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i <br /> PUMP sELEC[1ON PROCEDURE <br /> A. Determine pump capacity: <br /> Gravity Distribution <br /> t Minimum suggested is 20 gpin <br /> 2. Maximum suggested is 45 gpm <br /> Pressure Distibution <br /> 3. a Select number of perforated laterals Perforation Discharges in GPM <br /> b. Select perforation spacing = feet. (lead Perforation diameter <br /> c. Subtract 2 ft. from the rock layer length. feet fiches <br /> feet. liZelall <br /> r<, K <br /> Roc.t. ,< N- 2 ft. = <br /> d Determine the number of spaces between perforations. <br /> I <br /> 04 <br /> 056 0�a <br /> Length pert. spacing = ft. ft. = spaces z.ob oo 104 <br /> c. spaces + t = perforationsflateral <br /> f. Multiply perforations per lateral by number of laterals to a Use l 0loot single homes <br /> get total number of perforations. x - perforations. b Use t o feet(or anything else <br /> g.: tTrr x ��_- -gpm. /'/ <br /> SELECTED PUMP CAPACITY 44(69 gpm <br /> 13. Determine head requirements: Soil <br /> " """'`" <br /> /00 I Elevation difference between pump and point of discharge. °= •---- <br /> 5 feet roti p,fc kn6 1, _____-------- <br /> 2. <br /> 2. If pumping to a pressure distribution system, five feet for pressure <br /> required at manifold if gravit system, zero. q� `� y�a$,0��" <br /> Inlet 5AH.: t'a^v.loon O,r(f,e.te <br /> r0__ feet P;r.e <br /> 3 Friction loss ••t <br /> I <br /> a. Enter friction loss table with gpm and pipe diameter. <br /> Read friction�d loss in feet per 100 feet from table(F-14). <br /> F.L. = (vrL4_. ft./100 ft of pipe <br /> b. Determine total pipe length from pump to discharge Friction Loss in Plastic Pipe <br /> point. Estimate by adding 25 percent to pipe length for fitting Nominal <br /> loss,or use a fitting loss chart(F-1S feet). pipe dia. <br /> Equivalent pipe length • 1.25 times pipe length = Flow Rate 1.5" 2 3" <br /> _/20 x 1.25 = 150 feet gpm <br /> c. Calculate total friction loss by multiplying <br /> friction loss in ft/100 ft by equivalent ipe length. 20 2.47 0.73 0.11 <br /> `7 +100= 9.7 feet 25 3.73 1.11 0.16 <br /> J`D <br /> Total friction loss = ) x 30 5,23 155 0.23 <br /> 4. Total head required is the sum of elevation difference, 35 6.96 2.06 0.30 <br /> special head requirements,and total friction loss. 40 8.91 2.64 0.39 <br /> 45 11.07 3.28 0.48 <br /> _.__1 5 + 50 13.46 3.99 0.58 <br /> 55 4.76 0.70 <br /> (1) (2) (3c) 60 5.60 0.82 <br /> 65 6:4 0.95 <br /> TOTAL READ 1Q,7 feet 70 4 1-09 <br /> C. Pump selection <br /> 1. A pump must be selected to deliver at least <br /> . Co'Cogpm:.(StepA) witkat least a9. 7 feet.o.f:total head (Step.6)... • . <br /> ` _ <br />