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PRESSURE DISTRIBUTION SYSTEM tNO reR.oRATION OF " PERFORATED LATERAL <br /> Orn caro <br /> • <br /> 1. Select number of perforated laterals ? s; <br /> • waw send taro • 'tz I. Nei w:wow sfri.'- <br /> . <br /> 2. Select perforation spacing = feet �l <br /> /• •rnm! .�tltl rester Ilan OraW 1Wtreeh. <br /> MN Wer ere <br /> 4..p,',... / �. Al Lams It'N Set <br /> ela iliN :: H OKI LAW3. Since perforations'should not be placed closer, than 1 ft. to , " <br /> Peeletelle~LAMM n <br /> the edge of the rock layer (See diagram), subtract 2 ft. from Clem send Lever sella.•, L.Ier.l <br /> the rock layer length. 44 <br /> j 4 Orlrbel 3e11 Prgerty Sat/41W <br /> ...a,1._. .. <br /> I Solas Pleclnr Send Lew <br /> Rock layer length. 2 ft. = 7ei feet <br /> TABLE OF PERFORATION DISCHARGES IN GPI <br /> 4. Determine the number of spaces between perforations. Head Perforation diameter(inched) <br /> Divide the length above by perforation spacing and round <br /> down to nearest whole number. v= t/• <br /> ~ <br /> 1.0a 0.56 0.74 <br /> 0. <br /> Length perf. spacing = ?.e, ft. + ft. = I ' spaces hob 0 0 1.°. a <br /> (#3k (#2) 23 0.89 1.17 <br /> 5. Number of perforations is equal to one plus the-number of i 0 0.98 i.� <br /> perforation spaces . 5.0 1.26 1.65 <br /> aUse 1.0 foot of head for residential systems. <br /> /' spaces + 1 = 14 perforations per lateral bUse 2.0 feet of head for other establishments <br /> 6. Multiply perforations per lateral by number of laterals to <br /> get total number of perforations. <br /> Table 2 <br /> x _ = u perforations <br /> Masi us.dowebie number of cheater heck perfentiu.a per <br /> laterals Perls/lateral P lateral to guarantee clSXr Melling*variation <br /> rer'� I+="• 1.25 inch 1.5 inch 2.0 inc <br /> 7. Determine required flow rate by multiplying 2.5 14 18 28 <br /> number of perforations by flow per perforation 3.0 13 17 26 <br /> 3.3 12 16 25 <br /> 4.0 11 15 23 <br /> 2. u 5.0 10 14 22 <br /> > a x /p : 1 gpm. <br /> 8. If laterals are connected to header pipe as shown on upper ....or.o<..r... o MEM Anymbiter,,,•e <br /> example,select minimum required lateral diameter from -4,,. <br /> table 2;enter table with perffration spacing and number <br /> of perforations per lateral. Select minimum diameter for <br /> perforated lateral = inches0.-0°'� �- <br /> 9. If perforated lateral system is attached to manifold pipe near • <br /> the center,as in lower example, perforated lateral length and ""-+• = <br /> number of perforations per lateral will be approximately one cir' <br /> half of that in # 6. Using these values,select minimum a =- -s.r,.- 'w <br /> diameter for perforated lateral from table 2 --yarn.-- . <br /> perforated lateral = / 1/�. II, inches r \ '+'a <br /> ..°'' <br /> ��, -' well... <br />