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University of Minnesota Pressure Dit>tribution System Design-10125104 <br /> ,a b"d ffldwOft Mwfbe e„re,ee,Me Md vAl e+Warrafod Ahk <br /> s <br /> 1. select numberofperforated laterals: [' <br /> �� <br /> roman <br /> 2. Select perforation spacing <br /> caa-a,da 4M.a- <br /> 3. Since pertoretbns should not be placed loser that 1 foot to <br /> the edge of the rock layer(see diagram),subtract 2 W from <br /> the rock lager IaMth- <br /> 4. Determine the number of spaces beixveen perforations. <br /> Divide the length(3)by perforation gacbeg(2)and round down tonewel who*number. <br /> Perforation spacing= 36 ft/ 3 R- 12 <br /> 5. Select perforation she ®inch <br /> a Number of perforations Is equal to One pkis the munber of perforation spaces(4). <br /> 'O ack%wre E-4 to assure Hoe numberc(perfamdansper kdeh f guarent yes <br /> <10%dfsd Wage Yvon. <br /> 12 spaces+1= 13 perfarallonw1aterai <br /> -4 1101aximum Nwober of W Irtch pertoratfons E-5 Mandnsua hhaabar of 3f16 Inch perforations <br /> r lateral to guarantee<10'%dWchwg#variation Per lateral to suarantes<18%discharge varlatforh <br /> Pertaratbn Perforation <br /> Spacing Ripe Duunater Spaclm Pipe Diemeler <br /> ft 1 Inch 1.25 Inch 1.5 Inch 7-0 Inch led 1 huh 1.25 inch 1.5 inch 2.0 inch <br /> 2 8 14 18 2 is 25 39 <br /> 3.0 ti 13 17 26 311. 18 24'. 3� <br /> 3.3 7 12 16 25 3.3 10 17 23 36 <br /> 4.0 7 .11- 15. 23 .4: 10 16 21 33 <br /> 5.0 6 10 14 22 1 1 5 9 15 20 31 <br /> 7. A.Total n umberof perforations=perforations per lateral(5)Wates number of laterals(1). <br /> 13 perwiatx 3 laterals= 39 pmfotations <br /> B.Calculate the square footage per perforailm <br /> Reoornmended value is 5-10 agWperf.Does not applyto at-glades. <br /> 1. Rodc bed area-rook width(ft)x rock length(ft) <br /> 10 R x 36 ft- 380 ftz <br /> 2 per'peAcm-h-w Bed Ama-h-n-W- penN(8) <br /> 380.0 10 I 39 peril - 9.7 fel pert <br /> S. Determine required flash rate by multiplying the tatal number <br /> of perforations(EIN by flow per perf raYarat see fiawe E-6) <br /> 39 1 ports x 1 0.74 gpm I peril.= 26.9 gpm <br /> E-6 Perforation 59aarne In GPM <br /> Head Perforations diameter <br /> feel rhes <br /> 3118 1 7132 1 114 <br /> 1 0.42 .74 <br /> 20 0.69 0.80. 1.04. <br /> 5 0.94 1.28 1.65 <br /> a um 1.o A%A(Orsbrpie(ter*1wn es. <br /> b.Use 2.0 feel for wymy else <br /> 9. Determine Minimum Pipe Sias <br /> A Manifold on Ead. if laterals are connected to header pipe <br /> i <br /> as shown in Figure E-1,to select mkdmum required lateral <br /> diameter,enter figure E-4 or E6 with perforation spacing and <br /> number of perforations per lateral.Select um diameter <br /> for perforated laterals- 1. Inches <br /> B. Center Manifold. Uperkrated lateral system is attached to �••��•* .� <br /> manifold pipe near the center,Blue Figure E-2,perforated lateral length(3) <br /> and number of perforations per lateral(5)Will be approximately <br /> one half of that in step A. Using these values select <br /> minimum diameWfor perforated lateral= 1.5 Inches <br /> I he that in a anoe with all apppCaft ordinances,rules a . <br /> _(signature) $10 picensetz) t15A0 8(daft) <br /> G'd OL',9 EMP 2S6 spooA asjTgnr e1to :BO BO IZ Few <br />