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1994-006114 - septic
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1200 Phillips Drive - 27-118-23-32-0009
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1994-006114 - septic
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Entry Properties
Last modified
8/22/2023 4:20:08 PM
Creation date
7/5/2018 10:36:55 AM
Metadata
Fields
Template:
x Address Old
House Number
1200
Street Name
Phillips
Street Type
Drive
Address
1200 Phillips Drive
Document Type
Septic
PIN
2711823320009
Supplemental fields
ProcessedPID
Updated
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' PR�SSL_m_�DIS'�z_IBt�ON YSTEM � �F��T�� � A PERFORA7ED LATEWIL <br /> wou cov.r <br /> � 1. Select number of perforated laterals 3 T.�.� j <br /> ;;�r';:.�:...... . .....:r•;.�;:a.•�• <br /> r,;: ' �qy�N GwNttllt FoOrk(at bu <br /> ar, .��anp SaM taYv :Yrci�loyr of Mp ar drcr wwN <br /> 2. Select oration s acin .�• O fee� ''�� - �:'����•��*� <br /> P� P 8=--� <br /> ' ����Horhouauy <br /> c <br /> 3. Since perforations should not be placed closer than 1 ft.to ������d Req � .� o��;;a°Edqi <br /> the edge of the rock layer(see diagram),subtract 2 ft.from ' � '�•� � �" ' ��,,,;;�;;•,.�,�.,., <br /> the rock layer length. .` �"°•5ane�•y �°"�•°'`°�"� <br /> � ��j��-7 i�t.= o.S fee� ���� r.�.a,s���.� <br /> e.ex.�«�n,s,.,�,y., <br /> 4., Dete;mine the number of spaces between perforations. ��,� <br /> Divide the length above by perforation spacing and round � a.�,.� - � <br /> down to nearest whole number. � � � �"� �"� <br /> 1.Oa 0.56 0.74 <br /> Length perF spacing=�•S ft.+ 3 ft. __� spaces 2.Ob 0.80 1.04 <br /> (3) (2) �.vx�:���r�wy� <br /> 5. Number of perforations is equal to one plus the number of b.Use fa all otha a�;qa� <br /> perforation spaces. <br /> Z� spaces+1 = 2/ perforations/lateral Mlate�i-al�tonuar ulnteeQ 109G dis�chaerforations pe <br /> Sa rge variation <br /> Perfocation <br /> 6. Multiply p�rrforations per lateral by number of laterals to 5���g 13; � 2 <br /> � get total numb�of perforations. . � . 2.5 14 18 . .28 - <br /> .� x 2/ �3 erforations. � �" 13 � 26 - <br /> '"`�' �`""� P 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying 4.0 11 15 23 <br /> number of perforations by flow per perforation 5.0 1� 14 � <br /> � X��= y7�m. •��.T �a.��.�►�M.ti. <br /> � <br /> 8. If laterals are connected to header pipe as shown on upper "` <br /> example,to select minimum required lateral diameter;enter ���" <br /> table with perforation spacing and number of perforations ,,.•��''� "�"` <br /> per lateral. Select minimum diameter for ��"`"'� <br /> ' perforated 1�►teral= 2 inches. <br /> , �������� <br /> .�,,.�.....,�.....�.o <br /> �wwNrw wMs.� /�'f� <br /> 9. If perforated latesal sy�tsac►is attachad to manifold pips n�as ��'''� "' "'�� <br /> the center,ld�ver diagraat,perfo�ated lateral length and .•.�,•,,�..,.• . ' <br /> number of perforations per lateral will be approxintately one ••� <br /> half of that in step 8. Using these values,select minimum ,... ,, .- <br /> diameter for perforated lateral= inches. ,o•'"���. „ <br /> �'''" . . . , . <br /> . • , . . <br />
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