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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) . <br /> ' A. FLOW Estimated Sewage rk,ws in Gallons pa day <br /> /// (glad) <br /> Estimated ti_CO gpd (see pages D-7 or 1-3, 4, 5) Number Ty <br /> or measured gpd x 1.5 = - or Type 1 Type II Type III Iv <br /> Bedrooms <br /> 1 2 300 225 IRO <br /> B. SEPTIC TANK LIQUID VOLUMES 3 430 300 2111 <br /> 4 600 375 256 :Z.D - i p n U gallons (see pages C-3 or C-5) 5 950 45°3 i 2 T "r.L <br /> 7 1050 600 370 us <br /> R 1200 675 40K trams <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer = 1 ?. .1ti 1 r•-? inches Septic Tank Cap.cta•,M a•11...• <br /> .vmnc.of Minimum Lpu <br /> ual (.wd r• <br /> caiay.i4ri <br /> 2. Depth of percolation tests = I T inches 1,......„,. C� air°�d&spool <br /> 3. Percolation rate . 1 ?•-- mpi 2or km. <br /> 7501123 <br /> «. tan (inn <br /> 223(1 151114. Land slope -J) 6 <br /> �•4 or 6 bats 3 w <br /> mer V <br /> D. ROCK LAYER DIMENSIONS -- <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> 7--) _/C gpd x 0.83 sq. ft./gpd = 3,', sq. ft.-!- tD9a'-!s o�t <br /> 2. Select width of rock layer (10 feet or less) = /D ft. <br /> • <br /> 3. Length of rock layer = Area y Width = <br /> - ' O sq. ft. 1 / 3 ft. = Lj1 ft. Rock Bed _ <br /> . ., :.., ti••. ..••.•ti••.•. :.ti.ti.•,..t�dth 510ft <br /> •••J•.•J•r•r•r•,•r•••r•J••••J•J I <br /> E. ROCK VOLUME 1--- Length -- 4 <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 14 19 ,sq. ft. x/,:S' ft. = L30cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; . <br /> q1 cu. ft. + 27 = /..1_ cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> /4 cu. yd. x 1.4 ton/cu. yd. = a A tons. <br /> F. ADSORPTION WIDTH 4L.1.....4 L r ,; <br /> Absorption Width Sizing'1'uble <br /> 1. Percolation rate in top 12 inches of soil is l 3 T, mpi <br /> Percolation Rate I Gallons Rano of <br /> 2. Select allowable soil loading rate from table on page E-; in Minutes per Soil Texture liter day per AMr*yaion rid! <br /> gPd/f Inch(MVI, lagwre font M Roel1111,ays <br /> . t 5 W <br /> 2 <br /> 3. Calculate adsorption width ratio by dividing rock layer Fars.1 • C and Sand ---b"� 1.20 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 0.1t5" seSLoam and'''• <br /> 0.60 2.006 to 0.79 <br /> 1.20 gpd/ft2 2= 1610 10 Loam 0.60 2.00 <br /> 1 .ys gpd/ft -67 311045 Silt Loam 0 2.40 <br /> .50 <br /> Check this value on pageE-l6. . 4610 fin clay Loam 015 267 <br /> 60 10 12(1 Clay 0.24 3.0u <br /> 4. Multiply adsorption width ratio by rock layer width to get s17;;;;A" Clay - --• <br /> required adsorption width; <br /> __ „,.) x /0 ft =016.7 ft <br /> 1 . <br />