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1994-006604 - new septic system
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Orono Orchard Road North
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040 Orono Orchard Road North - 35-118-23-34-0005
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1994-006604 - new septic system
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Last modified
8/22/2023 4:58:47 PM
Creation date
5/9/2018 12:58:34 PM
Metadata
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Template:
x Address Old
House Number
40
Street Name
Orono Orchard
Street Type
Road
Street Direction
North
Address
40 Orono Orchard Road North
Document Type
Septic
PIN
3511823340005
Supplemental fields
ProcessedPID
Updated
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• <br /> DDO PERFORATION OP A P£RFOAATED U►'tRA-- <br /> C _ 10 E ; 1 • r <br /> 1. Select number .f perforated laterals -3 fr T.s..l A <br /> / G.. uae newts too.. Leto( <br /> M«N n <br /> heat,Send law :Men t.t.r ot ow«.rw t....N <br /> 2. Select perforad i n spacing= -3 feet. re w l rad <br /> •t ••• • �� <br /> t'rse:?rrsrrr?'rt•ta• rt.u, d.er T.e <br /> 3. Since perforatio should not be placed closer than 1 ft. to -:'f ' _ „ ” �,:' cap <br /> the edge of the ock layer(see diagram),subtract 2 ft. from -:-..' - ' r.t« d.tt000.lAcetof <br /> the rock layer 1= gth. , u».Send l.,.. bottom of (Alma <br /> Original Salt Proven? Scoolloo - <br /> ` -2 ft. _ '`�� feet. r..t«..t.�. s.,,.�.,.. <br /> rarer tengeh TABLE OF PERFORATION DISCHARGES IN CPM <br /> 4. Determine the umber of spaces between perforations. Head Perforanondlament(Inchel <br /> Divide the leng h above by perfc::::cn 31 acing and round I '/a '�. <br /> down to neares whole number. <br /> 1.0a') 036 0.71 i <br /> 73 0.69 0.90 <br /> Length perf. sp ting 31 ft.+ 3 ft. = l6 spaces z os 0.80 1.04 <br /> (3) (2) 3.0 0.s 1.23 <br /> 5. Number of perf rations is equal to one plus the number of to <br /> o .47 <br /> 1.13 1 <br /> perforation spa es . <br /> ....se 1.0 foot of head for residential"meats. <br /> IWise LO feet of head for other establishes:..... ( <br /> /G space• + 1 = 17 perforations/lateral <br /> M........•.t.......r.-.-.r.r.....r w.t.. <br /> 6. Multiply erfo•ationsper lateral bynumber of laterals to <br /> p y p .r. 125 inch 1.5 inch 2.0 inch <br /> get total numb- of perforations. 14 1$ 28 <br /> 13 ___11_17.) 26 <br /> �_ ) ') �3.3 12 16 25 <br /> X perforations. 4.0 11 15 23 <br /> lateral a pct's/lateral 5.0 10 14 22 <br /> 7. Determine req ed flow rate by multiplying <br /> number of perf'rations by flow per perforation <br /> O.7`1 _ 4 gp l l,. ......14.0 LOCA.ed .r OO St q.9e,. OSMOTIC.. [. <br /> . _ gpar/peri <br /> 8. If laterals are cected to header pipe as shown on upper <br /> example, to sel minimum required lateral diameter; enter �,,,. -,table with perf ration spacing and number of perforations ,,� <br /> per lateral. Sel ct minimum diameter for \- -''''''' <br /> perforated later = inches. <br /> c,__._,a..... <br /> 9. If perforated la ral system is attached to manifold pipe near "mamma center,low diagram,perforated lateral length and --:-.=-.1.-.----' <br /> number of perf rations per lateral will be approximately one - "•'Q'""''= <br /> half of that in s p 8. Using these values, select minimum �,,.'*�\� <br /> diameter for pe forated lateral = / z- <br /> inches. N.--.• ca 1-1.4-- <br />
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