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1992-004426 - replace septic
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1992-004426 - replace septic
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Last modified
8/22/2023 4:39:46 PM
Creation date
4/25/2018 11:05:55 AM
Metadata
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Template:
x Address Old
House Number
460
Street Name
Orchard Park
Street Type
Road
Address
460 Orchard Park Road
Document Type
Septic
PIN
3211823230012
Supplemental fields
ProcessedPID
Updated
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ENO PERFORATION OF A PERFORATED LATERAL <br /> PRESSURE DISTRIBUTION SYSTEM • onia am <br /> • tA <br /> 1. Select number of perforated laterals 3 , 1I SSM c <br /> • <br /> I .- <br /> ' '• , 'M Pi ,,« «o «erf Se' <br /> • <br /> 2. Select perforation spacing = 3 feet rei <br /> ':nrcnrrrtn^�wa Mk. ��a�NrwMo::/ <br /> Gyp. ti. 4 LIeM (a°to IIN <br /> " <br /> 3. Since perforations should not be placed closer than 1 ft. to '-" . . ' , of <br /> the edge of the rock layer(see diagram),subtract 2 ft. from awl sold(Mr "I""1rfil <br /> the rock layer length. <br /> 5Sso > <br /> t«.heap,s«w <br /> Rock layer length- 2 ft. _ •S"." feet <br /> TABLE Or PERFORATION DISCHARCIIS IN CPM <br /> 4. Determine the number of spaces between perforations. Head Perforation diameter(Inch.,) <br /> Divide the length above by perforation spacing and round L <br /> down to nearest whole number. '/_ ti4 <br /> 1.0a 0.56 0.74 <br /> Length perf. spacing = 53 ft. + -7 ft. = I9 spaces <br /> 1.5 0.69 <br /> o 0 °. <br /> (#3) (#2) 2.5 0.89 1.17 <br /> 5. Number of perforations is equal to one plus thehumber of 34:00 0.9813 iA7 <br /> perforation spaces . 5.0 1.26 1.65 <br /> aUse 1.0 foot of head for residential systems. <br /> It) spaces + 1 = I ce perforations per lateral bUse 2.0 feet of head for other establishments <br /> 6. Multiply perforations per lateral by number of laterals to <br /> get total number of perforations. <br /> Table 2 <br /> x 1 = S y perforations <br /> MC%anUm allowable number of grater loch perforation per as <br /> laterals Peds/lateral- h lateral to guaranies<10%Discharge variation <br /> 'e t:rift 1.25 inch 1.5 inch 2.0 inch <br /> 7. Determine required flow rate by multiplying 2.5 14 18 28 <br /> number of perforations by flow per perforation 3.0 13 17 26 <br /> 3.3 12 16 25 <br /> 4.0 11 15 23 <br /> 5.0 10 14 22 <br /> > s x pert= 8Pm• <br /> 8. If laterals are connected to header pipe as shown on upper .Le mem°`"' MOM"""""°'JAW* <br /> example,select minimum required lateral diameter from „r° <br /> table 2;enter table with perforation spacing and number --'' <br /> of perforations per lateral. Select minimum diameter for <br /> perforated lateral = inches .----- 1. 4, <br /> 9. If perforated lateral system is attached to manifold pipe near <br /> the center,as in lower example, perforated lateral length and "'"1"..X1.1=1.mss" <br /> . number of perforations per lateral will be approximately one cf"°'-"-"" <br /> half of that in #6. Using these values,select minimum A 1K=• `-••i°"'''° <br /> diameter for perforated lateral from table 2 %.- iL--- <br /> perforated lateral = 1 /It- inches <br />
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