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1996-008339 - new septic system
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Old Crystal Bay Road North
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0325 Old Crystal Bay Road North - 33-118-23-31-0003
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1996-008339 - new septic system
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Last modified
8/22/2023 4:49:13 PM
Creation date
3/7/2018 12:36:29 PM
Metadata
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Template:
x Address Old
House Number
325
Street Name
Old Crystal Bay
Street Type
Road
Street Direction
North
Address
325 Old Crystal Bay Road North
Document Type
Septic
PIN
3311823310003
Supplemental fields
ProcessedPID
Updated
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PRESSURE DISTRIBUTION SYSTEM END PERFORATION OF A PERFORATED LATERAL <br /> -crass cov.r <br /> 1. Select number of perforated laterals Topsoil AW <br /> of Geolexille Fabric for foLr,' <br /> Sand Lam krc layer of hOY or strove covvred <br /> with red rosin pow) <br /> 2. Select perforation spacing feet. IK7 <br /> --kCrWrorallon or Lzontally <br /> • into p Now Top <br /> A Least 12"to Ed9* <br /> Dra IIA <br /> 3. Since perforations should not be placed closer than 'I ft. to n Field Rof Rcw*Layer LAI PIUS At <br /> the edge of the rock layer (see diagram),subtract 2 ft. from NO ofl*M Located at <br /> the rock layer length. Bottom of Lateral <br /> Clean Sand Layer <br /> -zorl'ina <br /> I Solt Property Scuttled <br /> .7=72 ft. Before or'I Placing Sand Layer <br /> Rock layer length <br /> 4. Determine the number of spaces between perforations. %jW;2 ry <br /> Fcrforwt�oDischarge <br /> Divide the length above by perforation spacing and round aiv ns par ounute(SpWj <br /> = 31.6rd <br /> down to nearest whole number. (&Vt) <br /> 1.0a 0.56 0.74 <br /> Length perf. spacing = ft.1 3 ft. 7 spaces 2.Ob 0.80 1.04 <br /> (3) (2) a.Use for single family homes <br /> 5. Number of perforations is equal to one plus the number of b.Use for all other applications <br /> perforation spaces . <br /> /I — Maximum number of quirter inch perforations pez <br /> spaces + perforations/lateral lateral to guarmntee<10%discharge variation <br /> Perforation <br /> pactg <br /> 6. Multiply perforations per lateral by number of laterals to S?feet) 1-4 M 2 <br /> get total number of perforations. 2.5 14 18 28 <br /> . 3 /.5- z <br /> lateral s x = /-5— erforations. 3.0 13 17 26 <br /> periviateral —p 3.3 12, 16 25 <br /> 7. Determine required flow rate by multiplying. 4.0 11 15 23 <br /> number of perforations by flow per perforation 5.0 10 14 22 <br /> C/� .7 <br /> — X FOLO LOCATED AT END OF PFMSWK oisTnieurm systEm <br /> ,erfs j;;�/—p—erf 9PM' <br /> —XV <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example,to select minimum required lateral diameter; enter <br /> table with perforation spacing and number of perforations <br /> per lateral. Select minimum diameter for We <br /> perforated lateral = inches. <br /> LATOUT Or KRroftra RPE LATt"LS MR <br /> Mf.SSLQE D.27MWIlm W .W10 <br /> C'=——0 <br /> E- <br /> 9. If perforated lateral system is attached to manifold pipe near WE- K <br /> the center,lower diagram,perforated lateral length and <br /> number of perforations per lateral will be approximately one <br /> half of that in step 8. Using these values,select minimum <br /> diameter for perforated lateral = ZY'/ inches. <br /> 65 <br />
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