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septic design-2001
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505 Orchard Park Road - 31-118-23-14-0012
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septic design-2001
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Last modified
8/22/2023 4:29:33 PM
Creation date
4/27/2018 1:41:08 PM
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x Address Old
House Number
505
Street Name
Orchard Park
Street Type
Road
Address
505 Orchard Park Road
Document Type
Septic
PIN
3111823140012
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' PRESSURE DISTRIBUTION SYSTEM Geotextile fabric <br /> 1. Select number of perforated laterals 3 1 Quarter inch perforations spaced a 3' <br /> 2. Select perforation spacing= 3 ft <br /> Perf Sizing 3/16"-1/4" <br /> 3. Since perforations should not be placed closer than 1'foot to Perf Spacing 1.5'-5' <br /> the edge of the rock layer(see diagram),subtract 2 feet from <br /> the rock layer length. <br /> E-4: Maximum allowable number of 1/4-inch perforations <br /> 5 -2 ft = S3 ft per lateral to guarantee<10%discharge variation <br /> Rock layer length perforation <br /> 4. Determine the number of spaces between perforations. spacing <br /> Divide the length(3)by perforation spacing(2)and round (feet) 1 inch 1.25 inch . 1.5.inch 2.0 inch_ <br /> down to nearest whole number. <br /> 2:5 8 14 18 28 <br /> Perforation spacing= 4-3 ft+ 3 ft= Y') ,spaces 3.0 8 13 17 26 <br /> 5. Number of perforations is equal to one plus the number of 3.3 7 12 16 25 <br /> perforation spaces(4). Check figure E-4 to assure the number of 4.0 7 11 15 23 <br /> perforations per lateral guarantees<10%discharge variation. 5.0 6 10 14 22 <br /> I') spaces+1 = )cd perforations/lateral E-6: Perforation Discharge in gpm <br /> 6. A. Total number of perforations= perforations per lateral (5) . perforation diameter <br /> times number of laterals(1) head Inches) <br /> si perfs/let x 3 let= Sti perforations (feet) 3/16 7/32 1/4 <br /> 1.00 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. <br /> Should be 6-10 sqft/perf.Does not apply to at-grades. 2.Ob 0.59 0.80 1.04 <br /> Rock bed area = rock width(ft)x rock length(ft) 5.0 0.94 1.26 1.65 <br /> o ft x Ss'. ft= SSa <br /> sqft 0 Use 1.0 foot for single-family homes. <br /> Square foot per perforation=Rock bed area+number of perfs (6) b Use 2.0 feet for cnythinsl else. <br /> SS 0 sqft+ 5y_perfs= /0•-4- sqft/perf <br /> L etercko LOCATED AT END or mum oISTammos SYSTEM <br /> 7. Determine required flow rate by multiplying the total number of <br /> perforations (6A) by flow per perforation(see figure E-6) <br /> Sy perfs x .r)y gpm/perfs= 40 gpm /VC Mom <br /> 8. If laterals are connected to header pipe as shown on upper •.. <br /> example,to select minimum required lateral diameter;enter Pr"-_...,..0""‘ " "� <br /> figure E-4 with perforation spacing(2)and number of perforations \,.- d <br /> per lateral(5) Select minimum diameter for <br /> perforated lateral= inches. "`DVPRE MME a..RO°„ra.E,LATERALS FOR <br /> 9. If perforated lateral system is attached to manifold pipe near CE <br /> .sWwm PLASM..c <br /> the center,lower diagram,perforated lateral length(3)and Ju"'`l . 'VP.M"'°"M° <br /> Mhn <br /> number of perforations per lateral(5)will be approximately one . ;�r•.a....�.... ^ <br /> .n <br /> half of that in step 8. Using these values,select minimum '- <br /> diameter for perforated lateral= )`z-inches. "P' ''U? <br /> ..w a <br /> • <br /> • <br /> I hereby certify that I have completed this work in accordance with applicable ordinances, rules and laws. <br /> - -- 61 , a <br /> (signature) 3',ti (license#) 4!-1'3-v / (date) <br />
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