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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Pow in Gallon p7(gppd)Estimated _ � gpd Numberor measured x 1.5 = gpd. aed°oforw ►Ype 1 Type II Type 2 300 225 180 <br /> 218 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 � 375 256 Q. <br /> - ga110nS 6 900 525 35 750 450 32 .�. <br /> 7 1050 600 370 m,m, <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) Numbs .'"' <br /> 1. Depth to restricting layer= inches of <br /> Bemoan: CM-MY � <br /> 2. Depth of percolation tests = a inches `PLW-4 <br /> 3. Percolation rate m P i 2 3 o<a l,0a leu 0o0 1.lu <br /> 1.500 <br /> 4. Land slope % 7 or 8 2.000 3 i� <br /> ova 9 See 68.C•6 (a 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area f rock <br /> layer:A x 0.83 X O0 <br /> gpd x D&sq. ft./gpd = 425_4sq. ft. <br /> 2. Select width of rock layer(10 feet_or_less)_= / ft. <br /> 3. Length of rock layer = area_width= Rock Bed <br /> ft. _ ft. <br /> r•r•r•r r•r��• ti•ti•ti•�•� <br /> ;�•r r•r•r•r•r•r•r• <br /> ti•ti•ti.ti ti.ti ti•ti•ti.ti.ti.ti.ti•ti.ti <br /> r•r.r.r•r.r:r:r•r r•r.r•r•r•r•r• <br /> tdth SIO ft <br /> r•r•r•r•r•r•r•r•r r•r•r•r•r•rY• <br /> ti�ti.ti•yti•ti•ti•ti•ti•�•tiK•Y.ti•ti•tiH <br /> ••r•r•r•t•r•r•r•r r•r•r•r•r•r•r• <br /> E. ROCK VOLUME ' • Length <br /> 1. Multiply rock area by rock depth to get cubic feet f rock; <br /> >'SGaq. ft. x ft. _ Vcu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yard ; <br /> -/, S3)cu. ft. ?-27=_Z�u. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock i tons; <br /> yd. x 1.4 ton/cu. yd. =a3.3 tons. <br /> F. ADSORPTION WIDTH Absorption Width S'min table <br /> 1. Percolation rate in to 12 inches of soil is m 1 Cd • Rt d <br /> P p' ren:olaNen Rate <br /> Minut m per inch Soil'Texture ate a <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 120 1.00 <br /> Vie- gpd/ftz 0.1 to Sand iso 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 152 <br /> 3. Calculate adsorption width ratio b dividing rock layer 16 to 30 Loam 0.60, 2.00 <br /> y g31 to 45 Silt Loam 050 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading ra e; 46 to 60 Cla Loam 0.45 2.67 <br /> 1.20 d/ftz . d/ftp = 61 t0120 flay 0.24 5.00 <br /> gP gp _• Slower than 120 Clay <br /> -Sod having 5096 or move of fine or very fin sand. <br /> 4. Multiply adsorption width ratio by rock layer width to et <br /> required adsorption width; <br /> X /O ft=o?0 ft <br /> 71 <br />