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• _ OSTP Pressure Distribution :;�2 �.�, <br /> UNIVERSITY �°�` <br /> Minnesota Pollution Desi�n Worksheet OF MINNESOTA �: ` �'' <br /> Contro)A enc �v�� <br /> Project ID: v 11.09Z2 <br /> 1. Select Number of Perfarated Laterols in system/zone: �3 � ____ <br /> un..��w.�x�M�dw <br /> (1 feet�s minfmum and 3 feet is moximum spncfng) _ _ � <br /> .. _ , ,�_{ <br /> �� �` , ` ' <br /> 2. Setect Perforahon SP�c►nB= 3 0 ft ,Z• . . ,Z`S '� � - <br /> � <br /> �.i , <br /> Mimmum <br /> ..�•/.'perforatiom spaced 3'aya� 1'-Y"ot�ack� � � 12" <br /> 3. Select Perforation Diameter Size 7/32 in _ _ <br /> 6'of rock � . . <br /> 4. Length of Laterals =Media Bed Length-2 Feet. �a����u=j�:��•-_��,.� �no,a�.���,�:Z•�0 3• <br /> 63 - zft = 61 ft Perjorat�on con not be do�er then 1 foot jrom edge. <br /> 5• Determir�the Number of Perforation Spaces, Divide the Length of Loterals (Line 4)by the Perforation Spncing (Li�2)and <br /> round drnwn to the nearest whole number. <br /> Number of Perforallon Spaces = 61 ft = �-�ft = 20 Spaces <br /> 6. Number of Perjorotions per Loterol is equal to 1.0 plus the Number of Perforation Spoces (Line 5). <br /> Perforotions Per Lateral = 20 Spaces + 1 = 21 Perfs. Per lateral <br /> Check tab(e below to verify the number of perforations per loternl guarantees less thnn a 10%dfscharge variatfon. The volue is <br /> doubte if the 4 center manifold is used. <br /> Maximtan Mtrnbe�r o#Perforatiau Per Laterat ba Guarantee<1t!!6 Qisthauge Yariatiot+ <br /> l.Irx P orahans 7/32 Inch Perforations <br /> Perforation Spacutg(,FeeE} Pipe Diameter(Inct�es? Perforation Spacing Pipe D+arnete�r(1nc.hes) <br /> f 116 ti2 Z 3 iFeet) 4 IS+� t� 2 3 <br /> 2 10 13 !8 3d b0 2 if 16 21 3� 6$ <br /> 21� 8 12 16 28 54 2Yt 10 14 2Q 32 64 <br /> 3 B 12 16 35 5I 3 9 14 19 : 30 60 <br /> 3t 1 b Inch Perfora�ions 11$Inch Perforations <br /> Petforation Spating(Feet1 �Pe Diameter llnches) Perforation Spacing Pipe Oiameter(lnches) <br /> f 11� 1�i 2 3 IFe�et} t t� 1�t 2 3 <br /> 2 ' 12 18 26 4b $7 2 21 33 4� 74 1#9 <br /> �1� 12 i7 24 44 $0 2S� 20 3Q 4t 69 135 <br /> � 12 16 22 37 75 3 20 29 �8 64 t2$ <br /> �• Total Number of Perforations equals the IVumber of Perforations per Laterol (line 6)multiplied by the Number of <br /> Perforeted Lnternts (Line 1). <br /> 21 Perf. Per Laterat X �Number of Perf.Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Squnre Feet per Perforation. Recommended value is 4-10 ft2 per perforation. "�^°n"onD��6P14> �� <br /> Does not apply to At-Grades ""�""°"O1ane°" <br /> H.w aa <br /> 'i. 'i,. 'r,: 'i <br /> BC+d AreO = B@d Width(ft)X BEd L.2ngth(ft) ,.o- o.,s o.a, o.ss o.ss <br /> 1.S 0.22 O.St 0.69 0.9 <br /> 10 tt x 63 ft = 630 tt2 Zw o.� o.s� o.a ,.o, <br /> 2.5 0.29 0.65 0.89 t.t7 <br /> � 3.0 O.12 OJ2 0.98 1.29 <br /> Square Foot per Perforation =Bed Area divided by the Total Number of Perforatfons (Line 7). •.o o.r o.�s ,.,a ,..� <br /> s. o.n o.» ,.zs ,.ss <br /> 1 foot �����h 3/t61ncA m 1/4 tneh <br /> 630 ftz .- 63 perforations _ 10.0 ttz/perforations �w•« <br /> ����,,„8���,o�«� <br /> 2�K� Other eseatlhhmm[s eM htSTS wkh S/�6 <br /> 9. Select Mfnimum Average Heud: 1.0 ft ,Kh�,,,,;,��,�.�„�p,� <br /> 5��� Ocher acablhhmmts aml MSTS wkh t!8 inch <br /> pertorstb1s <br /> 10. Select Perforatlon Discharge (GPM)based on Table III: 0.56 GPM per Pertoration <br /> 11• petermine required Flow Rote by multiplying the Totul Number of Perforadons (Line 7)by the Perforotion Discharge (Line 10). <br />