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2002-P05601 - new septic system
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420 Orchard Park Road - 32-118-23-23-0006
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2002-P05601 - new septic system
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Last modified
8/22/2023 4:39:39 PM
Creation date
4/25/2018 9:00:18 AM
Metadata
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Template:
x Address Old
House Number
420
Street Name
Orchard Park
Street Type
Road
Address
420 Orchard Park Road
Document Type
Septic
PIN
3211823230006
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For blows up to 1200 gpd) <br /> A. FLOW I Estimated Sewage Flows to Gallons per day <br /> --7 _ gat) <br /> Estimated 5 I <br /> gpcl "o6cr'O 0..,..,,iaClass 101 Claus <br /> or measured x 1.5 = d B«tOpnk- P� <br /> - a� lg 'l <br /> 375 256I <br /> [3. SEPTIC TANK LIQUID VOLUMES 5 ACP 450 294 <br /> 2-1500 gallons 17 105000 60(1 I 370 I l yre h i <br /> 8675 U nr <br /> UI <br /> -- _-- 1 __1 columns <br /> C. SOILS (refer to site evaluation) <br /> Depth to restricting layer = L septic Tank Capacities fin gallons) <br /> 1. <br /> 7 inches /. /7feet <br /> L ,,,- dsFumberor Minimum Liquid Liquid ^dnposa <br /> 'c2. Depth of percolation tests = f inches <br /> Bedrooms Capacity garbage dgposar ldt:asnda <br /> 3. Texture LOAM Percolation rateJ - m P t 2orless: IOCA 750 X125 I,00 <br /> J or 1100 ,�� <br /> 4. Land slope 6 °/° 1or6 <br /> 15o0 72;0 7.8 or 9 2000 3c00 <br /> 10°° -1000 <br /> D. -ROCK LAYER DIMENSIONS /,0 /a l <br /> 1. Multiply flow rate by'�-to obtain required area of rock layer: A x9r= Mound LLR <br /> 75O gpd x 8ii�sq. ft./gpd = `750 sq. ft. <br /> Pere Rate LLR <br /> 2 Determine width of rock layer = 0.83 sq. ft./gpd x Linear Loading Rate (LLR) <120 MPI < l ? I <br /> 1,05sq. ft/gpdx /�; = _ _1Q_ _ ft >120 MPI 6 <br /> Length of rock layr = area width = <br /> - / ft. -- . i..a oeYa.s'aa pna e o ooiiao2ocs'eoo.� co,-,a opo <br /> 6o sq. ft. . 0 - �J ft. '�0°a:�Qoo o�,d75,,-.(14�"vn�"nu nc ,v 'r <br /> ,(1,14:1'.1c27;3,!-7=4,,a7=4:1)::4) <br /> ot70t7gaQC p000000�D R.n:a.v6.0.Q°...i ,a (2,,-,..,-41c."1„ <br /> e <br /> Width I0 ft °'1":.e�s00000nuDD,e <br /> . " o�onQr, <br /> <120mpi <10' Length 75 ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; i5D sq. ft. x / ft. _ <br /> 75bcu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 750cu. ft. _ 27 = �?,$ cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; P' cu. yd. x 1.4 ton/ -" 33, <br /> F. ABSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is / i_ mpi Absorption Width SizingTable <br /> Percolation Rate tn Gallons Rams m <br /> Texture Lo.� Montes per Incl, Sal Teuurc ix,dae rer ADtorpton Wdah <br /> (WI) square loot to Rock layer <br /> WgdN <br /> F]ster than 0.1 Coanc Sand 1.20 I00 <br /> 2. Select allowable soil loading rate from table; °1ioS 7Loamy and 170 °0 <br /> Loamy Saul <br /> 16/� 0.1 to 5 Fine Sand 060 700 <br /> 0 gpd/ft2 6to 15 Sandy Loam IS+ <br /> 16 to)0 Loam 0 t50 7.00 <br /> 31 to 45 Sig loam 7.40 <br /> Sig <br /> 3. Calculate absorption width ratio by dividing rock layer 46 to 60 Cq.y Loa <br /> Silty CU 0.5 76y <br /> Sandy CL <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; Slo60 wer Man ay 020 60 <br /> 1.20 gpd/ft2 -- O, 6,0_ gpd/ft2 = -7r 0 <br /> 4. Multiply absorption width ratio by rock layer width to get <br /> required absorption width; <br /> D x 10 ft = c0 ft <br />
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