My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
1995-007074 - septic replacement system
Orono
>
Property Files
>
Street Address
>
O
>
Old Long Lake Road
>
0900 Old Long Lake Road - 35-118-23-14-0008
>
Septic
>
1995-007074 - septic replacement system
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
8/22/2023 4:57:58 PM
Creation date
4/12/2018 10:52:18 AM
Metadata
Fields
Template:
x Address Old
House Number
900
Street Name
Old Long Lake
Street Type
Road
Address
900 Old Long Lake Road
Document Type
Septic
PIN
3511823140008
Supplemental fields
ProcessedPID
Updated
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
26
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
View images
View plain text
• • MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) • <br /> 1 <br /> A. FLOW Estimated Sewage Flow in Calkins pa Day(gpd) 1 "',‘ <br /> Estimated 'i SO gpd Number l <br /> of or measured - x 1.5 = - gpd. roonu <br /> I II Type III 'Type IV <br /> 2 300 225 180 60% <br /> 3 450 300 218 • <br /> B. SEPTIC TANK LIQUID VOLUMES • 4 600 375 256 <br /> 5 750 450 294 i1 <br /> j-1 X S0 t 1 -/000 gallons 6 900 525 <br /> 105 332 ,;,:r` <br /> 8 1200 675 408 <br /> C. SOILS(refer to site evaluation) ,, �� Naber = <br /> 1. Depth to restricting layer= 3z or 3y inches of <br /> Bedrooms ofroa, ,, <br /> 2. Depth of percolation tests = I'D." inches `""'' `'f`'' <br /> 3. Percolation rate )I•a mpi 23 a'41705000 1.5.125 <br /> 4. Land slope y % 7 a 8 1zo�0°o0 �' <br /> over 9 See 6g.C-6 (x 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = 0 f <br /> iS.0 . gpd x 0.83 sq. ft./gpd = (,az sq. ft.A-J'%=1-4 4 <br /> 2 Select width of rock layer(10 feet or less) = 10 ft. <br /> 3. Length of rock layer= areas width= Rock Bed <br /> 4S 4 sq. ft.+ 10 ft. = 10 c ft. 1rirvrti•�•N•tiK• M•i.Mti•ti��ti <br /> •ti <br /> lc;At: {egtir :ti:ti:titix:441 idth <10 ft. <br /> 140.7.05445:245:404555%.4.155 <br /> E. ROCK VOLUME Length --1 • <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> VtS4 sq.ft. x ).0acft. = 0i4ecu.ft. <br /> 2. Divide cu.ft.by 27 cu.ft./cu. yd. to get cubic yards; <br /> 7) cu.ft. - 27= "D 1 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 2.") ,cu.yd.x 1.4 ton/cu. yd. = 35/ tons. <br /> F. ADSORPTION WIDTH Li->!K LOA w1 <br /> Absorption Width s nn8 Table <br /> 1. Percolation rate in top 12 inches of soil is 11.*z mpi Percolation Rate edam tom.. <br /> Minutes w h <br /> Soil Texture �■ J�i.s <br /> s v � <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> L.1-.L.C. gpd/ft2 0.1 to 5 Sand 1.20 1.00 <br /> 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio by dividing rock layer 31 too 45 Silt Loam 0.0 2 40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Clay Loam 0.45 2.67 <br /> 61 120 1.20 gpd/ft2s . .0 gpd/ft2= a;t,') SlowerOthan 120 _ lay 0.24 - <br /> '. <br /> -Sal having 50%or more at fine or vay fine sand. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> z.t,7 x )o ft.3t,.'") ft <br /> .J <br />
The URL can be used to link to this page
Your browser does not support the video tag.