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• MOUND DESIGN WORKSHEET <br /> , , (For Flows up to 1200 gpd) <br /> A. FLOWEstimated Sewage Flows in Gallons per day <br /> ( pd) <br /> Estimated /;,0 o gpd 3 1,, -cs, u 00 s,= e _--v.,. 1)n t ,._k: <br /> Nunber 'IN/pe I Type n lave m <br /> Bcdrosfaug <br /> or measured x 1.5 =_.:_---_-__gpd. <br /> 280 <br /> 50 300 211$ 6051 <br /> B. SEPTIC TANK LIQUID VOLUMES „,g <br /> ba <br /> 600 375 256 vawa <br /> 65 750 750 450 294 ytpoe <br /> - f j D gallons r+^• n t 7 1050 6C0 370 Tbier <br /> I 8 � 1200 I 675 408 coco <br /> lumns <br /> C. SOILS (refer to site evaluation) Sq.*11449o,444y,Ye,yo.,, <br /> 1. Depth to restricting layer= -,.L..1. inches feet 1A1402 a r <br /> 2•44044 of /Claims Liquid Liquid aqactry 444i MIA dLopaRIA <br /> 2. Depth of percolation tests= ii inches <br /> 3. Texture '-L-p`.( t-0 A" i Percolation rate 13 .e) mpi 13 w 150ICCO 11221300 1303ZOO <br /> 1503 WO 30:0 <br /> 4. Land slope ' %C 1.AatY 1003 1000 <br /> D. ROCK LAYER.DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> au gpd x 0.83 sq. ft./gpd ==- sq. ft:E A,s,, \,i_,,o = so,0' <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = /o ft. <br /> 3. Length of rock layer= area+width= <br /> 4-:).6. s_sq. ft. + ._62--.ft. = 52 _ ft. �-fa <br /> ll;f...: •,. - '� .w�v�.x..�..sv1nv.r..c.wv� <br /> Width Jo ft • <br /> <120mpi <10' Length Jo 0 ft <br /> >120mpi <5' /b-.. cc) i <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; s�o sq. ft. x J,0 <br /> ft. _ =i cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> £..21.1.cu. ft. +27=• L cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; .cu. yd. x 1.4 <br /> ton/cu. yd. =.3 D tons. <br /> F. ABSORPTION WIDTH Absorption width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is mpi FeeeoiadaRata ie Gallons Redo ofAbscepdoe <br /> MiouIN loch Soil Tann p"day width w Rock <br /> Texture a Ln A�,-I �" Leyer width <br /> Falser due 0,1 Coates Saed 1.20 1.00 <br /> 0.1 to 5 Saod 1.20 1.00 <br /> 2. Select allowable soil loadingrate from table; 0.1 to 5 Floe Seed 0.60 2.00 <br /> 16 to body Loam 0.79 2.00 <br /> •N'i gpd/ft2 31 so 45 SltLam 030 2.40 <br /> 461060C1.6117211 <br /> 0.45 2.67 <br /> 0 <br /> 3. Calculate adsorption width ratio by dividing rock layer s°""iAie 120 0 0 6.0 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ ,4 gpd/ft2= . a,L/ . <br /> 4. • Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a, g ) x IL) ft=a to.1 ft <br />