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• MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. ,FLOW Estimated Sewage Flows in fiilll.ni%per(lay <br /> ` (grxi) I <br /> b� D <br /> Estimated <br /> gpd (see pages -7 or I-3,4,5) Numbcr <br /> or measured gpd x 1.5 =__. RedroTyPC I type II Type III Type <br /> omc <br /> 2 300 225 180 <br /> B. SEPTIC TANK LIQUID VOLUMES 3 4450 300 218of the <br /> •ti r'-'7u"• <br /> G 3 $ 750 450 294 ` <br /> gallons (see pages or C-5) 6 900 525 332 , t.t• <br /> 7 1050 600 370 nt <br /> • 8 1200 675 408 colurnra <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer = -L gt inches Septic Tank Capacities,in Kallon. <br /> Number or Minimum Liquid Liquid capacity with <br /> 2. Depth of percolation tests = I q inches Bedrooms Capacity rarb.Kc distars•1 <br /> 3. Percolation rate ( 16 rnpi 2o leu 75011233or4 1(X10 IAxt <br /> 4. Land slope (, ,;O or9 15(X) 2234/ <br /> T9NIX) x(s) <br /> over 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> (ov C} gpd x 0.83 sq. ft./gpd = L( sq. ft. x I. 1 - F <br /> . 2. Select width of rock layer (10 feet or less) = 1 0 _-ft. <br /> 3. Length of rock layer = Area +Width = <br /> sq. ft. + ft. = `- ft. Rock Bed <br /> •t•I'•t•l•t•t•d•t•l•t•1•t•t •: <br /> •••ti•ti•ti•• •.• <br /> •••,.••., Ii <br /> :•::::41::::::::::::::. dth- 1011. 1 <br /> :r-+ fff-r-r <br /> r - -fry �' <br /> -r' •'•'••r J <br /> E. ROCK VOLUME F--- Length <br /> 1. Multiply rock area by rdlk depth to get cubic feet of rock; <br /> sq. ft. x \ ft. =S';6 cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards, <br /> J '' cu. ft. + 27=7,74 cu. yd. <br /> . <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in .ons; <br /> 1;7 cu. yd. x 1.4 ton/cu. yd. =66 tons.• <br /> F. ADSORPTION WIDTH i <br /> p Absorption Width Sizing Table1. Percolation rate in top 12 inches of soil is 9 mpi <br /> Percolation Rate Canons Ratio of <br /> 2. Select allowable soil loabliDg rate from table on page E-, in Minutes per Soil Texture per day per Absorption width <br /> titch(MPI) square foot itt Kuck Layer <br /> r1 gpd/ft2 I Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand •.-•. ---- <br /> 0.1 to 5 Sand 1.20 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 0.110 5•• Fine Sand•• 0.60 ' 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 1.20 gpd/ft2+ ,L' = -7 gpd/ftd 1 / 16 to 30 • Loam 0.60 2.0031 to 45 silt Loam 0.50 2.40 <br /> Check this value ong pe Q E-16. 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 $ 5.0u <br /> 4. Multiply adsorption width ratio by rock layer width to get st:;,an clay <br /> required adsorption width; ` <br /> 2 ,;-7 x 10 ft =7,‘, 7ft <br />