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• MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Palmated Sewage Floors in Gelkass per day <br /> Estimated ( „t <br /> c) c9 gpd (see pages D-7 or I-3,4,5) Number cwd> <br /> or measured gpd x 1.5 = -. BedroomsType t Thse 11 ' 111 <br /> 2 300 <br /> B. SEPTIC TANK LIQUID VOLUMES ; 22„ ;;033 211w" <br /> 50 <br /> -10o c) gallons (see pages C-3 or C-5) 6 750 <br /> sn n VII.twaseie SOILS (refer to site evaluation) 7 s, ;a <br /> 1. Depth to restricting layer = a (o inches Sepik <br /> Tagil <br /> `ap r"`"`'p""" <br /> rah <br /> 2. Depth of percolation tests = 1 inches Number Mi i�awspa"+�'+ <br /> 3. Percolation rate mpi 2 ism ,a ;m <br /> 4. Land slope % �, ;;; 22.10 <br /> 3t <br /> ear 9 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = <br /> (c v gpd x 0.83 sq. ft./gpd = 1- sq. ft.4- o'>., <br /> 2. Select width of rock layer (10 feet or less) = I 0 ft. <br /> 3. Length of rock layer = Area+ Width = <br /> S4 7 sq. ft. + 1 o ft. = SS'"ft. Rock Bed <br /> �•r.r.r•r•r•r•r•r r•r•r•r.r.r•r <br /> .•.ti.4.ti.ti.b.ti•ti.ti..•.ti.S.ti.ti.ti•. <br /> r•rN•r•r•r•r•r r ctive•r•r <br /> ti•ti••.•ti.ti.ti.ti.;•,.••.•ti•ti•ti•ti�lNidth molt. <br /> •r•r.r•rM.rN•r 04 a <br /> E. ROCK VOLUME t;r_f r•r_rrr_r•.!.r.r•r.r•r_rrr <br /> I <br /> l-- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> t2 sq. ft. x 1. t. _ .6/7y cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ,s-14 cu. ft. +27=, 2. cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> l cu. yd. x 1.4 ton/cu. yd. = a, tons. <br /> F. ADSORPTION WIDTH 4.1-J1-Le L_o a r.l <br /> 1. Percolation rate in top 12 inches of soil is 9.u mpi Absorption Width SIzInRlbbk <br /> paeolatian Rale Gallant Rub of <br /> 2. Select allowable soil loading rate from table on page E-; loin iti gpd Soil Moron pa day per Absorption width <br /> . 9 s' gpd/ft2 luny t�RWrth e► <br /> 3. Calculate adsorption width ratio by dividing rock layer Faster than 0.1• Coarse Sand <br /> 0.1 w 3 stud 1.20 1.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; (LI:L.. Fine Sand•• oho 2.00 <br /> 6 to 13 Sandy Lamm 0.79 1.32 <br /> 1.20 gpd/ft2+ .ti S 8Pd/f t2= . .[e? . 16'0:+0 Loam 0.60 2.00 <br /> 31 to 43 Sit Loam 0.30 2.40 <br /> Check this value on page-16. 4„11 OrtlayLoan 00..2 22 o <br /> 4. Multiply adsorption width ratio by rock layer width to get S ;an par - -- <br /> required adsorption width; - <br /> .c�'1 /o ft = a c„. ft <br />