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t-19 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> I <br /> A. FLOW 1 D-7 I <br /> Estimated 7.. ' gpd (see pages D-7 or I-3,4, 5) Es11W>m sErI1.0[no*s 1N GILI.ONS POI <br /> W. <br /> MAMA 1.K 0/11E510E1•CE I. <br /> Of <br /> or measured 1 gpd. 2E06000I - Q CS 3 <br /> 2 300 225 100 10% <br /> 3 430 300 211 •r <br /> B. SEPTIC TANG LIQUID VOLUMESin <br /> 750 ;; u `' ` <br /> 2.^/00 0 gallons (see pages C-3 or C-5) 1 sis 1000 370 � <br /> 11 1200 .,] •Oe E3106.• <br /> v2i9/.0 A 'XI C-3 <br /> C. SOILS (refer tb site evaluation) SEPTIC TANK CAPACITIES, IN GALLONS <br /> 1. Depth to restricting layer = 20 inches °'"°`3.60" <br /> COd 1e.�e11Y ee7110•Ca•0. <br /> ttnloor uowo Guinan 01 <br /> 2. Depth of ercolation tests = / .-- inches ,a1..,, ,,, ,,,, <br /> 3. Percolati rate I - 1 Le mpi �«�' �••• t••• <br /> 20m. ,.e. 5200 <br /> 4. Land slop 4 % a. ,,,• ,.ee <br /> I <br /> t <br /> D. ROCK LAYS DIMENSIONS <br /> • 1. Multiply ow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> Z gpd x 0.83 sq. ft./gpd =6,ZZ sq. ft. <br /> 2. Select wid h of rock layer(10 feet or less) = /0 ft. <br /> 3. Lengthof tock layer= area+width = <br /> to i 2 sq. ft.+ JO ft. = to Z ft. Rock Bed <br /> VS%7.}ti Fr�r itiZi.. VWidth 510 <br /> �rlf!�r l•1�1t P11I ,,1 ZN <br /> E. ROCK VOLUME en th a <br /> 1. Multiply ock area by rock depth to get cubic feet of rock; " 2 <br /> 6, L sq. ft. x__I_ft. Z Cu. ft. i40 x 3 Z 10 <br /> 2. Divide cu ft. by 27 Cu. ft./cu.yd. to get cubic yards; <br /> (Q 2 cu. ft. +27= z3 cu. yd. 3 z <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> Z,3 cu. yd. x 1.4 ton/cu. yd. = 32 tons. <br /> i44 <br /> F. ADSORPTION 1WIDTH <br /> 1. Percolation r e in top 12 inches of soil is I So mpi E-16 <br /> 2. Select allows le soil loading rate from table on page E-16; •�-•-••0.�•�>nd•0L2e.eEA1loe•es <br /> (� gpd/ft2 :.A1.Y• ..--•- - i <br /> 3. Calculate adso tion width ratio by dividing rock layer <br /> en. . 1.00 ..N ..N Lea <br /> loading rate of .20 gpd/ft2 by allowable soil loading rate; '" '" <br /> ;660111: <br /> . ie e.w a.N t.a t.ee <br /> 1.20 gpci/ t2 140 gpd/ft2= .GJ'U 0.N •w 10. <br /> •. •.0 0.N 0.12 LN 2..1 <br /> .1 •120 0.2. 0.34 00 0 00 <br /> Check this value on page E-16. - <br /> 4. Multiply adso ption width ratio by rock layer width to get <br /> required adsor tion width; <br /> x /0 ft ....2e, <br /> ft <br />