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�� MOUND DESIGN WORKSHEET TFF� �Ri(/�S <br /> � (For Flows up to I200 gpd) <br /> A: FLOW �a s�.ti�FwM�ct��nar es� <br /> Estimated� <br /> or measured gx 1.5= gpd. �°i�,�,,, �I '�Yr�u �m �'v — <br /> s 30o xu �so � <br /> 3 450 300 238 •r <br /> B. SEPTIC TANK LIQUID VOLUMES 4 60o s�s as6 ,�, <br /> /ZSO gallOns f /DDO G,��c o.✓ Z.vo ?./,�.1< 6 �o su si � <br /> oaa <br /> f /2S0 �a/Ion Pu�+�in' fa+n k s i� 6�is i� �''m" <br /> C. SOILS(refer to site evaluation) ,� �� <br /> 1. Depth to restricting layer= .� 6 inches NB� �, � . <br /> 2. Depth of peroolation tests= _ /� inches `'"'�' <br /> 3. PercolaEion rate ��1• 8 mpi '3«`i` i.o o i•'wsso <br /> 4. Land slope �%i % ;a 8 � � � <br /> ova 9 See Gj.G(i (:1S) <br /> D. ROCK LA,YER DIlV�IIVSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required azea of rocic <br /> layer:A x 0.83= <br /> 7S0 gpd x 0.83 sq.ft./gpd= 61 S sq. ft. <br /> • 2 Select width of rock layer(10 feet or less)_ /o ft. <br /> 3. Length of rock layer=area+width= , IZock Bed <br /> 6 ZS sq.ft.+ /v ft. _ �Z.S ft. ,.,�.:ti,.�...ti.�.^�:�. .. <br /> r%•I I•!.�•�.r.f.�.r•f.f.�•j.j. <br /> ti•ti•\.ti•ti•��.ti•ti.ti•t.�•ti•�.��ti <br /> t•f.!•I•�.!•t.t•1 I•t•t•I•t•I•!. <br /> �.ti•�.�.�.ti.�.ti•ti.�.ti.�.�.�.ti.�.ti �dth 510 ft. <br /> �•1•I•�•J•t•l.I.r t•/•I•�•�•f•r• <br /> ti•ti•�•�•�•�•�•ti•ti.�.�•�•�•�•ti•�•ti <br /> � h�•f.rN•f•r•f.r.�.�•r.f.j•f•r• <br /> E. ROCK VOLUME �— �sw <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 62 s sq.ft.x � f�. _ �ZScu.ft. . <br /> 2 Divide cu.f�by 27 cu.ft./cu.yd.to get cubic yards; <br /> �zS cu.f� +27= L.�./cu.yd. <br /> . 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> . � 1.3•/cu.yd.x 1.4 ton/cu.yd. _�tons. <br /> F. ADSORPTTON WIDTH �b� ao�w�aws�, ybk <br /> 1. Percolation rate in top 12 inches of soil is /S mpi P�„�,,��,�„� �� �•• <br /> ����, Soilrexcure �.� M"d`.er,� <br /> �2 Select allowr�ble soil loading rate from table; Faster than Oa �sana 1 so � <br /> c�1E • o gpd/fi� oa co5 sana 1.2o i.00 <br /> . 0.1 to 5 Fine Sand" 0.60 2.00 <br /> . - - .- . - . 6 to 15 ndy Loam 0.79 152 <br /> 3. Calculate adsorption width ratio by dividing rock layer 3i a a�s siic[.o�am o� 2.� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; '��� c�a t,oaa► o.as 2b� <br /> 1.20 d/ft2+ 0,6o d/ft2= 1. D 61 t012o �1ay o24 5.00 <br /> $p $P Slower than 120 Cla <br /> "Sa1 lavin`509i ar mare d fisr or vey 8�r aand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsarption width; � <br /> 2,o x /� ft= Z� ft <br /> � . . . . � . , , <br />