtean sand lift (4.�1I (ft ` ------�- � 13 , � - �- ;I:� � Absor tion Width (3.A) PJote: 26.0 For 0 to 1 o slopes, Absorption Wrdth is measured from the 8edequally in both directions. For slopes >1 0, Absorptian w�dth is measured downhill from the upslope ed�e of the BPd. I � I Add ZO%for constructability: 77.5 yd3 x �.z = 93.0 ' I ��yd OSTP Mound Materiats Worksheet UNIVERSITY Minnesota Poliution �� -'��' OF MINNESOTA ,,�-,,_ Control Agency Projed ID: v 11.09.22 A• Calculate Bed (rock)Volume:8ed Length (2.0 X Bed Width 2.6)X Depth =Vo(ume ft' 63.0 ft X 10.0 ft X i.o = 630.0 ft' Divide ft'by 27 ft'/yd'to calculate cubic ards: 630.0 ft' : z7 = 23.3 yd' Add 20%for constructability: 23.3 yd'X 1.Z = 28.0 yd' B. Calculate Ctean Sand Volume: Votume Under Rock bed:Average Sand Depth x Media Widfh x Media Length =cubic feet 2.3 ft X 10.0 ft X 63.0 ft = 1428.0 ft3 For a Mound on a slope from 0-1% Volume from Length=((Upslope Mound Height-1)X Absorption Width Beyond Bed X Media Bed Length) f[ -1) X X ft = Volume from Width=((Upslope Mound Height-1)X Absorption Width Beyond Bed X Media Bed Width) ft -1) X X ft = Tota!Clean Sand Volume: Volume from Length+Vo(ume from Width+Volume Under Media ft' + � ft' + ft' = ft' For a Mound on a slope greater than t% Upslope Vo(ume:((Upslope Mound Height - 1)x 3 x Bed Length)+2=cubic feet (( 3.7 ft -1) X 3.0 ft x 63.0 )t z= 252.0 ftj Downslope Volume:((Downslope Height- f) x Downslope Absorption Width x Medio Length)�2=cubic feet (( 4.9 ft-�) x 16.0 ft X 63.0 )�2= 1948.8 ft' Endslope Volume:(Downslope Mound Height- 1)x 3 x Media Width =cubic feet ( 4.9 ft-1 ) X 3.0 ft X 10.0 ft = 116.0 ft' Total Cleon Sand Volume:Upslope Volume +Downslope Volume +Endslope Valume +Volume Under Media 252.0 ft' + 1948.8 ft' + 116.0 ft' � 1428.0 ft'= 3744.8 ft' Divide ft'by 27 ft'/yd'to calculate cubic yards: 3744.8 ft3 = z7 = 138.7 yd3 Add 20%for constructability: 138.7 yd'X 1.2 = 166.4 yd' C. Calculate Sandy Berm Volume: Tota!Berm Volume(approx):((Avg.Mound Height-0.5 ft topsoil)x Mound Width x Mound Length)y 2=cubic feet ( 4.3 . 0.5 )ft x 45.0 ft X 93.0 )�z= 7881.8 ft' Total Mound Vo(ume-Clean Sand volume-Rock Volume=cubic feet 7881.8 ft' - 3744.8 ft' - 630.0 ft' = 3507.0 ft' Divide ft'by 27 ft'/yd'to calculate cubic yards: 3507,0 ft' : 27 = 129.9 yd' Add 20%for construc[ability: 129.9 yd' x 1-2 = 155.9 yd' D. Calculate Topsoi!Moterial Volume:Tota!Mound Width X Tota(Mound Length X.5 ft 45.0 ft x 93.0 ft x o.5 ft = 2092.5 ft' Divide ft'by 27 ft'/yd'to calculate cubic yards: 2092.5 ft3 : 27 = 77.5 yd3 Add 20%for constructabitity: 77.5 yd; x �.z = 93.0 yd3 OSTP Pressure Distribution UNIVERSITY . � Min�esota Pollution Des�gn Worksheet OF MINNESOTA Control A enc �-''-�'" ProjectlD: v 11.09.22 1. Select Number of Perforated Loterals in system/zone: � --_ _ -- �„...�.,., �,,:.:,.�:�, (2 feet is minimum and 3 feet is maximum spacing) _ .:. _ ��. , 2. Select Perforation Spacing: 3.0 ft � ' s�'' � _ _ < . � Min�muin '/-'�����I�.�:�t������.�.��.���.cl�t'.��i.��i 1"�2"ol r�>ck •r „ .a 3. Setect Perforation Diameter Size 7/32 in _ _ C."c�l rwk 4. Length of Laterals =Media Bed Length-2 Feet. �.������.,�;�,,, �»:' "io n" rc�toc,ron;�.,nn�� �'co, 63 - 2ft = 61 ft Perforation can not be closer then 1 joot from edge. 5• Determine the Number of Perforation Spaces. Divide the Length of Latera(s (Line 4)by the Perforation Spacing (Line 2)and round down to the nearest whole number. Number of Perforation Spaces = 61 ft .- �ft = 20 Spaces 6. Number of Perforations per Loteral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). Perforations Per Latern( = 20 Spaces + 1 = 21 Perfs. Per Lateral Check toble below to verify the number of perforations per(ateral guarantees(ess than a 10%discharye voriotion. The va(ue is double if the a center manifold is used. Maximum Nurt�er of Fe��ations Fer L�eral to Guarantee<:tfl�e i�ischarge Variaro� `,(nth P QfeiG�15 7t32 Inc�Pe�feratio�s Pipe Diarrr�ier llnches) Perfaratiun Spacing Pip?Uameter(Inchesi Fe�farat:on Spaong iFeet? t il; i�: 1 3 IFe�etl 1 1�: 11: 1 3 2 tt� 13 i� 30 60 2 11 16 2! 34 68 2;". 8 12 t5 28 54 2�: 1Q 1�1 2C� 32 h4 3 $ 12 ib 25 5't 3 9 14 19 30 6Q 3'16 lrt�h Perforatians 1'8 lnch Pe�fcrations F'ipe Diar►�ter tincEws) Perfaration Sp�cing Fipe tha!*�eter(inch�sl Pe�crai�o:�Spacn�(Feetl t 11: 1 t� 2 3 (Feetl i t� f tZ 2 3 2 12 18 2b 46 87 2 2t 33 44 14 149 2�� 12 17 1� 44 8n 2i: 24 3Q 4t b9 135 3 12 16 12 37 75 � 2C 19 38 b4 12� 7- Total Number of PerJorations equals the Number of Perforations per Latera( (Line 6)multiplied by the Number of Perforated Laterals (Line 1). 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. ___ _ __ _ 8. Catculate the Squore Feet per Perforation. Recommended value is 4-10 ftz per perforotion. °e`«•"°"°„`""�"`P"`� Does not app/y to At-Grades Hcad(tt) �rforatbn Dtamecer ,,a �,, , �,, Bed Area = Bed Width(ft)X Bed Length (ft) �,O' 0.18 O.it 0.56 0.71 7.5 0.22 0.51 0.69 0.9 10 ft x 63 ft = 630 ftZ =.°° °.� °.5' °.� ,.°` 2.5 0.29 0.65 D.89 1.17 3.0 0.72 0.72 0.98 1.26 Square Foot per Perforation =Bed Area divided by the Tota!Number of Perforations (Line 7). 4.0 0.» 0.83 ,.,3 ,.°7 s.o` o.ai o.93 �.ze i.es � Z � Llvellir�with 31 t6 irKh[o t l�irch 630 ft 63 perforations = 10.0 ftZ/perforations '`�°` OCAO�a(i0M C�vrlling:wi[h 1/e inch peAora[cfc Zleet Otherr,[aMishmen[sand,vS75wich3/16 9. Select Minimum Average Head: 1.� ft inch to 7/a inch DeRoratbn 5 Ittc a�e�`zcadisnments and Y575 wi;n t/B irxh perforations 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation 11• Determine required Flow Rate by multiplying the Toto(Number of Perforations (Line 7)by the Perforotion Discharge (Line 10). OSTP Pressure Distribution UNIVERSITY ,,,- , Minnesota Pollution Desi n W�rk$heet `'�� Control A enc � OF MINNESOTA , - J;;`;,��, 63 Perforations X 0.56 GPM per Perforation = 36 GPM OSTP Pressure Distribution � � UNIVERSITY � Minnesota Pollution Design Worksheet OF �INNESOTA � '�"��� Control A enc - ,��•��� 12. Select Type of Manifold Connection (End or Center): � end ❑ Center _ __ __ 13. Select Latera(Diameter: 2.00 in Tabie II Volume of Liquid in 14. Vo(ume of Liquid Per Foot of Distribution Piping: 0.170 Gallons/ft Pipe Pipe Liquid 15, Volume of Distribution Piping = Diameter Per Foot _ [Number of Perforoted Laterals (Line 1)X Length of Laterals (Line 4)X (inches) (Gallons) (Volume of Liquid Per Foot of Distribution Piping(Line 14)] 1 0.045 �� X 61 ft X 0.170 gal/ft = 31.1 Gallons 1.25 0.078 1.5 0.110 16. Minimum Dose=Volume of Distribution Piping(Line 15)X 4 2 �-��� 3 0.380 31.1 gals x 4 = 124.4 Gallons 4 0.661 mani o p�pe� ,-Cieanouu �--� --'�� i - '�, i i , pipe from pUmp ,' Manitoid pipe, , � , ' lean ouu � � ♦ � AI[emate loca[ion �� ♦� of pipe from pump alternate location of i e from um Pi from um Comments/Speciat Design Considerations: Loqs of Soil Borinqs License#810 Location or Project: Proposed iot 2 Borings made by: Rusty Olson's Soil and Perc testing 1/6/2013 Classification System: AASHO ; USDS�USDS-SCS X ; Unified ; Other Auger used (check two): Hand_X_, or Power , Flight, Bucket or Probe_X_ Boring Number_1_Surface elevation_990.0_ Mottled Soil at_1.5_feet 0"-10" Dark brown loam 10yr3/2 H20 present at X 10"-18" Brown loam to clay loam 10yr4/4 18"-30" Rusty brown clay loam 10yr5/3 Boring Number_2_Surface elevation_990.0_ Mottled Soil at_1.5_feet 0"-10" Dark brown loam 10yr3/2 H20 present at X 1 Q"-18" Brown loam to clay loam 1 Qyr4/4 18"-30" Rusty brown clay loam 10yr5/3 Boring Number_3_Surface Elevation_984.9 Mottled Soil at_1.5 feet 0"-10" Dark brown loam 10yr3/2 H20 present at_X_ 10"-18" Brown loam to clay foam 10yr4/4 18"-30" Rusty brown clay loam 10yr5/3 Boring Number 4_ Surface elevation_984.9_ Mottled Soil at_1.3_feet 0"-10" Dark brown loam 10yr3/2 H20 present at_X_ 10"-16" Brown loam to clay loam 10yr4/4 16"-30" Rusty brown loam to clay loam 10yr5/3 Boring Number 5_Surface elevation_987.7_ Mottled Soil at_1.3_feet 0"-10" Dark brown loam 10yr3/2 H20 present at_X_ 10"-16" Brown loam to clay loam 10yr4/4 16"-30" Rusty brown loam to clay loam 10yr5/3 Boring Number 6_Surface elevation_982.7_ Mottled Soil at_1.3_feet 0"-10" Dark brown loam 1 Qyr3/2 H20 present at_X_ 10"-16" Brown loam to clay loam 10yr4/4 16"-3Q" Rusty brown loam to clay loam 10yr5/3 Percolation Test Data Sheet Lic.#810 Percolating test readings made by: Rusty Olson's Perc. starting at 10:39 P.M. On 1/07/13 Location: Proposed tot 2 Hole number: 1 Date hole was prepared: 1/06/13 Depth of hole bottom_12"_ inches, Diameter of hole 6" inches. Soil data from test hole: Depth, inches Soil texture 0-10" Dark Brown Loam 10yr3/2 10"-12" Brown loam to clay Ioam 10yr4/4 Method of scratching side wall: Knife Depth of gravel in bottom of hole 2 inches: Date of initial water filling 1/06/13 depth of initial water filling 12 inches above the hole bottom Method used to maintain at least 12 inches of water depth in hole for at least 4 hours Automatic Siphon Maximum water depth above hole bottom during tests 6 inches Time Time Depth Drop in H20 Perc Rate 11:04 11:34 6" 5.5 5.4 11:41 12:11 6" 5.5 5.4 12:12 12:42 6" 5.5 5.4 AVERAGE PERC. RATE 5.4 MPI Percolation Test Data Sheet Lic.#810 Percolating test readings made by: Rusty Olson's Perc. starting at 10:39 P.M. On 1/07/13 Location: Proposed lot 2 Hole number: 2 Date hole was prepared: 1/06/13 Qepth of hole bottom_12"_inches, Diameter of hole 6" inches. Soil data from test hole: Depth, inches Soil texture 0-10" Dark Brown Loam 10yr3/2 10"-12" Brown loam to clay loam 10yr4/4 Method of scratching side wall: Knife Depth of gravel in bottom of hole 2 inches: Date of initial water filling 1/06/13 depth of initial water filling 12 inches above the hole bottom Method used to maintain at least 12 inches of water depth in hole for at least 4 hours Automatic Siphon Maximum water depth above hole bottom during tests 6 inches Time Time Depth Drop in H20 Perc Rate 11:05 11:35 6" 5.5 5.4 11:40 12:10 6" 5.5 5.4 12:13 12:43 6" 5.5 5.4 AVERAGE PERC. RATE 5.4 MPI Percolation Test Data Sheet Lic.#81 Q Percolating test readings made by: Rusty Olson's Perc. starting at 10:39 P_M. On 1/07/13 Location: Proposed lot 2 Hole number: 3 Date hole was prepared: 1/06/13 Depth of hole bottom_12"_ inches, Diameter of hole 6" inches. Soil data from test hole: Depth, inches Soil texture 0-10" Dark Brown Loam 10yr3/2 10"-12" Brown loam to clay loam 10yr4/4 Method of scratching side wall: Knife Depth of gravel in bottom of hole 2 inches: Date of initial water filling 1/06/13 depth of initial water filling 12 inches above the hole bottom Method used to maintain at least 12 inches of water depth in hole for at least 4 hours Automatic Siphon Maximum water depth above hole bottom during tests 6 inches Time Time Depth Drop in H20 Perc Rate 11:06 11:36 6" 4.7 6.4 11:09 12:09 6" 4.6 6.5 12:14 12:44 6" 4.5 6.7 AVERAGE PERC. RATE 6.5 MPI Percolation Test Data Sheet Lic.#810 Percolating test readings made by: Rusty Olson's Perc. starting at 10:39 P.M. On 1/07I13 Location: Proposed lot 2 Hole number: 4 Date hole was prepared: 1/06/13 Depth of hole bottom_12"_inches, Diameter of hole_6"_inches. Soil data from test hole: Depth, inches Soil te�ure 0-10" Dark Brown Loam 10yr3/2 10"-12" Brown loam to clay loam 10yr4/4 Method of scratching side wall: Knife Depth of gravel in bottom of hole 2 inches: Date of initial water filling 1/06/13 depth of initial water filling 12 inches above the hole bottom Method used to maintain at least 12 inches of water depth in hole for at least 4 hours Automatic Siphon Maximum water depth above hole bottom during tests 6 inches Time Time Depth Drop in H20 Perc Rate 11:07 11:37 6" 3.5 8.6 11:08 12:08 6" 3.3 9.1 12:15 12:45 6" 3.3 9.1 AVERAGE PERC. RATE 8.9 MPI