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' MOUND DESIGN WORKSHEET <br /> (Fot Flows up to 1200 gpd) . <br /> 2.-I, A. FLOW IiatimaIA Sewage Plows in Gallons per day <br /> Win <br /> Estimated foo gpd (see pages D-7 or I-3,4, 5) hmins <br /> or measured gpd x 1.5 = -- Bedrooms 1Yaa I 1Yro 11 'NW In 7yps <br /> 1 <br /> B. SEPTIC TANK LIIQUID VOLUMES 2 300 300 211 ' <br /> 4 600 375 256 NM <br /> a. - /co o gallons (see pages C-3 or C-5) 6 � 4x30 a 4 TMla <br /> 7 1050 600 370 IT <br /> C. SOILS (refer to site evaluation) a 1200 673 .a edam <br /> 1. Depth to restricting layer = al`-1 inches NookTook CeprMlniWpliers <br /> Number ofimum Liquid liquid copeck),*ilk <br /> 2. Depth of percolation tests = I D inches ned,oama Mincapacity grams disponi <br /> 3. Percolation rate 15. I mpi leo is iin <br /> 4. Land slope Ce % ''"6 2!1111 21w <br /> 7,aa9 b111 ]11111 <br /> over 9 --.. <br /> • <br /> D. ROCK LAYER DIMENSIONS ..-- <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = - <br /> tic,o gpd x 0.83 sq. ft./gpd = 4^2 sq. ft.-+1,,'^- '1-) <br /> 2. Select width of rock layer (10 feet or less) = o ft. <br /> 3. Length of rock layer = Area +Width = <br /> Si-ii sq. ft. + i o ft. = 55' ft. Rock Bed <br /> l4::1:I:.-4r4;:(2..14;74 •���.� <br /> .-- , ti•ti•ti• 1.1• • f.j.j.J <br /> }J•J•J•j•J•J•j.r•J•j•J•j Aftt <br /> .ti•ti•ti•ti•ti•�•�•;.ti.ti.ti•ti•1•1•' dth SIO ft. <br /> r.r•r•r•r•r•r• r•r•r•r•r•r•r� <br /> ti 1.�.ti.�.�•ti�ti 5}5}.ti.�.ti.' I <br /> E. ROCK VOLUME 1--- r!J!r t Length f J!J!••!rlr� <br /> F-- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> -S.LI 1 sq. ft. x hos ft. = 5114 cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 04 cu. ft. +27= d,i cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a 1 cu. yd. x 1.4 ton/cu. yd. = a, tons. <br /> F. ADSORPTION WIDTH Le,11rv1 <br /> 1. Percolation rate in top 12 inches of soil is LS. 1 mpi Absorption Width SIsInR7Lbk <br /> Percolation Rate Gallons Ratio of <br /> 2. Select allowable soil loading rate from table on page E-; in1Min: Soil Theme f� Absorption width <br /> Nod Leyer <br /> • Co gpd/f t2 Width <br /> 3. Calculate adsorption width ratio by dividing rock layer Pater than 0.1• Cowie Send d ._. <br /> loading rate of 1.20 gpd/f t2 by allowable soil loading rate; o.1 to s•• Pine Senna•• 0660 2.0000 <br /> 6 to 15. Sandyoan) <br /> L0.79 1.52 <br /> 1.20 gpd/ft2+ •, gpd/ft2= a. 0 . ,161o30 Loam - 1/.60) 2.00 <br /> 31 10 45 Silt Lour--11.s0 2.40 <br /> Check this value on page E-16. 60 clay Lowe 0.,5 2.67 <br /> 64061:120 ay 0.21 5.00 <br /> 4. Multiply adsorption width ratio by rock layer width to get Sl Than Clay --- --- <br /> required adsorption width; <br /> __-_ x /0 ft = a0 ft <br /> I <br />