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� _ OSTP Pressure Distribution Y��,;��� <br /> � , UNIVERSITY � ° �` <br /> Mi�nesora Poilution Des�gn Worksheet OF MINNESOTA �;.� . r ,� � <br /> Control A enc •� �, <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number of Perforated Laterals in system/zone: � _______ <br /> (2 feet is minir►wm�ond 3 feet is maximum spocing) ��'"�""":.""'�" <br /> �� _ .. � ' 'r Y� <br /> 2. Setect Perforotion Spacing: 3.0 ft ,�.`�. • ';�--5oi1 �"`• ' ' � - <br /> -� t - <br /> MlnimWn <br /> `/.'pCrlwatioM syated 3'aP.xl 7'-1'ol rtxk� � � t2' � <br /> 3. Setect Perforation Diameter Size 7/32 in _ _ <br /> � �6'�ofrock � <br /> 4. Length of Laterals =Media Bed Length-2 Feet. ���.,i+����,:�,.-�o'!." Perloratbn spacinq:2'to 3' <br /> 63 - 2ft = 61 ft Perforation can not be closer then 1 foot from edge. <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spoces = 61 ft = �ft = 20 Spaces <br /> 6. Number of Perforations per L.ateral is equal to 1.0 plus the Number of Pert'oration Spaces (Line 5). <br /> Perforations Per Latera! = 20 Spaces + 1 = 21 Perts. Per Lateral <br /> Check table be(ow to verijy the number of perforations per laterat guaruntees less than a 10%dfisclwrge variotion. The vo(ue is <br /> double if the a center nwnifold is used. <br /> Maximum Mennb.v o#P�rforatiur�Fer Laterai to Guarbntee<fD96 flischarge Yariatia� <br /> ,,Enc P oraboaz 7/321nch Perforations <br /> Perforatio�SpMinB(Feet) �PQ Diameter(tntE�s1 Perfa�ation Spacing Pipe Diameter(inches) <br /> f 116 1Yt 2 3 (Fee!) t t1� 1V: 1 3 <br /> 2 �0 13 18 30 64 2 1t 16 21 34 b8 <br /> �� 8 12 1b 28 5-t 21h 10 14 10 32 b4 <br /> 3 � 12 16 Z� 52 3 9 14 14 30 60 <br /> 3�'161nct►Petfaratians iB Inch Perfarations <br /> Peiforatron Pipe E?ia+reter r#nches? PerforaEion Spacing Pipe Diameter(Inches) <br /> spacir,g IFeet) <br /> 1 115 t�t 1 3 fFee!) 1 t+k it; 2 3 <br /> 2 1� 18 26 9b 87 2 21 33 44 T4 149 <br /> 2ti': 11 17 24 4(? �0 2fh 2Q 3Q 4 t 69 135 <br /> 3 1$ 16 22 37 75 3 20 29 38 b� 128 <br /> 7• Totol Number of Perforat�ons equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of <br /> Perforated Lnterals (Line 1). <br /> 21 Pert. Per Lateral X �Number of Perf. Laterals = 63 Total Number of PerF. <br /> �—_�__.____.___�__---------- <br /> 8. Calculate the Square Feet per Perforation. Recommended va(ue is 4-f0 ft 2 per perforvtion. °Kfo^"°^D1���6P"'� <br /> Does not appl y to At-Grades ��`rt� Ao.ro.+�oi...a. <br /> ��� ��� r��� ��� <br /> Bed Area = Bed Width(R)X Bed Length(ft) <br /> LO' OJ6 O.N � 0.56 0.7t <br /> 1.S O.I2 O.St O.f9 0.9 <br /> 1� ft X 63 ft = 630 ftZ zo� o.�a oss o.m �_w <br /> zs o.z9 o.as o.n �.n <br /> s.o o.az o.sz o.so �.re <br /> Squore Foot per Perforotion =Bed Area divided by the Tota!Number of Perforations (Line 7). ..o 0.3� o.� ,.,a ,..� <br /> s. o.a� o.n �.:s �.as <br /> 630 ft2 .- 63 perforations = 10.0 ft2/perforations ���� p�,��h 3/16 inc�tv t/4 inch <br /> Dwellf��with t/d inch pMorallo� <br /> 3fee[ OCBeratadk�mentsaMM575wfcA3l�6 <br /> 9. Select Minimum Average Heod: 1.� ft �ncn w va�ncn oertoratb�s <br /> 5 teec aher esublkNnents aiW u5T5 with t/8 incA <br /> pMaatiau <br /> 10. Select Perforotion Disclwrge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required Ftow Rcte by muttiplying the Total Number of Perforations (Line 7)by the Perforotion Dixhorge (Line 10). <br />