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1993-005779 - new septic system
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1993-005779 - new septic system
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Last modified
8/22/2023 4:14:51 PM
Creation date
2/12/2018 2:07:46 PM
Metadata
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Template:
x Address Old
House Number
521
Street Name
North Stream
Street Type
Road
Address
521 North Stream Road
Document Type
Septic
PIN
2511823340007
Supplemental fields
ProcessedPID
Updated
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V.400V-P lwc�o <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated SewneFlows in cauadspa day <br /> Estimated 1,,0D - gpd(seepages D-7 or I-3,4,5) (Wo <br /> or measured - gpd x 1.5 = Be&drooms IV'�'pe' 'gyp`" '�i11 1y <br /> 2 300 725 180 <br /> 3 Oso 300 2la <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> 4 600 375 2% Values <br /> gallons (see pages C-3 or C-5) 5 9 0 4450 294 <br /> 4 in <br /> 7 1050 600 370 m <br /> 9 1200 675 408 wlumnn <br /> C. SOILS(refer to site evaluation) „ <br /> i Septic Tank Capacities,in gallons <br /> 1. Depth to restricting layer= ��+' :To -i �' inches <br /> !� Numherof Minimum Liquid Liquid capacity with <br /> 2. Depth of percolation tests = 1�. inches Bedrooms capacity garbage disposal <br /> 3. Percolation rate 11 . 1 mpi 2 or Itss 3or4 730 170 <br /> sera toxo tsoo <br /> 4. Land slope a % 7 9 or 9 '2ooS00o 3W0 <br /> D. ROCK LAYER DIMENSIONS <br /> L . Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:Daily Flow x 0.83 = <br /> gpd x 0.83 sq. ft./gpd = 'i�sq. ft.-�-)t�,:)j= S -1• , <br /> 2. Select width of rock layer(10 feet or less) _ ' ft. <br /> 3. Length of rock layer=Area=Width = <br /> sq. ft. _10 ft. = ft. Rock Bed <br /> r•r•r•r•r•r•r•r��r•r <br /> ti ti ti ti•ti•ti•ti•ti•ti•ti•ti•ti•ti• <br /> f:r:f•f•f•r•r•r r•r•r•r•r•r•r <br /> ti•ti•ti•ti•ti•ti•ti•ti•:•ti•ti•ti•ti•ti•�• dth 2.10ft. <br /> • r•r•r•r•r•r•r•r r.r•r•r•r•r,r <br /> E. ROCK VOLUME •rte-- Length•r•r•r•r•r•r <br /> 1. Multiply rock area by rock depth to get cubic feet of rock, <br /> ,�sq.ft.x L ft. = cu. ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 511-cu.ft +27= a I cu.yd. <br /> 3. - Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> Q I cu.yd.x 1.4 ton/cu.yd. =. L tons.. <br /> F. ADSORPTION WIDTH ZAAL' Lo O <br /> 1. Percolation rate in top 12 inches of soil is 11,I mpi Absorption Width 111M Table <br /> 2. Select allowable soil loading rate from table on page E-- soil Tumm �Por nr w�° t <br /> � gpd/ftz rneu c�Pi root a leek rya <br /> wilun <br /> 3. Calculate adsorption width ratio by dividing rock layer ftaff d=0.1• Comm Smod -- <br /> 0.1 to 5 * sand 1.20 1.00 <br /> loadingrate of 1.20 d/fe b allowable soil loadingrate; o f to s Fme sand- 0.60 zoo <br /> dt". Y 6 to is _ Sandy loam 0.79 1.52 <br /> 1.20 gpd/ft2 :1-1 gpd/ft' a G t 1 16to30 loam o.6o zoo <br /> 31 to 45 Silt loam 0.50 2.40 <br /> Check this value on page E-16. 4 �D l�tn o a 2-677 <br /> SM <br /> 4. Multiply adsorption width ratio by rock layer width to get .- c - <br /> required adsorption width; <br /> �X ft= '.2ft <br />
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