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septic info including 1994 design
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385 Orono Orchard Road South - 02-117-23-23-0009
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septic info including 1994 design
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Last modified
8/22/2023 4:07:27 PM
Creation date
5/22/2018 12:03:01 PM
Metadata
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Template:
x Address Old
House Number
385
Street Name
Orono Orchard
Street Type
Road
Street Direction
South
Address
385 Orono Orchard Rd S
Document Type
Septic
PIN
0211723230009
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) ' . ' . <br /> A. FLOW iryi t}yc.... y BEtror horn At)AN%.44-5%....v.._ Estimated Sewage 1 w,s in Gallons per day <br /> Estimated. 600 gpd (see pages D-7 or I-3,4,5) Number <br /> or measured gpd x 1.5 = - . B�fps Type I Type II Type III Type <br /> IV <br /> B. SEPTIC TANK LIQUID VOLUMES 2 300 225 <br /> 3 450 300 21818 218 tit 4 600 375 256 tion <br /> a -)DG d gallons (see pages C-3 or C-5) 5 75C; 450 294 yipse <br /> 1 <br /> I 6 900 525 332 1;_11. <br /> 7 1050 600 370 m <br /> 8 1200 675 408 cosmos <br /> C. SOILS (refer to site evaluation) <br /> IS <br /> 1. Depth to restricting layer = t- 1-(0 3o inches Septic Tank Capacities,in gallons <br /> 2. Depth of percolation tests = i a'' inches ��'s Minimum Liquid <br /> Lgarbaged uid capacity <br /> 3. Percolation rate /0. %mpi 2"k� 1 030 1� <br /> 4. Land slope or 6 <br /> 7`B8 or 9 1503 <br /> 2000 33000 <br /> over 9 ---.. <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = , <br /> , C.o o gpd x 0.83 sq. ft./gpd = Lo is. sq. ft-po° --75494 <br /> 2. Select width of rock layer (10 feet or less) = 10 ft. <br /> 3. Length of rock layer =Area s Width = <br /> . '-t', sq. ft.s 0 ft. = Ls ft. Rock Bed <br /> :.:.:.:.:.:.:.:.:.:.:.:.:.:.::r. <br /> 1 <br /> '•:•:•:.:•:•:J f :•:•:•:.f.:.. <br /> ti•ti•ti ti•ti•ti•{ {•ti•ti•ti.ti.ti.ti.ti:�'INidth 570 ft. <br /> E. ROCK VOLUME ,'.•:t:!:_:!:_:_t g_:!l:•:•:_:_:; <br /> F-- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 54.1 sq.ft. x1.o.r ft. = soil cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd.,to get cubic yards; <br /> Shy cu. ft. 27= a. 1 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> ? 1 cu. yd. x 1.4 ton/cu. yd. = 2 tons. 'T <br /> F. ADSORPTION WIDTH L<_4q ti7 A-'a1 <br /> 1. Percolation rate in top 12 inches of soil is O.< mpi Absorption Width Sizing Table <br /> 2. Select allowable soil loading rate from table on page E-; Percolation Rate Gallons Ratio of <br /> in Minutes pu Soil Texture per day per Absorption widtA <br /> .14. <br /> 1 i d/f t2 Inch(MPl) square foot to Rock Layer b! <br /> Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand <br /> 0.1 to 5 Sand 1.20 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 0.1 too•• Fine Sand•• 0.60 2.00 <br /> 6 1.20 gpd/ft2+ .Li gpd/ft2= a.V6to3 Lo <br /> 16 to 30 L <br /> ) . san0.79 2.00 <br /> oam m 0.60 2.00 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> Check this value on page E-16. 4660 to 60 Clay <br /> l alt am 0.450 2.67 <br /> 4. Multiply adsorption width ratio by rock layer width to get Slo ;;an Clay ---- <br /> required adsorption width; <br /> g,1,9 x /0 ft =3t..7 ft <br /> I <br />
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