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1992-004740 - septic system
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Old Crystal Bay Road North
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0245 Old Crystal Bay Road North - 33-118-23-31-0012
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1992-004740 - septic system
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Last modified
8/22/2023 4:49:21 PM
Creation date
3/7/2018 10:41:34 AM
Metadata
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Template:
x Address Old
House Number
245
Street Name
Old Crystal Bay
Street Type
Road
Street Direction
North
Address
245 Old Crystal Bay Road North
Document Type
Septic
PIN
3311823310012
Supplemental fields
ProcessedPID
Updated
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PUMP SELECTION PROCEDURE <br /> A. Determine pump capacity: _ <br /> Gravity DistributionENO PERFORATION OF A PERFORATED LATERAL <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahc:+d of -orau Cow <br /> water use rate <br /> 2. Maximum•suggested for de'livery'to a drop box of home system is 2,700 - --= <br /> ' foyer of tieeuu(te leak ter ia..:, <br /> gallons per hour(45 gpm)to prevent build-up of ressure in drop box. Leom,field layer <br /> Wile rrd ro.ie Peva) <br /> ' , er aql a '• rwlorel,e°dtlled Hdn,M+►etii <br /> Pressure Distribution .e "�°r �P r <br /> 3. a. Select number of• rforated laterals 3 '�• • "' l'°'' I A*Ease <br /> Qreln F191 Rode of nxt,lyer <br /> b. Select perforation spacing ft. P.ri.r°iia„tyce►.e et" <br /> c. Subtract 2 ft.from the rock layer length. Cleve soee Benau or leferol <br /> a 2 f t.a '�''�,f t <br /> ` - WoNal Sell Properly Scarified <br /> Before Ploc"Serd lever { l <br /> d. Determine the number of spaces between perforat ons. <br /> Length rt.spacing e= ft.+ ft.= aces <br /> g g -�'3- �- �- p TAi3LE Or mitrORATION DISC]IARCrs 1H CPM <br /> e. _M'spaces+.1 = 1-e perforations/lateral <br /> f. Multiply perforations per lateral by number of laterals to Head Perforation diameter(inches) <br /> get total nun)bcr of perforations. r t/e <br /> er. x ' R,I= perforations. <br /> 1.03 0.56 0.74 <br /> 90 <br /> g• Spar. x e _ 4 0 gpm. 1-5 0.69 <br /> o 80 1 .04 <br /> 25 0.89 1.17 <br /> SELECTED PUMP CAPACITY 4m 3.0 0.98 1.A <br /> ---Q-gyp 4.0 1.13 1.47 <br /> 5.0 1.26 1.65 <br /> B.Determine head requirements: aUse 1.0 foot of head for residential systems <br /> 1. Elevation difference between pump and point of discharge. bUse 2.0 feet of head for other establishments <br /> ) I feet <br /> 2. If pumping to a pressure distribution system,add five feet for pressure <br /> required at manifold <br /> .5" feet <br /> 3. Friction loss PiMl cngth <br /> a. Enter friction loss table with gpm and pipe diameter. Point or Discharge <br /> Read friction loss in feet per 100 feet from table. <br /> F.L= ft./100 ft of pipe ;"Fife- Elevation Difference <br /> b. Determine total pipe length from pump to discharge EIPUMIP d <br /> point. Add 25 percent to pipe length for fitting <br /> loss,or use a fitting loss chart. Equivalent pipe F-18b <br /> length-1.25 times pipe length= 1.5 inch 2.0 inch 3.0 inch <br /> .(/6 -x 1:25= feet gTym Friction tan Pa 100 n of pipe <br /> c. Calculate total friction loss by multiplying 10 0.69 0.20 <br /> friction loss in ft/100 ft by equivalent pipe length. 12 0.96 0.28 <br /> Total friction loss= &'-S_x �.U +100 D. ,feet 14 1.28 0.38 <br /> 4. Total head required is the sum of elevation differc ice, 16 1.63 0.48 <br /> special head requirements,and total friction loss. 20 2.47 0.73 0.11 <br /> 25 3.73 1.11 0.16 7. <br /> I. + S •+ 30 5.23 1.55 '. 023 <br /> (1) (21 (3c) 35 7.90 2.06 0.30. <br /> 40 11.07 2.64. . 0.39 <br /> 45 14.73 3.28 0:48 <br /> TOTAL HEAD I feet 50 3.99 0.58 <br /> S5 4.76 0.70. <br /> r <br /> 60 5.60 0.82 <br /> C. Pump selection <br /> i. A pump must be selected to deliver at least gpm (Step A) <br /> with at least feet of total head (Step B). ,{ <br />
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