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t-19 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW � D-7 <br /> Estimated gpd (see pages D-7 or 1-3,4,5) Mn"T®Sr""FLO"IA rJUaNa Pa Dm' <br /> NMMEA TTP!or Nl7,DN" <br /> or measured gpd. BED10OM I Ta g <br /> 2 No 723 ,60 60% <br /> 3 030 No 2,e °T <br /> s am 3n 736 'O p^ <br /> on B. SEPTIC TANK LIQUID VOLUMES a � � '' ` <br /> 1100 370 <br /> 1e 00V gallons (see pages C-3 or C-5) T 120 on <br /> I312M +w cowMiw„ <br /> C-3 <br /> C. SOILS (refer to site evaluation) SEPTIC TANK CAPACITIES, IN GALLONS <br /> Lia.uN6•.0� <br /> cr1111141. Depth to restricting layer = 9®- 6Zz inches smoru6w cuaa,� 6 <br /> mvosu <br /> 2. Depth of percolation tests = 1� inches ,o"uu Too T,36 <br /> E.i <br /> 3. Percolation rate , Z— mpi 6OR4 logo 1540 <br /> 3 On 6 logo 3790 <br /> 4. Land slope % Y.6.00 6 3000 3600 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> lv©� gpd x 0.83 sq. ft./gpd sq. ft. <br /> 2. Select width of rock layer(10 feet or less) = /0 ft. <br /> 3. Length of rock layer= area+width= <br /> ,-C-cV-0 sq. ft. ft. =' -CZ7 ft. <br /> Rock Bed <br /> •j•r•r•r•r•r•r•r r•r•r•r•r•r•r <br /> ti•ti•�•ti•ti•ti•ti•ti•ti•�•ti•ti•ti•ti•ti• I <br /> . . . .... . . . .rrrrrr <br /> ti.ti.ti.ti.ti.ti•ti.�. •ti•ti•ti.ti•ti.ti• 3dth 510 <br /> r•r•r•r•r•r•r•r r•r.r•r•r•r•r <br /> 'LM,•ti•1,•4•ti•ti•ti•ti•U•b S•S•S•�• <br /> •j•j•r•j•rM•j•j•j•j•j•r•r•r•r <br /> E. ROCK VOLUME L th <br /> 1. MultipVock area by rock depth to get cubic feet of rock; <br /> . ® sq. ft. x f ft. _ 'cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu.yd. to get cubic yards; <br /> `90 cu. ft. t 27= /,9 cu. yd. <br /> 3. Multi ly cubic yards by 1.4 to get weight of rock in tons; <br /> cu. yd. x 1.4 ton/cu. yd. --.----"';—tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is-57 Z mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; ""M&Lamm"MO..g1.3UXON MUNCS <br /> �-� gpd/ft2 ;. . .,..�. �. <br /> N• ti•M O.W r•n <br /> 3. Calculate adsorption width ratio by dividing rock layer �"• "�"� `�" "" •' `"° "" <br /> 33,33 ,.3e 9300 9370 ,.ee <br /> loading rate of 1.20 gpe�/ft2 by allowable soil l a Ing rate; ,6 .3o 9 <br /> e.. <br /> 1.20 gpd/ft2,- iY,gpd/ft2= �o� „ g.a 0390 3.03 <br /> u •6e 0..6 6.73 7.63 3.9T <br /> u •T9e o.,, 0.36 6.0 ,.eo <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> Z-0 x/Cft = ft <br />