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1100 Pine View Drive - 28-118-23-42-0010
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septic design/subdivision purposes only
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Last modified
8/22/2023 4:25:38 PM
Creation date
7/5/2018 12:48:26 PM
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Template:
x Address Old
House Number
1100
Street Name
Pine View
Street Type
Drive
Address
1100 Pine View Drive
Document Type
Septic
PIN
2811823420010
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� _ OSTP Pressure Distribution <br /> �� UNIVERSITY �` ��� .� <br /> Minnesota Pollution Desi�n Worksheet OF MINNESOTA �" � `� <br /> Control A enc �� ,.�� <br /> ProjectlD: v 11.09.22 <br /> 1. Select Number oj Perforated l.aterols in system/zone: �3� _____ <br /> Insub�M.<um Iwn <br /> (2 feet is minimu�and 3 feet is moximum spocing) � <br /> �� �� �_ � ' _ �r 7 <br /> ��Z�•�.• ,. • •.. �Z`sou<wer � � <br /> 2. Select Perforotion Spocing: 3.0 ft -; �. "' - <br /> . '�,'M`rtoratin.n WMM 3'aP� � Mi:MnumIXk . � .. iZ�. <br /> 3. Select Perforation Dlameter Size 7/32 in _ _ <br /> � � 6'o(rock � . . . <br /> 4. Length of Laterots =Media Bed Length-2 Feet. �,,�,,,��^���w:�,.-�a��,- ��+�,a«o���.�:2��0 3• <br /> 63 - 2ft = 61 ft Perforation cQn not be closer then 1 foot from edge. <br /> 5• Determine the Number of Perforotion Spaces. Divide the Length of L.aterals (Lir�4)by the Perforotion Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of PerjoraNan Spaces = b1 ft .- ��ft = 20 Spaces <br /> 6. Number of Perforutions per Loternt is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Latera! = 20 Spaces + 1 = 21 Perfs. Per Laterat <br /> Check tabte below to ver�jy the number of perforallons per latero!guarantees less than o 10%discherge v�oriation. The vatue is <br /> doubie ff the a center manifold is used. <br /> Mlaydm�►Nutnber a#Pecfaati�s Per Latea�a!ta Guaratrtee<10%ascharge Van�n <br /> 'i4lnth P aanons 7/32 Inch Perforatior� <br /> Perforation Sp�cing IFeet1 �Pe D+ameter(inch�es) Perforatiw►Spacir� Pipe D'+ame#er flnches) <br /> f 1� 1Yt 1 3 1Feet� t 11G tYt 2 3 <br /> � fA 13 f8 3t1 b0 2 it 16 21 34 6$ <br /> 2� 8 12 16 28 5� 2�i 10 14 20 32 b4 <br /> 3 8 12 ib 23 52 3 4 14 19 30 b0 <br /> 3 f 16 Irxfi Ferforations 1/�Inch Peiforat3ons <br /> Perforation Spacirtg IFeet) P+pe Diarrseter{inches� PerForation Spa�cir� Pipe Diameter(tnthes) <br /> t tc;i !�: 2 3 (feet) t i�i i1� 2 3 <br /> 1 12' t8 26 4�i 8T Z 21 33 M 74 149 <br /> 2}`i 12 17 24 40 $0 21� 20 3Q 4t 69 135 <br /> 3 12 16 22 37 75 3 20 19 3$ b4 128 <br /> �• Tota!Number of Perforatlau equals the Number of Perforations per LaterQ! (Line 6)multiplied by the Number of <br /> Perforated latera[s (Line 1). <br /> 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Catculate the Square Feet per Perforation. Recommended value is 4-f0 ft2 per perforotion. P°�'°"MonD1�'14P"'� � <br /> Does not appl y to At-Grades „,,,��t� "°"°""°"D1n10er <br /> �. '��. '��� '. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) <br /> �/.0' O.IB � �O.s1 . O.SS .�OJ4. <br /> 1.5 �.52 O.St 0.69 0.9 <br /> 10 ft x 63 ft = 630 ft� Z°' °:� °.S' °.'° ,.°. <br /> zs o.n o.ss o.ev i.n <br /> �A � OJ2 OJ2 . 0.1Y� L7A <br /> Square Foot per Perforet3on =Bed Area divided by the Total Number of Perforations (Line 7). •.o o.» o.o ,.,z ,.a <br /> 5.0` 0.�1 0.93� t16 � /.6S. <br /> Dwetlilgs wi[h 3/16 aich to 1/4;nch <br /> 630 ft2 .- 63 perforations = 10.0 ft2/perforations '`°°` ��•�� <br /> Owelli�wfth t I8 inch perforatb�n <br /> c. Z leet Ocher estaMhNnmts and M5T5 vAlh 3!16 <br /> 9. Select Minimum Average Head: 1.0 1 l irch to V4 inch peRoratiwn <br /> 5 teec ���b��s aMMS'fS wich 1/8 krcA <br /> 10. Select Perforation Dischorge (GPM)based on Table III: 0.56 GPM per Perforation <br /> �1• Determine required Ftow Rate by multiplying the Totat Number of Perforotions (Line 7)by the Perforation Discharge (Line 10). <br />
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