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02/1'91'15'9'9 08:41 4791547 1OLKENANT PAGE 02
<br /> • C. DOWNSLOPE DIKE WIDTH `-.
<br /> 1. If landslope is 2.9 percent or less,basal width includes both the
<br /> upslope and downslope dike widths, ',
<br /> • 2. Calculate minimum mound size based on geometery:
<br /> • a. Determine depth of clean sand fill at upslope edge of rock o.;
<br /> layer: Separation • 1 feet ':i.
<br /> b. Multiply rock layer width by landslope to determine drop t:
<br /> in elevation; Slope Difference J% 4l_W, • �;
<br /> •::S.�S1•.S .
<br /> ;%'.1 114.it li.d
<br /> 1,4
<br /> _ I.'V x % -x:100 = , 5 feet __Uel3ep.r.,lon !
<br /> , c Add depth of clean sand depth of clean sand for (-__Ltfr.VrJ1k -wan 1_� :
<br /> separation at upslope edge (2a) to depth of rock layer to11. 4III d W,.•),
<br /> rock depth and the depth of cover to find the total mound 119,,,,i1„pt1164,s
<br /> height at upslope edge of rock layer; '"`�:.
<br /> ) ft + 1ft + 1ft = +; _• feet
<br /> d. Enter table on page bottom with landslope and upslope
<br /> • dike ratio. Select dike multiplier of % ,q,s---
<br /> e. Multiply dike multiplier by upslope mound height .:
<br /> r',
<br /> to get upslope dike width: 3 x 1,4,5-7-- ,l 0,1 feet
<br /> f. Add the depth of slope difference (2b) to the upslope
<br /> height to get the downslope height r + = 3•s`• feet
<br /> a
<br /> g. Enter table on page E-18 with landslope and downslope
<br /> dike ratio. Select dike multiplier of 'A ,1 fo
<br /> It Multiply dike multiplier by downslope mound height
<br /> 'to get downslope dike width: 41c" x s. = 11 feet 4
<br /> i. Mininmum•mound width is the sum of upslope dike 1-7 <'
<br /> • width plus rock layer width plus downslope dike width; : i.
<br /> 11 ft + t D ft + 1-7 . ft 3 S feet Km is< 'Width•'" ti slopebike WIdth _T 1;
<br /> j. Subtract the Minimum width G.i 'from the Absorption 1
<br /> width F.4 to find the Additional Downslope required for ;;�f ;:;��ily •;.: *"`r'
<br /> Absorption : •; ;: ::::• .:: ::••::•:,::::�:;:: `:
<br /> ft ft - feet ufbsopefiikewidts :.Up5lopcllikeWidth_ ,1
<br /> -�5::
<br /> Ci
<br /> k• Add the Additional Downslope required for Absorption
<br /> -- -- . 1]nwruloPc•'i�iks•LVic{Ih•'_
<br /> to the downslope dike width and recalulate the Total
<br /> - • • Mound Width which is is the sum of upslope
<br /> dike ::
<br /> width plus rock layer width plus downslope dike width ': - ::' : - -E
<br /> Total t..enprtll "<:
<br /> ft +�_ ft + ft _�_��M feet }4________ - ►i
<br /> 1. Total mound length is the sum of upslope dike width ;
<br /> plus rock layer length plus upslope dike width; #
<br /> 1 i ft + 5n ft + j ft = 1(7. feet h:,
<br /> n ( Uva Du�d
<br /> -fi : -i-7..a. _L) :ii
<br /> owrtslops .tJp opc s,
<br /> 3:1 4:1 5:1 6:1 7:1 3:1 4:1 5:1 6:1 7:1 8:1 M
<br /> x alms
<br /> 0 3.0 4.0 5.0 6.0 7.0 3.0 4.0 .5.11 6,n 7.0 8.0 �!'
<br /> 1 3.09 4,17 5.26 6.39 7,53 2,11 3.85 4.76 5.1.4 (..54 7.41 .'
<br /> 2 3.19 4.35 5.26 6.82 8,14 2.83 3.70 4.54 5.36 614 6.90
<br /> 3 350 4,54 5.48 7..17 8.86 2.75 3.57 4.35 5.C9) 5.79 605
<br /> 4 3.41 4.76_, 6.25 7.89 9.72 2.E.4 J, 4.17 4.84 5.46 6.06 �;
<br /> S 3.53 5) 5.F7 8.5/ 11177 21,7 3T3 4,)X 4.62 5.14 5,71 r;
<br /> 6 3.66 5.26 7.14 9.38 1207 2..S4 3.23 3.85 4.41 4,93 5.41 71
<br /> 7 5.80 5.56 7.69 11).74 11.71 2.414 3.12 .1.70 4:7.3 4.70 5.33
<br /> 4 3,95 5.88 H.33 1154 15 41 7.47 3,111 3.57 4.1C 4.89 488
<br /> 9 4.11 6.25 9.09 13,14 11 '2 2.36 2.94 3.4$ 190 4.36 4.65
<br /> • 10 4.29 6.67 10.0 55.00 23.13 2,13 2,86 3.33 3,75 4.12 4.44 ,fi
<br /> 11 4.48 7.14 11.11 17.65 30.1.1 2.26 2,78 3.23 3.61 3.95 496 1
<br /> 124.69 7.69 1250 21.45 42,75 2.21 2.70 3,12 3.49 3.110 4.08
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