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2006-P10146 - septic
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Old Crystal Bay Road South
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0085 Old Crystal Bay Road South - 04-117-23-21-0004
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2006-P10146 - septic
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Last modified
8/22/2023 3:11:25 PM
Creation date
3/21/2018 10:54:25 AM
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x Address Old
Address
0085 Old Crystal Bay Rd S
Document Type
Septic
PIN
0411723210004
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ProcessedPID
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• F. ABSORPTION WIDTH Abslorption ratio: 2 <br /> 1. Absorption width equals absorption ratio times rock layer width <br /> 2.00 x 10.0 ft = 20.0 ft <br /> G. MOUND SLOPE WIDTH&LENGTH(Greater that 1%) <br /> 1. Downslope absorption width=absorption width minus rock layer width <br /> 20.0 feet - 10.0 feet= 10.0 ft <br /> 2. Calculate mound size <br /> UPSLOPE <br /> a.Depth of dean sand at upslope edge of rock layer=3 feet minus distance to restricting layer(C1) <br /> 3.0 ft - 1.8 ft= 1.2 ft <br /> b.Mound height at the upslope edge of rock layer=depth of dean sand for separation(G2a) <br /> at upslope edge plus depth of rock layer(1 foot)to depth of cover(1 foot) <br /> 1.2 ft+1ft+1 ft= 3.2 ft <br /> c.Upslope berm multiplier based on land slope(see figure D-34) <br /> Selected berm multiplier. 3.45 <br /> d.Upslope width=berm multiplier(G2c)times upslope mound height(G2b): <br /> 3.45 x 3.2 ft = 11.0 ft <br /> DOWNSLOPE <br /> e.Drop in elevation=rock layer width(D2)times pefcent landslope(C5)/100 <br /> 10.0 ft x 4.0 % /100= 0.4 ft <br /> f.Downslope mound height=depth of clean sand far slope difference(G2e) <br /> at downslope rock edge plus the mound height at the upslope edge of rock layer(2b) <br /> 0.4 ft + 3.2 ft= 3.6 ft <br /> g.Downslope berm multiplier based on percent land slope(see Figure D-34) <br /> Selected berm multiplier ( 4.76 <br /> h.Downslope width=downslope multiplier(G2g)times downslope mound height(G2f) • <br /> 4.76 x 3.6 = 17.0 ft <br /> i.Select greater of G1 and G2h as the downslope width 17.0 ft <br /> j.Total mound width is the sum of upslope(G2d)width plus rock layer width(D2)plus downslope width(G2i) <br /> 11.0 ft+ 10.0 ft+ 17.0 ft= 38.0 ft <br /> k.Total mound length is the sum of upslope width(G2d)plus rock layer length(D3)plus upslope width(G2d) <br /> 11.0 ft + 63.0 ft+ 11.0 ft= 85.0 ft <br /> I Final Dimensions (slope>1%) 38.0 ft x 85.0 ft <br /> I hereby certify that all work has been completed in accordance with all applicable ordinances,rules&laws. <br /> (signature) 810(license#) (AC (date) <br /> Page 2 of 5 <br />
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