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PRESSURE DISTRIBUTION SYSTEM EN0 PERFORATION OF A PERFORATED Lanai. <br /> Greet Caw . <br /> • <br /> P�,,,. <br /> 1. ' Select number of perforated laterals 3 Twill <br /> N sut.atI.pawk fr" <br /> LeanW fond Laps :Inch tars N lisp a.Mer q <br /> . ••want ruin paw) <br /> 2. Select perforation spacing = 3 feet ' ,r.., .".M ,No meg; MN Pete Nan aut.d 1b,ir.Mt:.:-," <br /> CPt+.dr Dr <br /> IX -AlLank 12'1° Edge <br /> 3. Since perforations should not be placed closer,than 1 ft. to °n.1e1°"" . ' el ROth Ilene <br /> -P.rlsr°ilnm Leaned et <br /> the edge of the rock layer (see diagram), subtract 2 ft. from Clean Sand Leger Sown,el Lateral <br /> the rock layer length. sok sa►MMd <br /> J Makes Placing send Leper <br /> Rock layer length 2 ft. = ?; feet <br /> TABLE Or PERFORATION DISCHARGES IN CPM <br /> 4. Determine the number of spaces between perforations. Head Perforation diameter(inches) <br /> Divide the length above by perforation spacing and round <br /> down to nearest whole number. ''" 'I4 <br /> 1.Oa 0.56 0.74 <br /> Length perf. spacing = S"? ft. + ft. = 7 spaces iob 0.69 1.a <br /> (#3) (#2) 2.5 0.89 1.17 <br /> 5. Number of perforations is equal to one plus the-humber of ;.0 0.98 i 48 <br /> perforation spaces . 5.0 1.26 1.65 <br /> aUse 1.0 foot of head for residential systems. <br /> 17 ,spaces + 1 = I °r perforations per lateral bUse 2.0 feet of head for other establishments <br /> 6. Multiply perforations per lateral by number of laterals to <br /> get total number of perforations. <br /> Table 2 <br /> X t - 54perforations Maaimumalloveblenumber ofguider inch perforati,m.per <br /> lateral a Perls/lateral P lateral to guarantee<10%Discharge variation <br /> per«.Z,"1" 1.25 inch 1.5 inch 2.0 inch <br /> 7. Determine required flow rate by multiplying 2.5 14 18 28 <br /> number of perforations by flow per perforation 3.0 13 17 26 <br /> 3.3 12 16 25 <br /> • 4.0 11 15 23 <br /> K_ 5.0 10 14 22 <br /> Pals X gpm/perf= L4 v gpm. <br /> 8. If laterals are connected to header pipe as shown on upper UMW OLD ier,.re., MI a,...What 66,•410,04e„r. <br /> example,select minimum required lateral diameter from 4,1. <br /> table 2; enter table with perforation spacing and number ,o,2- <br /> of perforations per lateral. Select minimum diameter for <br /> perforated lateral = inches ••••°"0.- Err- <br /> 9. If perforated lateral system is attached to manifold pipe near <br /> the center,as in lower example, perforated lateral length and """ "'= v..=- <br /> number of perforations per lateral will be approximately one c'"----"" <br /> .•- <br /> half of that in # 6. Using these values,select minimum is = Z••r ..is' <br /> diameter for perforated lateral from table 2 -- rx--- <br /> perforated lateral = / Ila inches wlIra+r** <br />