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septic info including 2002 design
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Old Crystal Bay Road North
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0405 Old Crystal Bay Road North - 33-118-23-24-0007
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septic info including 2002 design
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Last modified
8/22/2023 4:48:10 PM
Creation date
3/7/2018 1:01:58 PM
Metadata
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Template:
x Address Old
House Number
405
Street Name
Old Crystal Bay
Street Type
Road
Street Direction
North
Address
405 Old Crystal Bay Road North
Document Type
Septic
PIN
3311823240007
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ProcessedPID
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TRENCH AND BED WORK HEFT <br /> 1. AVERAGE DESFLOW A.1; estimated Sewage No"in"Join per Day <br /> A. Estimated IG o gpd(see figure A-1), nuriverall <br /> or measured x 15(94ctor)= gpld bedrooms cla I Clan 11 Glass 1I1 G�N <br /> B. Septic tank capacity So on -� Owons(see figure C-1) 3 450 300 218 of the <br /> u5 LSvo v>,�1� �1�1Av✓�F�4�'Pr SoQI"f'it41a� 4 600 376 286 values <br /> 4 Joao 110091laV <br /> 2. SOILS(Site evaluation data) a 790.0 525 832 In <br /> 1. <br /> C. Depth to restricting layer= a.3 l zed 4* 3.o feet 1 7 1060 600 370 I6 or III <br /> D. Max depth of system Item 2C-3 it= ft-^3 ft ft <br /> 8 1200 675 408 columns. <br /> E. Texture Percolation rate MPI <br /> F. Soil Sizing Factor(SSF) sgft/gpd(see figure D-15) <br /> G. %Land Slope % G1d Se tic Tank Catracilles On eallons) <br /> 3. TRENCH or BED BOTTOM AREA Number of Minimum Uquld Liquid capacity with wi h'd•s'ty <br /> poswH. For trenches with 6 inches of rock below the pipe: Bedrooms amity h��disposal lift i & <br /> A x F=_gpd x sgft/gpd= sgft2 or len 750 1125 1500 <br /> I. For trenches with 12 inches of rock below the pipe: i 3 or 4 1000 15D0 2000 <br /> A x F x 0.8=_gpd x sgft/gpd x 0.8= sgft 7,'a or 9 20M �o3000j. For trenches with 18 inches of rock below the pipe: <br /> A x F x 0.66=_gpd x sgft/gpd x 0.66= sgft D-25: $OA Characteristics and soil sizing <br /> F)(>3' Hon) <br /> K. For trenches with 24 inches of rock below the pipe: Far ctor 2(SSto actor <br /> A x F x 0.6= crop d x sgft/gpd x 0.6= sgft „"'"per via' se°r""'o' <br /> _ `q"d°fZt/ '"°" <br /> L. For gravity beds with 6 or 12 inches of rock below the pipe;e; faster pum 0•1• res.md 043 <br /> P1P cnsalto a Medlutn Sand 0 <br /> .83 <br /> 1.5 x A x F=1.5 x--ter d x sgft/gpd=�_.sgft a,t,,.. � ;^d ,., <br /> For pressure beds with 6 or 12 inches of rock below the pipe; 1b o'o 1 r8iidoan,''°"" 'g <br /> A x F= y o d x-1,o sgft/gpd=—a-0 O sgft' w t town Sao <br /> sndy <br /> 4. 'NSTRIBUTION(Check all that apply) aver 61:o,2o... fi`''r slay 4M <br /> ✓ Bed (<6%slope) Drop boxes(any slope) Rock slower dum mlti�ry <br /> Trenches Distribution box(<31/6) Chamber =ay.c ma or v y wrme <br /> piaswnr disMbudnn or..rlal dat j"dvn with <br /> Pressure Gravity Gravelless no emnch>=%of dr tow.Sum. -,, <br /> "Sell havt cp ti°%m mora fine Sand plus very fine sand 5 C6 . <br /> A mound muSt'be Fwd. <br /> 5. SYSTEM WIDTH,.LENGTH and VOLUME —An other or <br /> perfor"s=e system must be used <br /> M. Select trench width= ft D-9: Soil Characteristics and Soil sizing <br /> N. If using rock,divide bottom area by width: (H,I,JK or$.)+M= factors(SSF)for Gravelless Pipe <br /> --)V o sgft+ ft= lineal feet mir+ut /l+h) sou texture :Zwt Say <br /> Rock depth below disti j ution pipe plus 0.5 foot times bottom area: Faster than 0.1• coarse sand — <br /> Rock depth in f et+A4ret x-Area(H,I,J0.1105 Medium sand 0.28K,or L) � a1 to s =r- a6 <br /> ( /. ft+G )x moo sgft= l 1 D tuft 6t t yy <br /> s°' Loarn 0.4 <br /> Volume in cubic yards=volume in tuft divided by 27 321045 Slit LL toad► 0.67 <br /> sil <br /> l l l t� curt+27=�—cuyds 4e to 60 Say Loam(cl.) 0.74 <br /> Weight of rock in tons=cubic yards times 1.4 e<ower than su�Y. <br /> LL�—cuyds x 1.4= (o a tons Sandy ba — <br /> O. If using 10"Gravelless Pipe, Flow(A)x Gravelless SSF.! a figure D-9) sutyaay <br /> 'Soll too coarse for Sawa treatment. <br /> --oDr d x lineal feet/gpd= lin al feet Use systems for rapidly ps=neable soils. <br /> "Sou ha sox or move Aar send+v flee sand. <br /> P. If using Chambers,H,I,J,or K(based on height of chamb r slats)+ <br /> "'*oil with <br /> width of chamber in feet(M) Installation of a shndard inground system. <br /> sgft+ ft= lineal feet oArnit.F b& <br /> rs.*c~ <br /> 6. LAWN AREA <br /> Q. Select trench spacing,center to center= feet <br /> R. Multiply trench spacing by lineal feet R x Q=sgft of lawn rea <br /> ft x lineal feet=-c)0Q sgft s st r� >t 6-24•Rock t i <br /> 3/4-21/2" 1°1 <br /> 7. LAYOUT <br /> Include a drawing with scale(one inch= --O feet). Show p rtinent property boundaries,rights-of-way,ease- <br /> ments, location of house,garage,driveway,and all other impr vements, existing or proposed soil treatment system, <br /> well and dimensions of all elevations,setbacks and separation istances. <br /> I her ertify that I have completed this work in accordance ith applicable ordinances, rules and laws. <br /> �- (signature) (license#) 0 Z (date <br />
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