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PRESSURE DISTRIBUTION SYSTEM <br /> !;;rest.xoiM 9a1>cr� <br /> i :w+liAY•<4%iiwi2oE:i}j::;�2Yit:i`i#Yd.Sriii:.222c::Y:Mii;2Yt;%%5�•• <br /> ......... ...:.......... ....:..:::.:....::.:::.:......: ... <br /> All boxed rectangles must be entered,the rest wfll be calculated. <br /> SMaR':'vsff 3/Y9'- W., <br /> 1. Select number of perforated laterals: 0 <br /> 2. Select perforation spacing= 2.5 `{ ft <br /> tar c9�sr�tiatxsnss u�111X cSaclxarsra ecu------ E <br /> 3. Since perforations should not be placed closer that 1 foot to <br /> the edge of the rock layer(see diagram),subtract 2 feet from j . <br /> the rock layer lengthE <br /> as 8 14 1 f <br /> i8 a8 <br /> 75 -2.5 ft= 72.5- ft a;3 i a 13 `•. 17 s% i <br /> rock layer length a } is 16 2 <br /> 5 7 i'r ° is ab <br /> df 1 10 E 14 22 ° <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spacing= 72.5 ft/ 2.5 ft= 29 spaces <br /> 5. Number of perforations is equal to oneplus the nutnlbe' 9'0'6rfor`ation spaces(4). <br /> *Check figure E-4 to assure the number of perforations:per lateral guarantees <br /> < 90016 discharge variation. <br /> 29 spaces+1 = 30 perforations/lateral <br /> 6. A.Total number of,perforatio&=perforationsperlateral(5)times number of laterals(1). <br /> 30 perfs/lat x 3 laterals.-- 90 perforations <br /> t <br /> 1;8s: Ism€4Y1+l tyil Q$t is kal RWWA <br /> B.Calculate the square footage per perforation. - <br /> Should be 6-10 erf.Does not to at 'rades. �1't�r�-11114 tfiexrrs l r <br /> �P PPN -9 � rir�yl'��" <br /> 1. Rock bed area=rock width,(ft)x rock length(ft) (f�st� ;/8 3;yg 7/ 2 11,4 <br /> 10 ft x 75 ft= 750 ft2 1,£0 € IS 0,42 0;156 0.74 <br /> 2. Square foot per perforation=Rock Bed Area/number of perfs(6) <br /> 750.0 fl? / 90 perfs = 8.3 ftz/pert 8.3 b 0.26 0' } <br /> It ;r_ 25,0'_ x3,41 €3;9 126 t W <br /> 7. Determine required flow rate by multiplying the total number Ya 1:RT:::r<w:.:a. aYs; �.�:r•�P;::r: <br /> of perforations(6A)by flow per erfora9 (see figure FA s*s1 r:�.: ° <<.a.,:�,f:•,f sf , Nom:. <br /> 90 perfs x 0.74 gpm/perfs=° 66.6 gpm <br /> 8. If laterals are connected to header pipe as shown .................................... <br /> in Figure E-1,to select minimum required lateral <br /> diameter;enter figure E-4 with perforation spacing(2)and <br /> number of perforations per lateral(5). : `"n• �. <br /> t. F�9Y>9!;`is AStxtt45Ly Ltaoa�.+B M 1;:td CT Sy«lt9rr5 <br /> Select minimum diameter for berforated laterals.= inches <br /> 9. If perforated laterals em is attached to manifold pipe ..................-.................................................................................. <br /> near the center,like Figure E-R,perforated lateral length(3) <br /> and number of perforations per lateral(5)will be appro3dmately <br /> one half of that in step 8. Using-these values select :.�ti <br /> e•..:,y:.... •. <br /> minimum diameter for perforated lateral 1 5 inches. �:."•' "" <br /> I hereb certify that I have completed this work in accordance,with all applicable ordinances,rules and laws. <br /> (signature) 3 3q (license#) (date) <br />