My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
Septic info including 1985 design
Orono
>
Property Files
>
Street Address
>
O
>
Old Long Lake Road
>
0985 Old Long Lake Road - 35-118-23-41-0027
>
Septic
>
Septic info including 1985 design
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
8/22/2023 4:59:31 PM
Creation date
4/12/2018 12:43:26 PM
Metadata
Fields
Template:
x Address Old
House Number
985
Street Name
Old Long Lake
Street Type
Road
Address
985 Old Long Lake Road
Document Type
Septic
PIN
3511823410027
Supplemental fields
ProcessedPID
Updated
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
24
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
View images
View plain text
DOWNSLOPE DIKE WIDTH <br /> I. If landslope is 3% or more,subtract rock layer width from <br /> adsorption width to obtain minimum downslope dike toe <br /> / i ft- /0 ft= S'►L, feet <br /> 2. Calculate Minimum mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation / feet <br /> b. Multiply rock layer width by landslope t toot Cover <br /> to determine drop in elevation; <br /> I toot Rs •ed <br /> Slope Difference <br /> Separation feet <br /> /, /) x/7 %i- 100= i 7 feet slope Difference t <br /> uos pe width <br /> c. Add depth of clean sand for separation(2a) feet Reek kg Width <br /> at upslope edge,depth of rock layer(1 foot) to depth of feet Downslope Width <br /> cover(1 foot)to find themound height at the upslope edge 20-feet <br /> of rock layer; <br /> / ft+ lft+ lft= 3 feet <br /> d. Enter table with landslope and upslope dike ratio. <br /> Select dike multiplier of ,?, /L . <br /> e. Multiply dike multiplier by upslope mound height <br /> 3 <br /> to find upslope dike width: x __mound <br /> = q feet <br /> f. Add depth of clean sand for slope difference(2b)at . <br /> downslope edge,to the mound height at the upslope edge <br /> of rock layer (2c) to find the downslope height; <br /> . 7 ft+_eft= . ' 7 feet <br /> g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of ,‘.5-....5-40 . <br /> h. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width�ii"x J = ZO feet <br /> i. Compare the values of step G.1 and Step G.2h Select the <br /> greater of the two values as the downslope dike width; <br /> Z d feet <br /> UD,1 Wlelfl <br /> j. Total mound width is the sum of feel <br /> upslope dike(G.2e)width plus rock Rope pia WIDIe - - - <br /> /es felt <br /> layer width (D.2)plus o UC: •WIOIn - UDa •WlDlll <br /> do lope dike width(G.2i); a f eel lest <br /> 7- ft+ /0 ft+ Zo ft= /5q feet <br /> ,Dow IDW <br /> D.flelll <br /> k. Total mound length is the sum of ;; <br /> `' eat <br /> upslope dike width(G.2e)plus rock layer <br /> length(D.3)plus upslo a dike width (G.2e); <br /> V ft+ ZS' ft+ ft = Y3 feet <br /> Total Len015 <br /> Downslope Upslope <br /> 3:1 l-1 5:1 6:1 7:1 1:1 4:1 5:1 6:1 7:1 8:1 <br /> II.lope <br /> 0 3A l0 5.0 60 7.0 3.0 l0 5.0 60 7.0 8.0 <br /> I 3f19 4.17 5.26 638 757 291 3.15 4.76 5.66 656 7.41 <br /> 2 3.19 635 556 6.82 8.14 2.83 3.70 5.36 6.11 6.90 <br /> 3 3.30 156 5.88 7.32 186 2.75 357 .41$3.541. 5. 5.79 6.15 <br /> 3 3.41 6.76 6-25‘ 7.89 9.72 268 3.15 1.17 4.84 5.16 6.06 <br /> 5 351 5.00 .67 857 10.77 261 333 las l00 4.62 5.19 571 <br /> .41 183 Sst <br /> 3310, <br /> 14 9.38 <br /> 2.54 <br /> 3.70 4.23 <br /> 3 95 556 _. <br /> 7,69 <br /> - 1 15.0.34 91 2.12 ,.t 357 1.05 4.49 /d8 <br /> 9 6.11 6.25 9.09 13A1 18.92 2.36 294 3.45 3.90 130 165 <br /> 10 629 6.67 10.0 15.00 23.33 231 286 337 3.75 1.12 1.66 <br /> 11 4.48 7.14 11.11 17.65 30.13 2.26 2.78 3.13 3.61 3.95 116 64 <br /> 12 449 7.69 1250 21.43 13.75 2.21 2.70 3.12 3.19 3.80 I.OA <br />
The URL can be used to link to this page
Your browser does not support the video tag.