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505 Orchard Park Road - 31-118-23-14-0012
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septic design-2001
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Last modified
8/22/2023 4:29:33 PM
Creation date
4/27/2018 1:41:08 PM
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x Address Old
House Number
505
Street Name
Orchard Park
Street Type
Road
Address
505 Orchard Park Road
Document Type
Septic
PIN
3111823140012
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MOUND DESIGN WORK SHEET(For Flows up to 1200 gpd) <br /> A. Average Design FLOW A-1: Estimated Sewage Flows In Gallons per Day <br /> number of <br /> Estimated 01• • ti• e t•+ ',,,s't bedrooms Class I Class II Class III Class IV <br /> or measured 11 '' '` <br /> � . -404',ctor) = gpd 2 300 225 180 60% <br /> 3 . 450 300 218 of the <br /> S.:..-r :; �:.'illi * 4 600 375 256 values <br /> B. SE <br /> 5 750 450 294 in the <br /> 6 900 525 332 Class I, <br /> a - /CO ) gallons (see figure C-1) 7 1050 600 370 Il, or Ill <br /> 8 1200 675 408 columns. <br /> C. SOILS (refer to site evaluation) .1..1.1-1.J'tzS 11V, 1,'?t�D C-1: Septic Tank Capacities(in gallons) <br /> Liquid capacity <br /> Number of Minimum Liquid Liquid capacity with with disposal& <br /> 1. Depth to restricting layer =). 4):.0,a. ) feet Bedrooms Capacity garbage disposal lift inside <br /> 2. Depth of percolation tests = 1.o feet 2 or less 750 1125 1500 <br /> 3. Texture G‘..:Pr`i lr.o4-w1 3ora 1000 1500 20 <br /> 5 or 6 1500 2250 3000 <br /> Percolation rate i C•S mpi 7,8 or 9 2000 3000 4000 <br /> 4. Soil loading rate t 4S- gpd/sqft(see figure D-33) <br /> 5. Percent land slope ` % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> C".)0 gpd x0.83sgft/gpd = Lic7.6 sgft+)0'7v- S4 )D <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR) <br /> 0.83 sgft/gpd x I – gpd/sgft= 10 ft Mound LLR <br /> 3. Length of rock layer = area_width = <br /> 54V) sqft (D1) _ 10 ft (D2) = 5 5 ft < 120 M PI < 12 <br /> 9So x.45.5=L, .. - )v =ba. (i6+x i.lgoc-y-B>-7-, - "ir-- s^woo*-t X40,--,•) — <br /> E. ROCK VOLUME > 120 MPI < 6 <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> £1-1'? sgft x 1 ft = 541 cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> 5(i 1 cuft 4-0340)10014fiver�o —cuyd <br /> 3. Multiply cilftV 'df$ t of rock in tons <br /> D. – ' -Apns <br /> LIIRTIValle IA 41VKS3i`:=1A Cr,RifD-33: Absorption Width Sizing Table <br /> { f'�," ° „t Percolation Rate Loading Rale <br /> F. SEWA - <br /> Tf}, � f in Minutes per Soil Texture Gallons Absorption <br /> *OW la�11j1Rlp�fd Inch per day per Ratio <br /> wit 70i o (MPI) square foot <br /> 400,14 lr tomol ogruit i fl!W'Itt 4n,h).4 s0 ti')iiilbisakb #t} <br /> otpOttadfJflai Faster than 5 Coarse Sand 1.20 1.00 <br /> 1k1f?rt$2 '"+X:+, iii Medium Sand <br /> Absorption width equals gtafrAitl M{(ec ure D-33) Loamy Sand <br /> Fine Sand <br /> times rock layer width (D2) 6 to 15 Sandy Lnnm 0 6790 t 50 <br /> 16 to 30 Loam 0.60 2.00 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> t � ^ Silt <br /> D•1 /) <br /> 0 x 1 o ft — Ct IO '). ft 46 to 60 Sandy Clay Loan 0.45 2.67 <br /> Silty Clay Loam <br /> Clay Lnam <br /> 61 to 120 Silty Clay 0.24 5.00 <br /> Sandy Clay <br /> Clay <br /> Slower than 120'. <br /> •Srnem d.ogned to.U...e.cit.nnn be aver o.pe.ren,,..ce <br />
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