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=���4:;_ OSTP Pressure Distribution <br /> ` UNIVERSITY , <br /> Minnesota Pollution Desi�n Worksheet OF MINNESOTA <br /> Control A nc +�"�� <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Laterals in system/zone: � _ _ <br /> (2 feet is minfmum ond 3 feet is maximum spacinq) <br /> ��h�w�.�.,«M.�,,.. <br /> � . �,� _ �f-� _ <br /> 2. Select Perforation Spocing: 3.0 ft '�`' ' ' �' '2'So°"'"�` ; .- <br /> �� '/."perlotatiorn spaaW:{� n �Mini�nuin I�----.--+ <br /> upa 2"ol mck 1.2^ <br /> 3. Select Perforation Diometer Size 7/32 in _ _ <br /> 6'o(rock <br /> 4. Length of Loterals =Media Bed Length-Z Feet. Pe�������������n:�,•-��'/+" Perforation spacin9:I to 3' <br /> 63 - 2ft = 61 ft Pe�foration can not be claser thert 1 foot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Latera(s (Line 4)by the Perforvt�on Spvcfng (Line 2)and <br /> round down to the nearest whote number. <br /> Number of Perforation Spoces = 61 ft + C�ft = 20 Spaces <br /> 6. Number of Perforntions per L.QterQt 1s equal to 1.0 ptus the Number of Perforation Spaces (Line 5). <br /> Perforations Per LAternl = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check table below[o verify the number of perforations per(atera!guorontees less than a 10%discharge variation. The value is <br /> double if the a center manifold is used. <br /> ldauimt�r►ti�xnber of PerForatia�s Per t.ateral to Guarar�ee<tqli piuh�rge Yariatiac� <br /> !�[rx P aahons 7l32 Inch PerForatiatis <br /> Pe�faration Pipe Diameter tinchesl Perforaoon Spacing Pipe Diameter Nruhes) <br /> Spa�(feet) t 11� 1sh 2 3 fFeet► t ti� tvt 2 3 <br /> 2 10 13 16 30 60 2 11 16 21 34 b$ <br /> 1� 8 12 16 28 54 1�: 10 14 24 32 6# <br /> 3 8 92 4d 25 52 3 9 �4 14 30 b0 <br /> 3!161nch Perforatia�s 1!8 Inch Perforati�s <br /> Pipe Diameter Iinches) Prerforation Spacing Pipe Diameter linchesl <br /> Perfaratoon5pacinglFeet) 1 1N� f�t 1 3 (Fee#1 1 11�c 1�# 2 3 <br /> 2 12 1S 26 �b 87 2 21 33 �4 7� 1�9 <br /> Z�4 12 tT 24 #0 80 2�. 10 30 41 69 i35 <br /> 3 t2 1b 21 3T 75 3 10 24 38 N 128 <br /> �• Totol Number of Perforotions equals the Number of Perforotions per Lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1}. <br /> 21 Perf. Per Laterat X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> _. .-- .__ .._ ...___�------__�_._..._ __ _. <br /> 8. Calculate the Square Feet per Perforation. Recommended value ls 4-10 ft Z per perforation. "r'°�"°^°f�M���6P"� <br /> Dces not app(y to At-Grodes ,�,a „� "°`'«"'°"D11nOeir <br /> � y. ,�. ,��: ,i. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) �,� o.�a a.�� o.ss o.�a <br /> i.S 0.22 0.57 O.i9 0.9 <br /> 10 tt x 63 ft = 630 ft2 Zo> o.� O.S9 0.� ,.o. <br /> 2.5 0.19 0.65 O.B9 7.17 <br /> a.o o.�Z o.�2 o.ss �.xs <br /> Square Foot per Perforation =Bed Area divided by the Tota(Number o/Perforatlons (Une 7). +.o 0.77 o.aa ,.,3 ,..� <br /> 5.0 0:41 0.97 1.26 1.63 <br /> 630 nz .- 63 perforations = 10.� ft2/perforations ���'� oertoratb�rs�h 3it61nch to t/a irch <br /> DwelHnqs wl[n i/a inch perforatb�e <br /> 9. Select Minimum Average Head: 1.0 ft =�»� ahe�e+taWkMnenes and MSTS vAah 1/�6 <br /> inch to i I4 irKh peAoratbro <br /> 5 fxc a�r eStaOlhhmM[s anE NSTS wlt�1/!iritM <br /> peADrDtbns <br /> 10. Select Perforatlon Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required Flow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br />