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. <br /> F/ <br /> 13-34 • SECTION 13: Forms and Reference <br /> OSTP Pressure Distribution <br /> UNIVERSITY <br /> Minnesota Pollution • <br /> Design Worksheet OF MINNESOTA <br /> Control Agency lit**11• <br /> Project ID: v 11.10.10 <br /> 1. Select Number of Perforated Laterals in system/zone: I 3 I <br /> (2 feet is minimum and 3 feet is mo)mum spacing) _ <br /> it z .s.:':.;•;.7-;:U1.,-;.;17;: t id's <br /> 2. Select Perforation Spacing: I 3 I1La t ; yit s s e r p <br /> 3. Select Perforation Diameter Size 7/ g. Iin <br /> - <br /> LR'9t tatr <br /> 4. Length of Laterals =Media Bed Length-2 Feet. ,, •,• - <br /> 7S' - 2ft = 7 3 ft Perforation can not be closer then 1 foot from edge. <br /> 5. Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 73 ft + 3 ft = =4. Spaces <br /> 6. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> • Perforations Per Lateral - Z+ Spaces + 1 = Z..5 Perfs. Per Lateral <br /> Check table below to verify the number of perforations per lateral guarantees less than a 10%discharge variation. The value is <br /> double if the a center manifold is used. <br /> > of <br /> Rr�1`6k��LtnEerr�!� 4�. � N <br /> . 1 <br /> Wf4Inr�i Fer1`aria ' ' ..- lin itch Perforations , <br /> Pharalion erda'(Feet Diameter(inches) Portion 6F�+�Q Pipe Diameter(Inches) <br /> 1 114 iii 2 <br /> (Feet) 1 Ito 1 Pe 3 3 <br /> 114 12 30 48 -r.:-..--,,,.,. l` 0 ,, ' '.'` <br /> 211 <br /> 8 12 16 28 54 21<t <br /> 114 14 <br /> C! P< <br /> 3/16Inch-Perforations in Inch Perforation . , <br /> Pif <br /> foration Spacing NO • <br /> Pipio Dimnstor Oran) PPrfaor flan Pik*t(#miel*ir(I .°!'4"! <br /> 1 11311111311 3 (F <br /> . <br /> X <br /> 21i 13 mos= 40 30 T 20 30 1111111111133.1 136 <br /> 2 11_ _ 20 19 ill " i <br /> 7. Total Number of Perforations equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 2-5 Perf. Per Lateral X I 3 JNumber of Perf.Laterals 75 Total Number of Perf. .. <br /> 8. Calculate the Square Feet per Perforation. Recommended value is 4-10 f t r ?f* ,- <br /> per p er f oration. lyrre.•l?nOtld,.n�(ai1N) f <br /> Does not apply to At-Grades t+dorelbn Dl..na•f <br /> ;14...d frt. .I. 14. r4, 14 .. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) <br /> t f O.: -:-041' '!'0.11i'C 0;7Y <br /> 1.1 0.32 0.N O.if O.7 <br /> 7S ft X f ft = I 7•S'a Ift2 r_i—co_-,..-ii.--,..._ s'�.7,--ii,—.3-7-"ias <br /> , 2! 0 i 0.115 0fie 1.17 <br /> c'60 0.2x,. ,0.72 '::-0.Or.: 1:24 <br /> Square Foot per Perforation =Bed Area divided by the Total Number of Perforations (Line 7). ' sA 0.27 0.112 ;.1 1•,7 <br /> 1 <br /> O ft2 + G perforations = ,1,ot Dwellings with 3/16 In&10114 inch <br /> '7S ft/perforations pe.fe1,010/t• <br /> 9. Select Minimum Average Head: /, ft 2 fa` Other.s2ebtkMnents"^°µ11s wit 2/14 <br /> inch W <br /> 1 inch 7oRer.6n <br /> ,f pOtZ rlAbb10mqo end As5T5 whi1t4 Inch <br /> 10. Select Perforation Discharge (GPM)based on Table III: . 5(cs GPM per Perforation <br /> 09111 <br />