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• ' : ' r . ' , PUMP' SELECTTO.N.PROCEDURE • <br /> • <br /> 1. D etermine pump capafity : -FLS W/✓-? - <br /> A. Gravity distribution <br /> 1. Minimum required discharge is 10 gpm • <br /> 2. . aximum ggested'dis is 45,gpm. For <br /> Mother <br /> establish= is at least 16% • iiter than the water supply rate, <br /> but no:faster than the rate a which effli ent will flow out of the • <br /> distribution device. . . <br /> B. Pressure distribution 1 . " . ' <br /> See pressure•distrr iution work sheet <br /> • <br /> From'A or B Selected•p • p capacity: WI gpm <br /> • <br /> 2. Determine pump head• -quirements: . . <br /> A. Elevation difference between • .. • and point of discharge? • soil treatment systi <br /> 4 ,feet . ! &p•Int • •Ischar <br /> 13. Special head requirement?(See figure at right-Special Head Requirements) . total •Ipe <br /> feet len. <br /> Inlet t;Y, ,.u.,,, 2A.elevation <br /> C. Calculate Friction loss . pipe ti I'll difference <br /> 1. Select. ia diameter Q. v • - <br /> PP � ,f, <br /> 2. Enter Figure E-9 with gpm(1}A�or B)and pipe diameter(Cl). �.°u•w. ° �'�''' <br /> rrcr�✓ <br /> Read friction loss in feet per p.00feet from FigureE-9 ' Special Head Requirements <br /> Friction Loss in 3.2 ,ft/100ft of pipe Gravity Distribution 0 ft' <br /> 3. Determine total pipe length from pump discharge to soil treatment ;Pressure Dtstrtbution 5 ft <br /> discharge point.Estimate b •adding 25.percent to pipe length for . <br /> fitting loss. Total pipe length times 1.25 a equivalent pipe lengthE-, Friction Loss to Plastic Pipe <br /> 3‘ ?feet x 1.25 = �-1 • nominal <br /> eet • Per 100 toot <br /> 4. Calculate total friction loss . multiplying friction loss(C2) <br /> in.ft/100 ftby.the equivalent ipe•length(C3)and divide by 100. pipe diameter <br /> = 3.1.- ft/100ft x 441 . +100= I ft ' flow rata 1. 2 3 <br /> gpm _ <br /> D. Total head required is.the sued.of elevation difference(A),Opecial''' 20 ' 2.47 0.73 • 0.11 <br /> head requireatents.(B),and total friction loss(C4) ' 25 3.73 1.11 0.16 <br /> '1. ft+ S ' ft+l, I ft.. t . . 30 5.23 1.55 0.23 ' <br /> Total head: 1 ye t 35 6.96 2.06 0.30 <br /> • 40 8.91 2.64 0.39 <br /> ;. Pump selection 45 . 11.07 328 0.48 <br /> . • 50 13.46 3.99 0,58 <br /> 0 <br /> A pump must be selected to delver at least . 4 3• •gpm 0. <br /> 60' 55 2 <br /> 0 5.6600 5 0.82 <br /> (1A or B) with at least 1 4 (feet of total head(2D) • 65 6.48 0.95 <br /> . • <br /> 70 7.44 1.09 <br /> • <br /> I hereby certify that I have completed this work in accordance with applicable ordinal ces, :rules and laws. <br /> 7 i-- (signature) 3'7(4 (license#) I -?•-\ -0 2_ (date) <br />